QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#152154#5414. Stop, Yesterday Please No Morelaxx99#TL 1ms5484kbC++143.5kb2023-08-27 17:24:312023-08-27 17:24:32

Judging History

你现在查看的是最新测评结果

  • [2023-08-27 17:24:32]
  • 评测
  • 测评结果:TL
  • 用时:1ms
  • 内存:5484kb
  • [2023-08-27 17:24:31]
  • 提交

answer

#include<bits/stdc++.h>
#define INF 0x3f3f3f3f
#define PI acos(-1)
#define endl "\n"
#define int long long
#define pb push_back
#define fi first
#define se second
using namespace std;
typedef pair<int, int> PII;
typedef unsigned long long ULL;
const int N = 1e6+5,mod=1e9+7,modd=998244353;
int ar[N],br[N];
int  k, s,n,m,sum1,len;
int cmp(int a, int b){	return a > b;}
int lowbit(int x){return x&(-x);}
int read() { int x=0,f=1; char c=getchar(); while(c<'0'||c>'9'){if(c=='-') f=-1;c=getchar();}
while(c>='0'&&c<='9') x=x*10+c-'0',c=getchar();return x*f;}
const double eps = 1e-8;
int tree[5000][5000];
// void add(int x,int y,int v)
// {
	
//     while(x<=n)
//     {
//         int ty=y;
//         while(ty<=n)
//         tree[x][ty]+=v,ty+=lowbit(ty);
// 		//cout<<"x="<<x<<" ty="<<ty<<endl;
//         x+=lowbit(x);
//     }
// }
// int ask(int x, int y)
// {
//     int res=0;
//     while(x)
//     {
//         int ty=y;
//         while(ty)
//             res+=tree[x][ty],ty-=lowbit(ty);
//         x-=lowbit(x);
// 		// cout<<"x="<<x<<" ty="<<ty<<endl;
// 		// cout<<res<<endl;
//     }
//     return res;
// }
void add(int x, int y, int k) {
	for (int i = x; i <= n; i += lowbit(i)) {
		for (int j = y; j <= m; j += lowbit(j)) {
			tree[i][j] += k;
			
		}
	}
	return;
}
long long get(int x, int y) {
	long long sum = 0;
	for (int i = x; i > 0; i -= lowbit(i)) {
		for (int j = y; j > 0; j -= lowbit(j)) {
			sum += tree[i][j];
			
		}
	}
	return sum;
}
void real_add(int x1,int y1,int x2,int y2,int v)
{
    add(x1,y1,v);
    add(x1,y2+1,-v);
    add(x2+1,y1,-v);
    add(x2+1,y2+1,v);
}


signed main()
{
	int t=1;
	ios_base::sync_with_stdio(false);cin.tie(0); cout.tie(0);
 
	cin>>t;
	for(int ff=1;ff<= t;ff++)
	{
		int a, b,c,d, l, y, x, s, r,flag = 0,idx = 0,gg = 0,hh=0,res=0,sum=0, sum2 = 0;
		string str2,str,str3;

         //cin>>n;
		// for(int i=1;i<=n;i++)cin>>ar[i];
	      cin>>n>>m>>k;
		  for(int i=0;i<=n+1;i++)
		  {
			for(int j=0;j<=m+2;j++)
			{
				tree[i][j]=0;
			}
		  }
		  cin>>str;
		  int upl=1,dol=n,lel=1,ril=m;
		  int x1=lel,y1=upl,x2=ril,y2=dol;
		  x=1;
		  for(int i=0;i<str.length();i++)
		  {
           if(str[i]=='U')y1--,y2--,upl=max(upl,y1),dol=min(dol,y2);
		   if(str[i]=='D')y2++,y1++,upl=max(upl,y1),dol=min(dol,y2);
		   if(str[i]=='L')x1--,x2--,lel=max(lel,x1),ril=min(ril,x2);
		   if(str[i]=='R')x2++,x1++,lel=max(lel,x1),ril=min(ril,x2);
		  }
		  swap(upl,dol);
		   int yuan=(upl-dol+1)*(ril-lel+1);
		  int que=yuan-k;
		//  cout<<upl<<" "<<dol<<" "<<lel<<" "<<ril<<endl;
		//  cout<<yuan<<" "<<que<<endl;
		 
		 if(upl<dol||ril<lel)
		 {
			if(k==0)cout<<n*m<<endl;
			else cout<<0<<endl;
			continue;
		 }
	      if((upl-dol+1)*(ril-lel+1)-k<0)
		  {
			cout<<0<<endl;
			continue;
		  }
		  if((upl-dol+1)*(ril-lel+1)==k)
		  {
			cout<<0<<endl;
			continue;
		  }
		x1=lel,y1=upl,x2=ril,y2=dol;
		y1=n-y1+1;y2=n-y2+1;
		// cout<<x1<<" "<<y1<<" "<<x2<<" "<<y2<<endl;
		real_add(x1,y1,x2,y2,1);
		// cout<<x1<<" "<<y1<<" "<<x2<<" "<<y2<<endl;
           for(int i=0;i<str.length();i++)
		   {
       
		if(str[i]=='U')y1++,y2++;
		if(str[i]=='D')y2--,y1--;
		if(str[i]=='L')x1--,x2--;
		if(str[i]=='R')x2++,x1++;
		// cout<<x1<<" "<<y1<<" "<<x2<<" "<<y2<<endl;
		real_add(x1,y1,x2,y2,1);
		   }
         for(int i=1;i<=n;i++)
		  {
			for(int j=1;j<=m;j++)
			{
				//cout<<get(i,j)<<" ";
				if(get(i,j)==k)sum++;
			}
			//cout<<endl;
		  }
		  cout<<sum<<endl;
	}
return 0;
}


Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 1ms
memory: 5484kb

input:

3
4 5 3
ULDDRR
4 5 0
UUUUUUU
4 5 10
UUUUUUU

output:

2
20
0

result:

ok 3 number(s): "2 20 0"

Test #2:

score: -100
Time Limit Exceeded

input:

1060
19 12 0
UDLDDUUUUDDDLLRDUDUURULUUUDRDUDRDRLRLRLULULLLDLDDRLUUUURUUUDDRLLRUUUDULURUULLRDRLRDDURDUUURRRLURLRUULRRUDURDLUUURDLURDDLUUURDDRLLURRDLRUDLRDRLLRRDRDDLDRURRRLUDULLLRUUDLRRURRDLLRRRDLLRDDDLRLRURURDDDL
11 1 0
UR
3 18 33
UDRLR
17 11 132
RLDRDLDRUU
6 10 13
UULUDDLRDLUUDLDD
1 15 0
D
6 20 50
D...

output:


result: