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ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#168854 | #6560. Broken Minimum Spanning Tree | ucup-team134# | WA | 1ms | 3824kb | C++14 | 5.2kb | 2023-09-09 00:04:33 | 2023-09-09 00:04:33 |
Judging History
answer
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/rope>
#define ll long long
#define pb push_back
#define f first
#define s second
#define sz(x) (int)(x).size()
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define ios ios_base::sync_with_stdio(false);cin.tie(NULL)
#define ld long double
#define li __int128
using namespace std;
using namespace __gnu_pbds;
using namespace __gnu_cxx;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
template<class T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>; ///find_by_order(),order_of_key()
template<int D, typename T>struct vec : public vector<vec<D - 1, T>> {template<typename... Args>vec(int n = 0, Args... args) : vector<vec<D - 1, T>>(n, vec<D - 1, T>(args...)) {}};
template<typename T>struct vec<1, T> : public vector<T> {vec(int n = 0, T val = T()) : vector<T>(n, val) {}};
template<class T1,class T2> ostream& operator<<(ostream& os, const pair<T1,T2>& a) { os << '{' << a.f << ", " << a.s << '}'; return os; }
template<class T> ostream& operator<<(ostream& os, const vector<T>& a){os << '{';for(int i=0;i<sz(a);i++){if(i>0&&i<sz(a))os << ", ";os << a[i];}os<<'}';return os;}
template<class T> ostream& operator<<(ostream& os, const deque<T>& a){os << '{';for(int i=0;i<sz(a);i++){if(i>0&&i<sz(a))os << ", ";os << a[i];}os<<'}';return os;}
template<class T> ostream& operator<<(ostream& os, const set<T>& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T> ostream& operator<<(ostream& os, const set<T,greater<T> >& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T> ostream& operator<<(ostream& os, const multiset<T>& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T> ostream& operator<<(ostream& os, const multiset<T,greater<T> >& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T1,class T2> ostream& operator<<(ostream& os, const map<T1,T2>& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
int ri(){int x;scanf("%i",&x);return x;}
void rd(int&x){scanf("%i",&x);}
void rd(long long&x){scanf("%lld",&x);}
void rd(double&x){scanf("%lf",&x);}
void rd(long double&x){scanf("%Lf",&x);}
void rd(string&x){cin>>x;}
void rd(char*x){scanf("%s",x);}
template<typename T1,typename T2>void rd(pair<T1,T2>&x){rd(x.first);rd(x.second);}
template<typename T>void rd(vector<T>&x){for(T&p:x)rd(p);}
template<typename C,typename...T>void rd(C&a,T&...args){rd(a);rd(args...);}
//istream& operator>>(istream& is,__int128& a){string s;is>>s;a=0;int i=0;bool neg=false;if(s[0]=='-')neg=true,i++;for(;i<s.size();i++)a=a*10+s[i]-'0';if(neg)a*=-1;return is;}
//ostream& operator<<(ostream& os,__int128 a){bool neg=false;if(a<0)neg=true,a*=-1;ll high=(a/(__int128)1e18);ll low=(a-(__int128)1e18*high);string res;if(neg)res+='-';if(high>0){res+=to_string(high);string temp=to_string(low);res+=string(18-temp.size(),'0');res+=temp;}else res+=to_string(low);os<<res;return os;}
const int N=2005,M=3005;
vector<pair<pair<int,int>,pair<int,int>>> edges;
vector<int> inside(M);
vector<int> par(N);
int find(int tr){return par[tr]==tr?tr:par[tr]=find(par[tr]);}
bool merge(int a,int b){
a=find(a);
b=find(b);
if(a==b){
return 0;
}
par[a]=b;
return 1;
}
void resetDsu(){
iota(all(par),0);
}
vector<set<int>> graf(N);
vector<int> rc;
vector<bool> visited(N);
void dfs(int tr){
visited[tr]=1;
rc.pb(tr);
for(auto p:graf[tr]){
if(!visited[p]){
dfs(p);
}
}
}
int main()
{
int n=ri(),m=ri();
for(int i=0;i<m;i++){
int u=ri()-1,v=ri()-1,w=ri();
edges.pb({{w,i},{u,v}});
}
sort(all(edges));
resetDsu();
for(int i=0;i<m;i++){
if(merge(edges[i].s.f,edges[i].s.s)){
inside[i]=1;
}
else{
inside[i]=0;
}
}
resetDsu();
vector<pair<int,pair<int,int>>> outside;
vector<bool> takenOut;
vector<pair<int,pair<int,int>>> toReplace;
for(int i=0;i<m;i++){
if(inside[i]){
if(edges[i].f.s>=n-1){
outside.pb({edges[i].f.s,{edges[i].s}});
takenOut.pb(0);
}
else{
graf[edges[i].s.f].insert(edges[i].s.s);
graf[edges[i].s.s].insert(edges[i].s.f);
}
}
else{
if(edges[i].f.s<n-1){
toReplace.pb({edges[i].f.s,{edges[i].s}});
graf[edges[i].s.f].insert(edges[i].s.s);
graf[edges[i].s.s].insert(edges[i].s.f);
}
}
}
printf("%i\n",sz(toReplace));
for(auto p:toReplace){
int i=p.f;
graf[p.s.f].erase(p.s.s);
graf[p.s.s].erase(p.s.f);
dfs(p.s.s);
bool found=0;
for(int i=0;i<sz(outside);i++){
if(takenOut[i]){
continue;
}
if(((int)visited[outside[i].s.f]^(int)visited[outside[i].s.s])==1){
found=1;
takenOut[i]=1;
graf[outside[i].s.f].insert(outside[i].s.s);
graf[outside[i].s.s].insert(outside[i].s.f);
printf("%i %i\n",i+1,outside[i].f+1);
break;
}
}
assert(found);
for(auto p:rc){
visited[p]=0;
}
rc.clear();
}
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 1ms
memory: 3824kb
input:
4 4 1 2 10 2 3 3 3 4 1 1 4 4
output:
1 1 4
result:
ok correct!
Test #2:
score: -100
Wrong Answer
time: 1ms
memory: 3800kb
input:
6 8 1 2 10 2 3 10 3 4 10 4 5 10 5 6 10 6 1 10 1 3 1 4 6 1
output:
2 1 7 2 8
result:
wrong answer not a spanning tree after swap 2