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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#168824 | #6563. Four Square | ucup-team134# | WA | 1ms | 3996kb | C++14 | 5.1kb | 2023-09-08 23:10:00 | 2023-09-08 23:10:00 |
Judging History
answer
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/rope>
#define ll long long
#define pb push_back
#define f first
#define s second
#define sz(x) (int)(x).size()
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define ios ios_base::sync_with_stdio(false);cin.tie(NULL)
#define ld long double
#define li __int128
using namespace std;
using namespace __gnu_pbds;
using namespace __gnu_cxx;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
template<class T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>; ///find_by_order(),order_of_key()
template<int D, typename T>struct vec : public vector<vec<D - 1, T>> {template<typename... Args>vec(int n = 0, Args... args) : vector<vec<D - 1, T>>(n, vec<D - 1, T>(args...)) {}};
template<typename T>struct vec<1, T> : public vector<T> {vec(int n = 0, T val = T()) : vector<T>(n, val) {}};
template<class T1,class T2> ostream& operator<<(ostream& os, const pair<T1,T2>& a) { os << '{' << a.f << ", " << a.s << '}'; return os; }
template<class T> ostream& operator<<(ostream& os, const vector<T>& a){os << '{';for(int i=0;i<sz(a);i++){if(i>0&&i<sz(a))os << ", ";os << a[i];}os<<'}';return os;}
template<class T> ostream& operator<<(ostream& os, const deque<T>& a){os << '{';for(int i=0;i<sz(a);i++){if(i>0&&i<sz(a))os << ", ";os << a[i];}os<<'}';return os;}
template<class T> ostream& operator<<(ostream& os, const set<T>& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T> ostream& operator<<(ostream& os, const set<T,greater<T> >& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T> ostream& operator<<(ostream& os, const multiset<T>& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T> ostream& operator<<(ostream& os, const multiset<T,greater<T> >& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T1,class T2> ostream& operator<<(ostream& os, const map<T1,T2>& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
int ri(){int x;scanf("%i",&x);return x;}
void rd(int&x){scanf("%i",&x);}
void rd(long long&x){scanf("%lld",&x);}
void rd(double&x){scanf("%lf",&x);}
void rd(long double&x){scanf("%Lf",&x);}
void rd(string&x){cin>>x;}
void rd(char*x){scanf("%s",x);}
template<typename T1,typename T2>void rd(pair<T1,T2>&x){rd(x.first);rd(x.second);}
template<typename T>void rd(vector<T>&x){for(T&p:x)rd(p);}
template<typename C,typename...T>void rd(C&a,T&...args){rd(a);rd(args...);}
//istream& operator>>(istream& is,__int128& a){string s;is>>s;a=0;int i=0;bool neg=false;if(s[0]=='-')neg=true,i++;for(;i<s.size();i++)a=a*10+s[i]-'0';if(neg)a*=-1;return is;}
//ostream& operator<<(ostream& os,__int128 a){bool neg=false;if(a<0)neg=true,a*=-1;ll high=(a/(__int128)1e18);ll low=(a-(__int128)1e18*high);string res;if(neg)res+='-';if(high>0){res+=to_string(high);string temp=to_string(low);res+=string(18-temp.size(),'0');res+=temp;}else res+=to_string(low);os<<res;return os;}
