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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#160880 | #7103. Red Black Tree | ucup-team1447# | AC ✓ | 635ms | 46320kb | C++14 | 4.1kb | 2023-09-02 21:41:50 | 2023-09-02 21:41:52 |
Judging History
answer
// what is matter? never mind.
//#pragma GCC optimize("Ofast")
//#pragma GCC optimize("unroll-loops")
//#pragma GCC target("sse,sse2,sse3,sse4,popcnt,abm,mmx,avx,avx2")
#include<bits/stdc++.h>
#define For(i,a,b) for(int i=(a);i<=(b);++i)
#define Rep(i,a,b) for(int i=(a);i>=(b);--i)
#define ll long long
#define int long long
#define ull unsigned long long
using namespace std;
inline int read()
{
char c=getchar();int x=0;bool f=0;
for(;!isdigit(c);c=getchar())f^=!(c^45);
for(;isdigit(c);c=getchar())x=(x<<1)+(x<<3)+(c^48);
if(f)x=-x;return x;
}
#define mod 998244353
struct modint{
int x;
modint(int o=0){x=o;}
modint &operator = (int o){return x=o,*this;}
modint &operator +=(modint o){return x=x+o.x>=mod?x+o.x-mod:x+o.x,*this;}
modint &operator -=(modint o){return x=x-o.x<0?x-o.x+mod:x-o.x,*this;}
modint &operator *=(modint o){return x=1ll*x*o.x%mod,*this;}
modint &operator ^=(int b){
modint a=*this,c=1;
for(;b;b>>=1,a*=a)if(b&1)c*=a;
return x=c.x,*this;
}
modint &operator /=(modint o){return *this *=o^=mod-2;}
friend modint operator +(modint a,modint b){return a+=b;}
friend modint operator -(modint a,modint b){return a-=b;}
friend modint operator *(modint a,modint b){return a*=b;}
friend modint operator /(modint a,modint b){return a/=b;}
friend modint operator ^(modint a,int b){return a^=b;}
friend bool operator ==(modint a,int b){return a.x==b;}
friend bool operator !=(modint a,int b){return a.x!=b;}
bool operator ! () {return !x;}
modint operator - () {return x?mod-x:0;}
bool operator <(const modint&b)const{return x<b.x;}
};
inline modint qpow(modint x,int y){return x^y;}
vector<modint> fac,ifac,iv;
inline void initC(int n)
{
if(iv.empty())fac=ifac=iv=vector<modint>(2,1);
int m=iv.size(); ++n;
if(m>=n)return;
iv.resize(n),fac.resize(n),ifac.resize(n);
For(i,m,n-1){
iv[i]=iv[mod%i]*(mod-mod/i);
fac[i]=fac[i-1]*i,ifac[i]=ifac[i-1]*iv[i];
}
}
inline modint C(int n,int m){
if(m<0||n<m)return 0;
return initC(n),fac[n]*ifac[m]*ifac[n-m];
}
inline modint sign(int n){return (n&1)?(mod-1):(1);}
#define fi first
#define se second
#define pb push_back
#define mkp make_pair
typedef pair<int,int>pii;
typedef vector<int>vi;
#define maxn 200005
#define inf 0x3f3f3f3f
int n,m,Q;
vector<pii> e[maxn];
int fa[maxn][20],dep[maxn],val[maxn],dis[maxn],vis[maxn],top[maxn];
void dfs(int u,int pa){
fa[u][0]=pa,dep[u]=dep[pa]+1;
For(i,1,19)fa[u][i]=fa[fa[u][i-1]][i-1];
for(auto [v,w]:e[u])
if(v!=pa){
dis[v]=dis[u]+w;
if(vis[v]) val[v]=0,top[v]=v;
else val[v]=val[u]+w,top[v]=top[u];
dfs(v,u);
}
}
int lca(int u,int v){
if(dep[u]<dep[v])swap(u,v);
Rep(i,19,0)if(dep[fa[u][i]]>=dep[v])u=fa[u][i];
if(u==v)return u;
Rep(i,19,0)if(fa[u][i]!=fa[v][i])u=fa[u][i],v=fa[v][i];
return fa[u][0];
}
int dist(int u,int v){return dep[u]+dep[v]-2*dep[lca(u,v)];}
int kth(int u,int k){
For(i,0,19)if(k>>i&1)u=fa[u][i];
return u;
}
int jump(int u,int v){return kth(u,dep[u]-dep[v]-1);}
int go(int u,int v,int k){
int d=dep[lca(u,v)];
return k<=dep[u]-d?kth(u,k):kth(v,dep[v]+dep[u]-2*d-k);
}
int a[maxn];
void work()
{
n=read(),m=read(),Q=read();
For(i,1,n)e[i].clear(),val[i]=vis[i]=dis[i]=dep[i]=0;
For(i,1,m)vis[read()]=1;
For(i,2,n){
int u=read(),v=read(),w=read();
e[u].pb(mkp(v,w));
e[v].pb(mkp(u,w));
}
top[1]=1;
dfs(1,0);
For(i,1,n) assert(val[i]==dis[i]-dis[top[i]]);
For(_,1,Q){
int k=read();
For(i,1,k)a[i]=read();
sort(a+1,a+k+1,[&](int x,int y){
return val[x]<val[y];
});
// For(i,1,k)cout<<a[i]<<" "<<top[a[i]]<<"\n";
int res=val[a[k]];
int lc=0;
Rep(i,k,1){
if(top[a[k]]!=top[a[i]]) break;
if(i==k) lc=a[k];
else lc=lca(lc,a[i]);
res=min(res,max(dis[a[k]]-dis[lc],val[a[i-1]]));
}
cout<<res<<"\n";
}
}
signed main()
{
int T=read();
while(T--)work();
return 0;
}
/*
2
12 2 4
1 9
1 2 1
2 3 4
3 4 3
3 5 2
2 6 2
6 7 1
6 8 2
2 9 5
9 10 2
9 11 3
1 12 10
3 3 7 8
4 4 5 7 8
4 7 8 10 11
3 4 5 12
3 2 3
1 2
1 2 1
1 3 1
1 1
2 1 2
3 1 2 3
*/
这程序好像有点Bug,我给组数据试试?
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 19344kb
input:
2 12 2 4 1 9 1 2 1 2 3 4 3 4 3 3 5 2 2 6 2 6 7 1 6 8 2 2 9 5 9 10 2 9 11 3 1 12 10 3 3 7 8 4 4 5 7 8 4 7 8 10 11 3 4 5 12 3 2 3 1 2 1 2 1 1 3 1 1 1 2 1 2 3 1 2 3
output:
4 5 3 8 0 0 0
result:
ok 7 lines
Test #2:
score: 0
Accepted
time: 635ms
memory: 46320kb
input:
522 26 1 3 1 1 4 276455 18 6 49344056 18 25 58172365 19 9 12014251 2 1 15079181 17 1 50011746 8 9 2413085 23 24 23767115 22 2 26151339 26 21 50183935 17 14 16892041 9 26 53389093 1 20 62299200 24 18 56114328 11 2 50160143 6 26 14430542 16 7 32574577 3 16 59227555 3 15 8795685 4 12 5801074 5 20 57457...
output:
148616264 148616264 0 319801028 319801028 255904892 317070839 1265145897 1265145897 1072765445 667742619 455103436 285643094 285643094 285643094 317919339 0 785245841 691421476 605409472 479058444 371688030 303203698 493383271 919185207 910180170 919185207 121535083 181713164 181713164 181713164 181...
result:
ok 577632 lines
Extra Test:
score: 0
Extra Test Passed