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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#152515#6309. Aqrechen_zexingWA 6ms3692kbC++172.3kb2023-08-28 10:54:262023-08-28 10:54:28

Judging History

你现在查看的是最新测评结果

  • [2023-08-28 10:54:28]
  • 评测
  • 测评结果:WA
  • 用时:6ms
  • 内存:3692kb
  • [2023-08-28 10:54:26]
  • 提交

answer

#pragma GCC optimize("Ofast,unroll-loops")
#include <bits/stdc++.h>
using namespace std;
int a[1005][1005];
int main() {
    int T = 1, kase = 0;
    cin >> T;
    while (T--) {
        int n, m;
        cin >> n >> m;
        if (n <= 3 && m <= 3) {
            printf("%d\n", n * m);
            for (int i = 1; i <= n; i++, puts(""))
                for (int j = 1; j <= m; j++)
                    printf("1");
        }
        else if (n == 3) {
            int ans=m/4*9+m%4*3-(m%4>1);
            printf("%d\n",ans);
            for(int i=1;i<=n;i++,puts(""))
                for(int j=1;j<=m;j++){
                    if(j%4==2&&i==3||j%4==0&&i!=3) printf("0");
                    else printf("1");
                }
        }
        else if (m == 3) {
            int ans=n/4*9+n%4*3-(n%4>1);
            printf("%d\n",ans);
            for(int i=1;i<=n;i++,puts(""))
                for(int j=1;j<=m;j++){
                    if(i%4==2&&j==3||i%4==0&&j!=3) printf("0");
                    else printf("1");
                }
        }
        else {
            int ans = 0;
            for (int i = 1; i <= n; i++) {
                if (i % 4 == 1) ans += m / 4 * 3 + m % 4;
                else if (i % 4 == 2) ans += m / 4 * 3 + m % 4 - (m % 4 > 1);
                else if (i % 4 == 3) ans += m / 4 * 3 + m % 4 - (m % 4 > 2);
                else ans += m / 4 * 3 + m % 4 - (m%4>0);
            }
            printf("%d\n", ans);
            for (int i = 1; i <= n; i++)
                for (int j = 1; j <= m; j++) {
                    if (i % 4 == 1 && j % 4 == 0 || i % 4 == 2 && j % 4 == 2 || i % 4 == 3 && j % 4 == 3 ||
                        i % 4 == 0 && j % 4 == 1)
                        a[i][j]=0;
                    else a[i][j]=1;
                }
            if(n%4==1&&m%4==1){
                for(int i=2;i<=n;i+=4)
                    for(int j=1;j<=m;j++){
                        int ov=a[i][j];
                        a[i][j]=a[i+1][j],a[i+1][j]=a[i+2][j],a[i+2][j]=ov;
                    }
            }
            for(int i=1;i<=n;i++,puts(""))
                for(int j=1;j<=m;j++)
                    printf("%d",a[i][j]);
        }
    }
    return 0;
}
/*
11101
11011
01110
10111
11101
 */


详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 3628kb

input:

3
2 2
3 4
3 8

output:

4
11
11
9
1110
1110
1011
18
11101110
11101110
10111011

result:

ok ok (3 test cases)

Test #2:

score: -100
Wrong Answer
time: 6ms
memory: 3692kb

input:

361
2 2
2 3
2 4
2 5
2 6
2 7
2 8
2 9
2 10
2 11
2 12
2 13
2 14
2 15
2 16
2 17
2 18
2 19
2 20
3 2
3 3
3 4
3 5
3 6
3 7
3 8
3 9
3 10
3 11
3 12
3 13
3 14
3 15
3 16
3 17
3 18
3 19
3 20
4 2
4 3
4 4
4 5
4 6
4 7
4 8
4 9
4 10
4 11
4 12
4 13
4 14
4 15
4 16
4 17
4 18
4 19
4 20
5 2
5 3
5 4
5 5
5 6
5 7
5 8
5 9
5 1...

output:

4
11
11
6
111
111
6
1110
1011
8
11101
10111
9
111011
101110
11
1110111
1011101
12
11101110
10111011
14
111011101
101110111
15
1110111011
1011101110
17
11101110111
10111011101
18
111011101110
101110111011
20
1110111011101
1011101110111
21
11101110111011
10111011101110
23
111011101110111
1011101110111...

result:

wrong answer ans finds a larger answer (test case 81)