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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#151489#7087. Counting PolygonsCrysflyTL 198ms213320kbC++176.5kb2023-08-26 19:52:462023-08-26 19:52:48

Judging History

你现在查看的是最新测评结果

  • [2023-08-26 19:52:48]
  • 评测
  • 测评结果:TL
  • 用时:198ms
  • 内存:213320kb
  • [2023-08-26 19:52:46]
  • 提交

answer

# pragma GCC optimize (2)
# pragma GCC optimize (3)
# pragma GCC target ("avx")
# pragma GCC optimize ("Ofast")
# pragma GCC optimize ("inline")
# pragma GCC optimize ("-fgcse")
# pragma GCC optimize ("-fgcse-lm")
# pragma GCC optimize ("-fipa-sra")
# pragma GCC optimize ("-ftree-pre")
# pragma GCC optimize ("-ftree-vrp")
# pragma GCC optimize ("-fpeephole2")
# pragma GCC optimize ("-ffast-math")
# pragma GCC optimize ("-fsched-spec")
# pragma GCC optimize ("unroll-loops")
# pragma GCC optimize ("-falign-jumps")
# pragma GCC optimize ("-falign-loops")
# pragma GCC optimize ("-falign-labels")
# pragma GCC optimize ("-fdevirtualize")
# pragma GCC optimize ("-fcaller-saves")
# pragma GCC optimize ("-fcrossjumping")
# pragma GCC optimize ("-fthread-jumps")
# pragma GCC optimize ("-funroll-loops")
# pragma GCC optimize ("-fwhole-program")
# pragma GCC optimize ("-freorder-blocks")
# pragma GCC optimize ("-fschedule-insns")
# pragma GCC optimize ("inline-functions")
# pragma GCC optimize ("-ftree-tail-merge")
# pragma GCC optimize ("-fschedule-insns2")
# pragma GCC optimize ("-fstrict-aliasing")
# pragma GCC optimize ("-fstrict-overflow")
# pragma GCC optimize ("-falign-functions")
# pragma GCC optimize ("-fcse-skip-blocks")
# pragma GCC optimize ("-fcse-follow-jumps")
# pragma GCC optimize ("-fsched-interblock")
# pragma GCC optimize ("-fpartial-inlining")
# pragma GCC optimize ("no-stack-protector")
# pragma GCC optimize ("-freorder-functions")
# pragma GCC optimize ("-findirect-inlining")
# pragma GCC optimize ("-fhoist-adjacent-loads")
# pragma GCC optimize ("-frerun-cse-after-loop")
# pragma GCC optimize ("inline-small-functions")
# pragma GCC optimize ("-finline-small-functions")
# pragma GCC optimize ("-ftree-switch-conversion")
# pragma GCC optimize ("-foptimize-sibling-calls")
# pragma GCC optimize ("-fexpensive-optimizations")
# pragma GCC optimize ("-funsafe-loop-optimizations")
# pragma GCC optimize ("inline-functions-called-once")
# pragma GCC optimize ("-fdelete-null-pointer-checks")

#include<bits/stdc++.h>
#define For(i,a,b) for(register int i=(a);i<=(b);++i)
#define Rep(i,a,b) for(register int i=(a);i>=(b);--i)
//#define int long long
using namespace std;
inline int read()
{
    char c=getchar();int x=0;bool f=0;
    for(;!isdigit(c);c=getchar())f^=!(c^45);
    for(;isdigit(c);c=getchar())x=(x<<1)+(x<<3)+(c^48);
    if(f)x=-x;return x;
}
  
#define mod 1000000007
struct modint{
    int x;
    modint(int o=0){x=o;}
    modint &operator = (int o){return x=o,*this;}
    modint &operator +=(modint o){return x=x+o.x>=mod?x+o.x-mod:x+o.x,*this;}
    modint &operator -=(modint o){return x=x-o.x<0?x-o.x+mod:x-o.x,*this;}
    modint &operator *=(modint o){return x=1ll*x*o.x%mod,*this;}
    modint &operator ^=(int b){
        modint a=*this,c=1;
        for(;b;b>>=1,a*=a)if(b&1)c*=a;
        return x=c.x,*this;
    }
    modint &operator /=(modint o){return *this *=o^=mod-2;}
    modint &operator +=(int o){return x=x+o>=mod?x+o-mod:x+o,*this;}
    modint &operator -=(int o){return x=x-o<0?x-o+mod:x-o,*this;}
    modint &operator *=(int o){return x=1ll*x*o%mod,*this;}
    modint &operator /=(int o){return *this *= ((modint(o))^=mod-2);}
    template<class I>friend modint operator +(modint a,I b){return a+=b;}
    template<class I>friend modint operator -(modint a,I b){return a-=b;}
    template<class I>friend modint operator *(modint a,I b){return a*=b;}
    template<class I>friend modint operator /(modint a,I b){return a/=b;}
    friend modint operator ^(modint a,int b){return a^=b;}
    friend bool operator ==(modint a,int b){return a.x==b;}
    friend bool operator !=(modint a,int b){return a.x!=b;}
    bool operator ! () {return !x;}
    modint operator - () {return x?mod-x:0;}
    bool operator <(const modint&b)const{return x<b.x;}
};
inline modint qpow(modint x,int y){return x^y;}
  