const int N=4;
vector<pair<int,int>> pc(N);
vector<pair<int,int>> place(N);
vector<bool> rot(N),in(N);
int n;
bool intersects(pair<int,int> a,pair<int,int> b){
if(a.f>b.s||a.s<b.f){
return 0;
}
}
bool intersects(int i,int j){
if(!in[i]||!in[j]||i==j)
return 0;
vector<pair<int,int>> x,y;
if(rot[i]){
x.pb({place[i].f,place[i].f+pc[i].f-1});
y.pb({place[i].s,place[i].s+pc[i].s-1});
}
else{
x.pb({place[i].f,place[i].f+pc[i].s-1});
y.pb({place[i].s,place[i].s+pc[i].f-1});
}
if(rot[j]){
x.pb({place[j].f,place[j].f+pc[j].f-1});
y.pb({place[j].s,place[j].s+pc[j].s-1});
}
else{
x.pb({place[j].f,place[j].f+pc[j].s-1});
y.pb({place[j].s,place[j].s+pc[j].f-1});
}
return intersects(x[0],x[1])&&intersects(y[0],y[1]);
}
int getLast(int i,int row){
if(!in[i])
return -1;
if(row<place[i].f||row>place[i].f+(rot[i]?pc[i].f:pc[i].s)-1)
return -1;
return place[i].s+(rot[i]?pc[i].s:pc[i].f)-1;
}
bool canPlace(int i,int r,int c,int ro){
if(r+(ro?pc[i].f:pc[i].s)-1>=n||c+(ro?pc[i].s:pc[i].f)-1>=n){
return 0;
}
for(int j=0;j<N;j++){
if(intersects(i,j)){
return 0;
}
}
return 1;
}
bool dfs(){
int r=-1,c=-1;
for(int row=0;row<n;row++){
int mx=-1;
for(int j=0;j<N;j++){
mx=max(mx,getLast(j,row));
}
if(mx!=n-1){
r=row;
c=mx+1;
break;
}
}
if(r==-1){
return 1;
}
for(int j=0;j<N;j++){
if(in[j]){
continue;
}
for(int ro=0;ro<2;ro++){
if(canPlace(j,r,c,ro)){
place[j]={r,c};
rot[j]=ro;
in[j]=1;
if(dfs()){
return 1;
}
in[j]=0;
}
}
}
return 0;
}
int main()
{
rd(pc);
for(auto p:pc){
n+=p.f*p.s;
}
int sq=-1;
for(int i=1;i<10000;i++){
if(i*i==n){
sq=i;
}
}
if(sq==-1){
printf("0\n");
return 0;
}
n=sq;
printf(dfs()?"1\n":"0\n");
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 1ms
memory: 3752kb
input:
1 1 1 1 1 1 1 1
output:
1
result:
ok single line: '1'
Test #2:
score: 0
Accepted
time: 1ms
memory: 3812kb
input:
3 1 3 3 2 2 3 3
output:
0
result:
ok single line: '0'
Test #3:
score: 0
Accepted
time: 1ms
memory: 3772kb
input:
2 8 2 8 2 8 2 8
output:
1
result:
ok single line: '1'
Test #4:
score: 0
Accepted
time: 1ms
memory: 3768kb
input:
5 3 5 5 3 3 3 5
output:
1
result:
ok single line: '1'
Test #5:
score: 0
Accepted
time: 1ms
memory: 3808kb
input:
1 2 4 8 16 32 64 128
output:
0
result:
ok single line: '0'
Test #6:
score: 0
Accepted
time: 1ms
memory: 3816kb
input:
4 4 2 1 4 4 2 1
output:
0
result:
ok single line: '0'
Test #7:
score: 0
Accepted
time: 1ms
memory: 3996kb
input:
995 51 559 565 154 536 56 780
output:
0
result:
ok single line: '0'
Test #8:
score: 0
Accepted
time: 1ms
memory: 3876kb
input:
391 694 540 42 240 937 691 246
output:
0
result:
ok single line: '0'
Test #9:
score: 0
Accepted
time: 1ms
memory: 3884kb
input:
519 411 782 710 299 45 21 397
output:
0
result:
ok single line: '0'
Test #10:
score: 0
Accepted
time: 1ms
memory: 3808kb
input:
96 960 948 18 108 82 371 576
output:
0
result:
ok single line: '0'
Test #11:
score: -100
Wrong Answer
time: 0ms
memory: 3808kb
input:
3 2 4 3 3 1 1 4
output:
1
result:
wrong answer 1st lines differ - expected: '0', found: '1'