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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#156298#7109. Traveling on the Axisucup-team918#AC ✓8ms6244kbC++142.0kb2023-09-02 13:24:282023-09-02 14:33:29

Judging History

你现在查看的是最新测评结果

  • [2023-09-02 14:33:29]
  • 评测
  • 测评结果:AC
  • 用时:8ms
  • 内存:6244kb
  • [2023-09-02 13:24:28]
  • 提交

answer

//#pragma GCC optimize(2)
#include<bits/stdc++.h>
using namespace std;
#define int long long
#define ll long long
#define N 200005
#define mod 998244353
#define pii pair<int,int>
#define mp make_pair
#define pb push_back
#define ld long double
#define ls (rt<<1)
#define rs ((rt<<1)|1)
#define SZ(x) (int)(x.size())
#define debug cout<<endl<<"ff"<<endl
#define YES cout<<"YES"<<endl
#define NO cout<<"NO"<<endl
#define fi first
#define se second
#define INF 1e9
#define pq priority_queue
#define rep(x,a,b) for(int x=a;x<=b;x++)
int qpow(int a,int b){
	int res=1;
	for(;b;b>>=1){
		if(b&1) res=res*a%mod;
		a=a*a%mod;
	}
	return res;
}
/*int fac[N],ifac[N];
int C(int n,int m){
	if(m>n||m<0||n<0) return 0;
	return fac[n]*ifac[n-m]%mod*ifac[m]%mod;
}
void init(){
	fac[0]=1;
	for(int i=1;i<N;i++) fac[i]=fac[i-1]*i%mod;
	ifac[N-1]=qpow(fac[N-1],mod-2);
	for(int i=N-2;i>=0;i--) ifac[i]=ifac[i+1]*(i+1)%mod;
}*/
/*struct node{
	int nxt,to;
}e[N<<1];
int cnt=1,head[N];
inline void add(int x,int y){
	e[++cnt].nxt=head[x];
	head[x]=cnt;
	e[cnt].to=y;
}*/
inline int lowbit(int x){return x&(-x);}
inline int read(){
  int x=0,t=1;char ch=getchar();
  while(ch<'0'||ch>'9'){
    if(ch=='-') t=-1;
    ch=getchar();
  }
    while(ch>='0'&&ch<='9'){
        x=(x<<1)+(x<<3)+(ch-'0');
        ch=getchar();
    }
    return x*t;
}
inline void write(int x){
	if(x<0) putchar('-'),x=-x;
	if(x>=10) write(x/10);
	putchar(x%10+'0');
}
int T,n,dp[N][2];
string s;
signed main(){
	ios::sync_with_stdio(false);
	cin.tie(0);cout.tie(0);
	cin>>T;
	while(T--){
		cin>>s;n=s.size();s=" "+s;
		int ans=0;
		for(int i=0;i<=n;i++) dp[i][0]=dp[i][1]=0;
		//0表示偶数时间,1奇数 
		for(int i=n-1;i>=0;i--){
			if(s[i+1]=='1'){
				dp[i][0]=dp[i+1][1]+n-i;
				dp[i][1]=dp[i+1][1]+2*(n-i);
			}else{
				dp[i][0]=dp[i+1][0]+2*(n-i);
				dp[i][1]=dp[i+1][0]+n-i;
			}
			ans+=dp[i][0];
		}
		cout<<ans<<endl;
	}
	return 0;
}

这程序好像有点Bug,我给组数据试试?

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 1ms
memory: 3808kb

input:

3
101
011
11010

output:

12
15
43

result:

ok 3 lines

Test #2:

score: 0
Accepted
time: 8ms
memory: 6244kb

input:

6107
1010101
010110100110101
1010
1010101010010101010
101011
0101101011010101010
0101101011
11011010101
010
1011010
10110101010101010100
010101010110101
10101010101011
0101010101010101011
00101010011000
1010101010010110110
01010101001010101010
101010101010101
100100101010101010
01
011
0101010100101
...

output:

96
889
24
1515
69
1567
279
345
14
106
1702
791
621
1447
764
1615
1755
736
1333
6
15
542
44
1689
1515
140
833
497
596
24
1640
694
462
30
425
14
1041
1446
96
504
124
75
560
970
771
945
6
1
321
137
786
720
206
769
46
103
225
74
554
2
100
529
260
207
197
2
197
1041
140
857
207
1
74
1604
41
343
1041
14
1...

result:

ok 6107 lines

Extra Test:

score: 0
Extra Test Passed