#include <bits/stdc++.h>
using namespace std;

typedef long double db;
const db eps=0;
int sign(db k){
	if (k<-eps) return -1;
	else if (k>eps) return 1;
	return 0;
}
int cmp(db k1,db k2){return sign(k1-k2);}

struct point{
	db x,y,z;
	point operator + (const point &k){return (point){x+k.x,y+k.y,z+k.z};}
	point operator - (const point &k){return (point){x-k.x,y-k.y,z-k.z};}
	point operator * (db k){return (point){x*k,y*k,z*k};}
	point operator / (db k){return (point){x/k,y/k,z/k};}
	db abs2(){return x*x+y*y+z*z;}
	db abs(){return hypot(hypot(x,y),z);}
	db dis(point k){return ((*this)-k).abs();}
	point unit(){
		db d=abs();
		return (point){x/d,y/d,z/d};	
	}
	void print(){
		cerr << "(" << x << "," << y << "," << z << ") ";
	}
};
int main(){
	ios_base::sync_with_stdio(false);
	cout << fixed << setprecision(12);
	int T;
	cin >> T;
	for (;T--;){
		int x,y,z;
		cin >> x >> y >> z;
		
		if (x==0 && y==0 && z==0){
			cout << 0 << "\n";
			continue;
		}
		if ((x==0 || x==255) && (y==0 || y==255) && (z==0 || z==255)){
			cout << 1 << "\n";
			cout << x << " " << y << " " << z << " " << 1000.0 << "\n";
		}
		
		point ed=(point){(db)x,(db)y,(db)z};
		point P=(point){sign(ed.x)==0?0.0:255.0,sign(ed.y)==0?0.0:255.0,sign(ed.z)==0?0.0:255.0};
		vector<pair<point,db>> ans;
		for (int cc=1;cc<=3;cc++){	
		//	ed.print();P.print();
		//	cerr << endl;
			point dir=(ed-P).unit();
			db l=0,r=1000;
			for (int tt=1;tt<=100;tt++){
				db mid=(l+r)/2;
				point tmp=ed+dir*mid;
				if (sign(tmp.x)<0 || sign(tmp.y)<0 || sign(tmp.z)<0) r=mid;
				else l=mid;
			}
			point nxt=ed+dir*l;
			ans.emplace_back(P,l);
			
			ed=nxt;
			if (sign(ed.x)==0) ed.x=0;
			if (sign(ed.y)==0) ed.y=0;
			if (sign(ed.z)==0) ed.z=0;
			P=(point){sign(ed.x)==0?0.0:255.0,sign(ed.y)==0?0.0:255.0,sign(ed.z)==0?0.0:255.0};
			if (sign(P.x)==0 && sign(P.y)==0 && sign(P.z)==0) break;
		}
		
		reverse(ans.begin(),ans.end());
		cout << (int)ans.size() << "\n";
		for (auto [P,t]:ans){
			int x=P.x+0.5;
			int y=P.y+0.5;
			int z=P.z+0.5;
			cout << x << " " << y << " " << z << " " << t << "\n";	
		}
	}
	return 0;	
}