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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#149542#5460. Sum of NumbersinvernoTL 3ms6588kbC++142.0kb2023-08-24 20:04:182023-08-24 20:04:20

Judging History

你现在查看的是最新测评结果

  • [2023-08-24 20:04:20]
  • 评测
  • 测评结果:TL
  • 用时:3ms
  • 内存:6588kb
  • [2023-08-24 20:04:18]
  • 提交

answer

#include<bits/stdc++.h>

using namespace std;

const int N = 200050;
struct big{
    int n;
    short a[N];
}ans, nw;
bool inti = 1;
int n, k; 
string st;

big operator + (big a, big b) {
    int m = max(a.n, b.n);
    big c;
    c.n = m;
    c.a[1] = 0;
    for (int i = a.n + 1;i <= m;++ i) a.a[i] = 0;
    for (int i = b.n + 1;i <= m;++ i) b.a[i] = 0;
    for (int i = 1;i <= m;++ i) {
        c.a[i + 1] = 0;
        c.a[i] += a.a[i] + b.a[i];
        if (c.a[i] > 9) {
            c.a[i] -= 10;
            c.a[i+1] ++ ;
        }
    }
    if (c.a[m + 1] != 0) ++ c.n;
    return c;
}
bool operator < (big &a, big &b) {
    if (a.n != b.n) {
        return a.n < b.n;
    }
    for (int i = a.n;i >= 1;-- i) {
        if (a.a[i] != b.a[i]) 
            return (a.a[i] < b.a[i]);
    }
    return false;
}

big cp(int x, int y) {
    big c;
    c.n = 0;
    for (int i = y;i >= x;-- i) {
        c.a[++c.n] = st[i - 1] - '0';
    }
    return c;
}

void dfs(int d, int j, big nw, int len) {
    if (d == k) {
        if (abs(n - j + 1 - len) > 1) return;
        big nw2 = cp(j, n);
        nw = nw + nw2;
        
        if (inti || nw < ans) {
            ans = nw;
            inti = false;
        }
        return ;
    }
    if (j > n) return;
    for (int h = -1;h <= 1;++ h){
      int i = h + len; 
      if (i <= 0) continue;
      big nw2 = nw + cp(j,j + i - 1); //!!!
      if (j + i <= n + 1)
        dfs(d + 1, j + i, nw2, i);
    }
    return;
}

int main(){
    ios::sync_with_stdio(false); cin.tie(0);
    
    int tcase = 0;
    cin >> tcase;
    while (tcase --) {
      inti = 1;
      
      cin >> n >> k;
      ++ k;
      cin >> st;
      int L = max((int)((double)2 * n / k - (k - 1))/2,1);
      int R = min(L + k - 1, n);
      for (int i = L;i <= R;++ i) 
        dfs(2, i + 1, nw = cp(1,i), i);

      for (int i = ans.n;i >= 1;-- i) cout << ans.a[i];
      cout << endl;
    }
    return 0;
}


詳細信息

Test #1:

score: 100
Accepted
time: 3ms
memory: 6588kb

input:

2
8 1
45455151
2 1
42

output:

9696
6

result:

ok 2 lines

Test #2:

score: -100
Time Limit Exceeded

input:

10
1301 6
56328399613959594774559774218276494124991536454496431869449134772679831477279356599352619469813771742358572734317965823527349354276551857226632977613336815474383422853946661428822284645652423563864641261338984158269966469425994769486371736593879954275146732544891889693921182364554588732946...

output:

2861837555106640794797067737879913860686764066159587941287350938727749577629356630565034353414526438507603808735990935008225192080065174423508575377930722196909797866802717925250679901255
1330897896655974774035586406544907434842835048336411271110427836483063457950873824562288934364096546537492367401...

result: