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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#162161#7110. Kuririn MIRACLEucup-team1198#TL 241ms191488kbC++201.9kb2023-09-03 05:23:582023-09-03 05:23:59

Judging History

你现在查看的是最新测评结果

  • [2023-09-03 05:23:59]
  • 评测
  • 测评结果:TL
  • 用时:241ms
  • 内存:191488kb
  • [2023-09-03 05:23:58]
  • 提交

answer

#include <bits/stdc++.h>

#pragma GCC optimize("fast-math")

using namespace std;
#define ll long long
#define pii pair<int, int>
#define ld long double
#define all(a) (a).begin(), (a).end()

const ld pi = atan2l(1, 0) * 2;
const int T = 4000000;

ld pre3sin[T];

ld presin[T];
ld precos[T];


ld get_dphi(int phi, ld u, ld r) {
    return (- u * presin[phi] + sqrtl(u * u * pre3sin[phi])) / (2 * r);
}

ld rush(int phi, ld r, ld v, ld d, ld t) {
    d -= 2 * r + t * v;

    ld x = - 2 * r * precos[phi];
    ld y = 2 * r * presin[phi];

    ld x1 = d - x;
    ld y1 = y;

    ld l = sqrtl(x1 * x1 + y1 * y1);
    ld fac = 2 * v / l;

    x1 *= fac;
    y1 *= fac;

    x1 -= v;

    if (x1 * x > y * y1 - 1e-7) {
        // cerr << l << '\n';
        return l / (2 * v);
    } else {
        return -1;
    }
}

void solve() {
    ld u, r, d;
    
    // u = 2.0;
    // r = 3;
    // d = 30;

    cin >> u >> r >> d;

    ld cur_t = 0;
    for (int i = 0; i < T; ++i) {
        // cur phi = pi * i / T
        
        if (cur_t * u > (d - 2 * r)) {
            break;
        }

        if (i * 2 > T) {
            ld ost = rush(i, r, u, d, cur_t);
            if (ost >= 0) {
                // cerr << 
                cout << min(cur_t + ost, (d - r) / u) << '\n';
                return;
            }    
        }

        ld dphi = get_dphi(i, u, r);  // at further point better
        cur_t += pi / T / dphi;

        // ld phi = pi * i / T;
        // cerr << phi / pi * 180 << '\n';
        // cerr << cur_t << '\n';
    }

    cout << (d - r) / u << '\n';
}

signed main() {
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);


    for (int i = 0; i < T; ++i) {
        presin[i] = sinl(pi * i / T);
        precos[i] = cosl(pi * i / T);
        pre3sin[i] = presin[i] * presin[i] + 3;
    }

    cout << fixed << setprecision(15);

    int t = 1000;
    cin >> t;
    while (t--) solve();


    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 241ms
memory: 191488kb

input:

1
2.00 3 30.0

output:

8.310579782626437

result:

ok found '8.3105798', expected '8.3105799', error '0.0000000'

Test #2:

score: -100
Time Limit Exceeded

input:

100
8.66 6.05 71.59
8.44 8.67 82.55
4.23 9.68 24.74
6.63 9.95 7.45
1.2 7.27 97.55
2.08 2.94 31.61
8.48 5.56 20.16
7.35 5.55 52.48
1.35 8.15 51.23
3.88 9.02 72.37
7.03 1.97 57.03
1.78 4.44 93.44
5.5 6.11 52.94
1.09 9.64 69.01
1.01 3.54 16.78
1.63 4.55 44.06
5.82 5.51 5.92
5.62 2.93 76.01
4.75 4.43 73...

output:


result: