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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#158049 | #7108. Couleur | ucup-team866# | AC ✓ | 1725ms | 31720kb | C++14 | 2.9kb | 2023-09-02 16:09:34 | 2023-09-02 16:09:34 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N = 2e5 + 5, NN = 2e6 + 6;
int T, n, root[N], nodes, ls[NN], rs[NN], tree[NN], cnt, l[N], r[N], id[N], a[N]; ll inv[N], x;
void update(int &rt, int lrt, int l, int r, int x) {
rt = ++ nodes;
if (l == r) return void (tree[rt] = tree[lrt] + 1);
int mid = l + r >> 1;
if (x <= mid) rs[rt] = rs[lrt], update(ls[rt], ls[lrt], l, mid, x);
else ls[rt] = ls[lrt], update(rs[rt], rs[lrt], mid+1, r, x);
tree[rt] = tree[ls[rt]] + tree[rs[rt]];
}
int query(int rt, int l, int r, int x, int y) {
if (! rt || x > y) return 0;
if (l == x && r == y) return tree[rt];
int mid = l + r >> 1;
if (y <= mid) return query(ls[rt], l, mid, x, y);
else if (x > mid) return query(rs[rt], mid+1, r, x, y);
else return query(ls[rt], l, mid, x, mid) + query(rs[rt], mid+1, r, mid+1, y);
}
int main() {
cin >> T;
while (T --) {
scanf ("%d", &n);
for (int i=1; i<=n; i++)
root[i] = 0; nodes = 0;
cnt = 1, l[1] = 1, r[1] = n, inv[1] = 0, id[n+1] = 0;
for (int i=1; i<=n; i++)
scanf ("%d", &a[i]), update(root[i], root[i-1], 1, n, a[i]),
inv[1] += query(root[i-1], 1, n, a[i] + 1, n), id[i] = 1;
priority_queue <ll> que, del;
que. push(inv[1]);
for (int i=1; i<=n; i++) {
while (! del. empty() && del. top() == que. top())
del. pop(), que. pop();
printf (i < n ? "%lld " : "%lld\n", que. top());
scanf ("%lld", &x), x ^= que. top();
int y = id[x]; id[x] = 0, del. push(inv[y]);
if (! id[x-1] && ! id[x+1]) continue;
if (x - l[y] <= r[y] - x) {
inv[y] -= query(root[x-1], 1, n, a[x] + 1, n) - query(root[l[y]-1], 1, n, a[x] + 1, n);
for (int j=l[y]; j<=x; j++)
inv[y] -= query(root[r[y]], 1, n, 1, a[j] - 1) - query(root[x], 1, n, 1, a[j] - 1);
if (x > l[y]) {
cnt ++, l[cnt] = l[y], r[cnt] = x - 1, inv[cnt] = 0;
for (int j=l[cnt]; j<=r[cnt]; j++)
id[j] = cnt;
for (int j=l[cnt]+1; j<=r[cnt]; j++)
inv[cnt] += query(root[j-1], 1, n, a[j] + 1, n) - query(root[l[cnt]-1], 1, n, a[j] + 1, n);
inv[y] -= inv[cnt], que. push(inv[cnt]);
} l[y] = x + 1, que. push(inv[y]);
} else {
inv[y] -= query(root[r[y]], 1, n, 1, a[x] - 1) - query(root[x], 1, n, 1, a[x] - 1);
for (int j=x; j<=r[y]; j++)
inv[y] -= query(root[x-1], 1, n, a[j] + 1, n) - query(root[l[y]-1], 1, n, a[j] + 1, n);
if (x < r[y]) {
cnt ++, l[cnt] = x + 1, r[cnt] = r[y], inv[cnt] = 0;
for (int j=l[cnt]; j<=r[cnt]; j++)
id[j] = cnt;
for (int j=l[cnt]+1; j<=r[cnt]; j++)
inv[cnt] += query(root[j-1], 1, n, a[j] + 1, n) - query(root[l[cnt]-1], 1, n, a[j] + 1, n);
inv[y] -= inv[cnt], que. push(inv[cnt]);
} r[y] = x - 1, que. push(inv[y]);
}
/* puts ("");
for (int i=1; i<=n; i++)
printf ("%d ", id[i]);
puts ("");
for (int i=1; i<=n; i++)
if (id[i] && id[i] != id[i-1])
printf ("%d : %lld\n", id[i], inv[id[i]]);
puts (""); */
}
}
}
这程序好像有点Bug,我给组数据试试?
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 2ms
memory: 7896kb
input:
3 5 4 3 1 1 1 5 4 5 3 1 10 9 7 1 4 7 8 5 7 4 8 21 8 15 5 9 2 4 5 10 6 15 4 8 8 1 12 1 10 14 7 14 2 9 13 10 3 37 19 23 15 7 2 10 15 2 13 4 5 8 7 10
output:
7 0 0 0 0 20 11 7 2 0 0 0 0 0 0 42 31 21 14 14 4 1 1 1 0 0 0 0 0 0
result:
ok 3 lines
Test #2:
score: 0
Accepted
time: 1725ms
memory: 31720kb
input:
11116 10 10 5 10 3 6 4 8 5 9 8 31 27 24 11 12 3 0 2 3 1 10 8 2 7 2 8 10 1 10 9 10 6 5 2 13 2 1 0 1 3 1 10 7 10 7 6 1 3 10 6 7 9 21 18 10 1 6 5 4 8 9 10 10 2 10 4 8 8 5 7 2 6 7 20 10 9 1 15 0 4 2 9 7 10 1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10 10 1 2 3 4 5 6 7 8 9 10 6 3 5 2 7 10 9 1 4 8 10 1 10 1 3...
output:
21 18 16 12 10 6 4 1 1 0 12 12 10 10 4 4 4 2 1 0 20 16 9 5 3 3 3 0 0 0 22 14 8 8 5 5 2 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 19 12 7 4 4 2 2 1 0 0 20 18 8 3 1 1 0 0 0 0 45 21 21 10 3 3 3 0 0 0 17 11 8 2 1 1 1 0 0 0 13 4 1 0 0 0 0 0 0 0 29 27 22 15 9 7 4 3 1 0 26 16 9 2 1 1 1 1 1 0 0 0 0 0 0 ...
result:
ok 11116 lines
Extra Test:
score: 0
Extra Test Passed