vector<modint> fac,ifac,iv;
inline void initC(int n)
{
    if(iv.empty())fac=ifac=iv=vector<modint>(2,1);
    int m=iv.size(); ++n;
    if(m>=n)return;
    iv.resize(n),fac.resize(n),ifac.resize(n);
    For(i,m,n-1){
        iv[i]=iv[mod%i]*(mod-mod/i);
        fac[i]=fac[i-1]*i,ifac[i]=ifac[i-1]*iv[i];
    }
}
inline modint C(int n,int m){
    if(m<0||n<m)return 0;
    return initC(n),fac[n]*ifac[m]*ifac[n-m];
}
inline modint sign(int n){return (n&1)?(mod-1):(1);}
  
#define fi first
#define se second
#define pb push_back
#define mkp make_pair
typedef pair<int,int>pii;
typedef vector<int>vi;
  
#define maxn 10000005
#define inf 0x3f3f3f3f
  
int n,m,g;
bool vis[maxn];
int pri[maxn],tot,phi[maxn],mnp[maxn];
void prework(int n)
{
    vis[1]=1;phi[1]=1;
    For(i,2,n){
        if(!vis[i])pri[++tot]=i,phi[i]=i-1,mnp[i]=i;
        For(j,1,tot){
            if(i*pri[j]>n)break;
            int x=i*pri[j];
            vis[x]=1; mnp[x]=pri[j];
            if(i%pri[j])phi[x]=phi[i]*(pri[j]-1);
            else {phi[x]=phi[i]*pri[j];break;}
        }
    }
}
  
int p[233333],pc[233333],cnt;
void getfac(int n){
    cnt=0;
    while(n>1){
        int i=mnp[n];
        p[++cnt]=i;pc[cnt]=0;
        while(n%i==0)n/=i,pc[cnt]++;
    }
}
  
modint res=0;
  
modint calc(int x)
{
    int n=::n/x;
    int m=::m/x;
   //  cout<<x<<" "<<phi[x]<<' '<<(C(n-1,m-1) - C(n-(n+1)/2,m-1)*m).x<<endl;
    if(x>1) return C(n-1,m-1);
    return C(n-1,m-1) - C(n-(n+1)/2,m-1)*m;
}
  
void dfs(int u,int now)
{
    if(u==cnt+1) return res+=phi[now]*calc(now),void();
    dfs(u+1,now);
    For(i,1,pc[u]) now*=p[u],dfs(u+1,now);
}
  
void work()
{
    n=read(),m=read(),g=__gcd(n,m);
    getfac(g);
    res=0;
    dfs(1,1);
//   cout<<"res "<<res.x<<endl;
    if(m%2==0){
        int lim=(n-1)/2;
        for(int i=0;i<=n;i+=2){
            int dan=n-i;
            int L=max(1,dan-lim);
            int R=min(lim,dan-1);
            if(L>R)continue;
            int tmp=R-L+1;
            res+=(m/2)*C(i/2-1,m/2-2)*tmp;
        }
        if(n%2==0)res+=C(n/2-1,m/2-1)*(m/2);
    }else{
        For(i,1,(n-1)/2)
            if((n-i)%2==0)res+=C((n-i)/2-1,m/2-1)*m;
    }
    res/=(2*m);
    printf("%d\n",res.x);
}
  
/*
9 3
5 3
  
2 3 4 (6)
1 4 4 (3)
3 3 3 (1)
  
2 3 4
3 2 4
1 4 4
3 3 3
  
2 3 4
  
*/
  
signed main()
{
    prework(1e7);
    initC(1e7);
    ;int T=read();
    while(T--)work();
    return 0;
}
  
/*
.... .... ....
*/
  
/*
  
$n,m$
  
$ C(n-1,m-1) - \sum_{i=(n+1)/2}^{n-(m-1)} C(n-i-1,m-2)*m $
  
$ C(n-1,m-1) - m * C()$
  
*/ 

詳細信息

Test #1:

score: 100
Accepted
time: 198ms
memory: 213320kb

input:

4
3 3
4 3
5 3
7 4

output:

1
0
1
3

result:

ok 4 tokens

Test #2:

score: -100
Time Limit Exceeded

input:

10000
8708700 6531525
8062080 4031040
7068600 2356200
3659040 332640
7309575 2088450
5503680 1572480
7162848 3581424
9831360 7724640
6306300 5045040
5783400 2891700
4677120 2338560
5110560 786240
9525600 2381400
6955200 4173120
8229375 3291750
7068600 5405400
9639000 3213000
5969040 2984520
5274360 ...

output:


result: