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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#159447#7107. Chaleurucup-team088#AC ✓185ms16640kbC++177.4kb2023-09-02 17:56:282023-09-02 17:56:29

Judging History

你现在查看的是最新测评结果

  • [2023-09-02 17:56:29]
  • 评测
  • 测评结果:AC
  • 用时:185ms
  • 内存:16640kb
  • [2023-09-02 17:56:28]
  • 提交

answer

#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include<iostream>
#include<string>
#include<cstdio>
#include<vector>
#include<cmath>
#include<algorithm>
#include<functional>
#include<iomanip>
#include<queue>
#include<ciso646>
#include<random>
#include<map>
#include<set>
#include<bitset>
#include<stack>
#include<unordered_map>
#include<unordered_set>
#include<utility>
#include<cassert>
#include<complex>
#include<numeric>
#include<array>
#include<chrono>
using namespace std;

//#define int long long
typedef long long ll;

typedef unsigned long long ul;
typedef unsigned int ui;
//ll mod = 1;
constexpr ll mod = 998244353;
//constexpr ll mod = 1000000007;
const int mod17 = 1000000007;
const ll INF = mod * mod;
typedef pair<int, int>P;

#define rep(i,n) for(int i=0;i<n;i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define Rep(i,sta,n) for(int i=sta;i<n;i++)
#define rep1(i,n) for(int i=1;i<=n;i++)
#define per1(i,n) for(int i=n;i>=1;i--)
#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)
#define all(v) (v).begin(),(v).end()
typedef pair<ll, ll> LP;

using ld = double;
typedef pair<ld, ld> LDP;
const ld eps = 1e-10;
const ld pi = acosl(-1.0);

template<typename T>
void chmin(T& a, T b) {
	a = min(a, b);
}
template<typename T>
void chmax(T& a, T b) {
	a = max(a, b);
}
template<typename T>
vector<T> vmerge(vector<T>& a, vector<T>& b) {
	vector<T> res;
	int ida = 0, idb = 0;
	while (ida < a.size() || idb < b.size()) {
		if (idb == b.size()) {
			res.push_back(a[ida]); ida++;
		}
		else if (ida == a.size()) {
			res.push_back(b[idb]); idb++;
		}
		else {
			if (a[ida] < b[idb]) {
				res.push_back(a[ida]); ida++;
			}
			else {
				res.push_back(b[idb]); idb++;
			}
		}
	}
	return res;
}
template<typename T>
void cinarray(vector<T>& v) {
	rep(i, v.size())cin >> v[i];
}
template<typename T>
void coutarray(vector<T>& v) {
	rep(i, v.size()) {
		if (i > 0)cout << " "; cout << v[i];
	}
	cout << "\n";
}
ll mod_pow(ll x, ll n, ll m = mod) {
	if (n < 0) {
		ll res = mod_pow(x, -n, m);
		return mod_pow(res, m - 2, m);
	}
	if (abs(x) >= m)x %= m;
	if (x < 0)x += m;
	//if (x == 0)return 0;
	ll res = 1;
	while (n) {
		if (n & 1)res = res * x % m;
		x = x * x % m; n >>= 1;
	}
	return res;
}
//mod should be <2^31
struct modint {
	int n;
	modint() :n(0) { ; }
	modint(ll m) {
		if (m < 0 || mod <= m) {
			m %= mod; if (m < 0)m += mod;
		}
		n = m;
	}
	operator int() { return n; }
};
bool operator==(modint a, modint b) { return a.n == b.n; }
bool operator<(modint a, modint b) { return a.n < b.n; }
modint operator+=(modint& a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= (int)mod; return a; }
modint operator-=(modint& a, modint b) { a.n -= b.n; if (a.n < 0)a.n += (int)mod; return a; }
modint operator*=(modint& a, modint b) { a.n = ((ll)a.n * b.n) % mod; return a; }
modint operator+(modint a, modint b) { return a += b; }
modint operator-(modint a, modint b) { return a -= b; }
modint operator*(modint a, modint b) { return a *= b; }
modint operator^(modint a, ll n) {
	if (n == 0)return modint(1);
	modint res = (a * a) ^ (n / 2);
	if (n % 2)res = res * a;
	return res;
}

ll inv(ll a, ll p) {
	return (a == 1 ? 1 : (1 - p * inv(p % a, a)) / a + p);
}
modint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }
modint operator/=(modint& a, modint b) { a = a / b; return a; }
const int max_n = 1 << 20;
modint fact[max_n], factinv[max_n];
void init_f() {
	fact[0] = modint(1);
	for (int i = 0; i < max_n - 1; i++) {
		fact[i + 1] = fact[i] * modint(i + 1);
	}
	factinv[max_n - 1] = modint(1) / fact[max_n - 1];
	for (int i = max_n - 2; i >= 0; i--) {
		factinv[i] = factinv[i + 1] * modint(i + 1);
	}
}
modint comb(int a, int b) {
	if (a < 0 || b < 0 || a < b)return 0;
	return fact[a] * factinv[b] * factinv[a - b];
}
modint combP(int a, int b) {
	if (a < 0 || b < 0 || a < b)return 0;
	return fact[a] * factinv[a - b];
}

ll gcd(ll a, ll b) {
	a = abs(a); b = abs(b);
	if (a < b)swap(a, b);
	while (b) {
		ll r = a % b; a = b; b = r;
	}
	return a;
}
template<typename T>
void addv(vector<T>& v, int loc, T val) {
	if (loc >= v.size())v.resize(loc + 1, 0);
	v[loc] += val;
}
/*const int mn = 2000005;
bool isp[mn];
vector<int> ps;
void init() {
	fill(isp + 2, isp + mn, true);
	for (int i = 2; i < mn; i++) {
		if (!isp[i])continue;
		ps.push_back(i);
		for (int j = 2 * i; j < mn; j += i) {
			isp[j] = false;
		}
	}
}*/

//[,val)
template<typename T>
auto prev_itr(set<T>& st, T val) {
	auto res = st.lower_bound(val);
	if (res == st.begin())return st.end();
	res--; return res;
}

//[val,)
template<typename T>
auto next_itr(set<T>& st, T val) {
	auto res = st.lower_bound(val);
	return res;
}
using mP = pair<modint, modint>;
mP operator+(mP a, mP b) {
	return { a.first + b.first,a.second + b.second };
}
mP operator+=(mP& a, mP b) {
	a = a + b; return a;
}
mP operator-(mP a, mP b) {
	return { a.first - b.first,a.second - b.second };
}
mP operator-=(mP& a, mP b) {
	a = a - b; return a;
}
LP operator+(LP a, LP b) {
	return { a.first + b.first,a.second + b.second };
}
LP operator+=(LP& a, LP b) {
	a = a + b; return a;
}
LP operator-(LP a, LP b) {
	return { a.first - b.first,a.second - b.second };
}
LP operator-=(LP& a, LP b) {
	a = a - b; return a;
}

mt19937 mt(time(0));

const string drul = "DRUL";
string senw = "SENW";
//DRUL,or SENW
//int dx[4] = { 1,0,-1,0 };
//int dy[4] = { 0,1,0,-1 };

//------------------------------------


void solve() {
	int n, m; cin >> n >> m;
	vector<vector<int>> G(n);
	rep(i, m) {
		int a, b; cin >> a >> b; a--; b--;
		G[a].push_back(b);
		G[b].push_back(a);
	}
	auto comp = [&](int x, int y) {
		return G[x].size() > G[y].size();
	};
	vector<int> ids(n); rep(i, n)ids[i] = i;
	sort(all(ids), comp);
	vector<bool> iss(n);
	int cc = 0;
	for (int id : ids) {
		int num = 0;
		for (int to : G[id])if (iss[to])num++;
		if (num == cc) {
			iss[id] = true; cc++;
		}
	}
	//cout << "??\n";
	//coutarray(iss);



	ll ans1 = 0, ans2 = 0;
	//after divide
	vector<int> vs, vt;
	rep(i, n) {
		if (iss[i])vs.push_back(i);
		else vt.push_back(i);
	}
	int c = 0;
	rep(i, vs.size()) {
		bool exi = false;
		for (int to : G[vs[i]]) {
			if (!iss[to]) {
				exi = true;
			}
		}
		if (!exi)c++;
	}
	if (c > 0) {
		ans2 = c;
	}
	else {
		ll c2 = 1;
		rep(i, vs.size()) {
			vector<int> tos;
			for (int to : G[vs[i]])if (!iss[to]) {
				tos.push_back(to);
			}
			if (tos.size() >= 2) {
				//
			}
			else if (tos.size() == 1) {
				c2++;
				//ids[vs[i]] = tos[0];
			}
			else {
				assert(false);
				/*cl++;
				ids[vs[i]] = -2;*/
			}
		}
		ans2 = c2;
	}
	ll c2 = 1;
	set<int> st;
	for (int id : vs)st.insert(id);
	rep(i, vt.size()) {
		for (int to : G[vt[i]])if (iss[to]) {
			st.erase(to);
		}

		if (st.size() >= 2) {
			//
		}
		else if (st.size() == 1) {
			c2++;
			//int to = *st.begin();
			//if (ids[to] == vt[i] || ids[to] == -2)c2++;
		}
		else {
			assert(false);
			/*c2 += cl;
			ids[vt[i]] = -2;*/
		}


		for (int to : G[vt[i]])if (iss[to]) {
			st.insert(to);
		}
	}
	ans1 = c2;
	

	//cout << "ans is ";
	cout << ans1 << " " << ans2 << "\n";
}




signed main() {
	ios::sync_with_stdio(false);
	cin.tie(0);
	//cout << fixed<<setprecision(10);
	//init_f();
	//init();
	//init2();
	//while(true)
	//expr();
	int t; cin >> t; rep(i, t)
		solve();
	return 0;
}

这程序好像有点Bug,我给组数据试试?

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 12144kb

input:

3
3 2
1 2
2 3
6 6
1 2
2 3
1 3
1 4
2 5
3 6
4 1
1 2

output:

2 1
1 4
1 2

result:

ok 3 lines

Test #2:

score: 0
Accepted
time: 185ms
memory: 16640kb

input:

2231
1 0
5 7
4 1
3 4
3 1
3 5
4 2
3 2
4 5
5 4
2 1
2 5
2 4
2 3
5 10
3 2
2 5
1 4
4 2
4 5
1 2
1 3
3 5
3 4
1 5
5 10
1 3
2 4
1 4
5 2
2 3
1 5
5 4
1 2
3 4
5 3
5 9
2 5
3 5
2 3
2 1
4 3
3 1
4 1
4 5
2 4
5 4
4 2
4 1
4 5
4 3
5 9
4 1
4 5
3 4
2 4
2 1
3 1
2 5
3 5
3 2
5 4
2 5
2 3
2 1
2 4
5 9
5 2
1 3
4 3
1 2
5 4
4 2
5...

output:

1 1
3 1
4 1
1 5
1 5
2 1
4 1
2 1
4 1
2 1
2 1
3 1
4 1
4 1
1 5
2 1
4 1
1 5
1 5
1 5
3 1
4 1
4 1
4 1
3 1
3 1
4 1
4 1
2 1
4 1
4 1
1 5
1 5
2 1
4 1
4 1
4 1
3 1
2 1
4 1
2 1
4 1
4 1
4 1
3 1
1 5
4 1
4 1
1 5
2 1
4 1
2 1
2 1
1 5
4 1
1 5
3 1
4 1
1 5
2 1
1 5
3 1
3 1
1 5
3 1
3 1
2 1
1 5
4 1
3 1
1 5
2 1
3 1
2 1
2 1
...

result:

ok 2231 lines

Extra Test:

score: 0
Extra Test Passed