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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#150757#6349. Is This FFT?275307894aTL 1ms3768kbC++141.5kb2023-08-26 08:12:232023-08-26 08:12:26

Judging History

你现在查看的是最新测评结果

  • [2023-08-26 08:12:26]
  • 评测
  • 测评结果:TL
  • 用时:1ms
  • 内存:3768kb
  • [2023-08-26 08:12:23]
  • 提交

answer

#include<bits/stdc++.h>
#define Gc() getchar() 
#define Me(x,y) memset(x,y,sizeof(x))
#define Mc(x,y) memcpy(x,y,sizeof(x))
#define d(x,y) ((m)*(x-1)+(y))
#define R(n) (rnd()%(n)+1)
#define Pc(x) putchar(x)
#define LB lower_bound
#define UB upper_bound
#define fi first
#define se second
using namespace std;using ll=long long;using db=double;using lb=long db;using ui=unsigned;using ull=unsigned long long;using pii=pair<int,int>;using LL=__int128;
const int N=250+5,M=N*N+5,K=14348907+5,mod=998244353,Mod=mod-1;const db eps=1e-9;const ll INF=1e18+7;mt19937 rnd(time(0));
int n,p,k;ll f[N][M],g[M],frc[N],inv[N];
ll C(int x,int y){return frc[x]*inv[y]%p*inv[x-y]%p;}
void Solve(){
	int i,j,h;scanf("%d%d",&n,&p);k=max(n,n*(n-1)/2);
	inv[1]=1;for(i=2;i<=k;i++) inv[i]=(p-inv[p%i])*(p/i)%p;
	for(frc[0]=inv[0]=i=1;i<=k;i++) frc[i]=frc[i-1]*i%p,inv[i]=inv[i-1]*inv[i]%p;
	f[1][0]=1;
	for(i=2;i<=n;i++){
		int l=i*(i-1)/2;
		for(j=1;j<i;j++){
			fill(g+1,g+l+1,0);
			int l1=j*(j-1)/2,l2=(i-j)*(i-j-1)/2;
			for(int x=0;x<=l1;x++){
				for(int y=0;y<=l2;y++) g[x+y+1]+=f[j][x]*f[i-j][y]%p*C(x+y,x)%p*C(l-j*(i-j)-x-y,l1-x)%p;
			} 
			for(h=0;h<=l;h++) f[i][h]=(f[i][h]+g[h]%p*frc[j*(i-j)-1]%p*C(l-h,j*(i-j)-1))%p;
		}
		for(j=1;j<=l;j++) f[i][j]=(f[i][j]+f[i][j-1])%p;
	}
	for(i=2;i<=n;i++) printf("%lld\n",f[i][i*(i-1)/2]*inv[i*(i-1)/2]%p*(i^1?frc[i]*(p+1)/2%p:1)%p);
}
int main(){
	int t;
	// scanf("%d",&t);
	t=1;
	while(t--) Solve();
	cerr<<clock()*1.0/CLOCKS_PER_SEC<<'\n';
}

Details

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Test #1:

score: 100
Accepted
time: 1ms
memory: 3768kb

input:

10 998244353

output:

1
1
532396989
328786831
443364983
567813846
34567523
466373946
474334062

result:

ok 9 numbers

Test #2:

score: -100
Time Limit Exceeded

input:

250 998244353

output:


result: