QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#149170#5422. Perfect PalindromeJadeReaperAC ✓2ms4048kbC++23894b2023-08-24 06:05:452023-08-24 06:05:48

Judging History

你现在查看的是最新测评结果

  • [2023-08-24 06:05:48]
  • 评测
  • 测评结果:AC
  • 用时:2ms
  • 内存:4048kb
  • [2023-08-24 06:05:45]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;

const int MOD = 1e9 + 7;
using ll = long long;
using dbl = long double;
// #define int ll

using pii = pair<int, int>;
using vi = vector<int>;
using vvi = vector<vi>;
using vii = vector<pii>;
using vvii = vector<vii>;
using vll = vector<ll>;

#define ff first
#define ss second
#define pb push_back
#define rep(i, a, b) for (int i = a; i < (b); ++i)
#define all(x) begin(x), end(x)
#define sz(x) (int)(x).size()
#define tc    \
    int t;    \
    cin >> t; \
    while (t--)
#define fightFight cin.tie(0)->sync_with_stdio(0)

void solve() {
    string s;
    cin >> s;
    const int N = 26;
    vi freq(N, 0);
    for (auto &i : s) freq[i - 'a']++;
    int best = sz(s);
    for (auto &i : freq) best = min(best, sz(s) - i);
    cout << best << "\n";
}

signed main() {
    fightFight;
    tc solve();
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 1ms
memory: 3768kb

input:

2
abcb
xxx

output:

2
0

result:

ok 2 number(s): "2 0"

Test #2:

score: 0
Accepted
time: 2ms
memory: 4048kb

input:

11107
lfpbavjsm
pdtlkfwn
fmb
hptdswsoul
bhyjhp
pscfliuqn
nej
nxolzbd
z
clzb
zqomviosz
u
ek
vco
oymonrq
rjd
ktsqti
mdcvserv
x
birnpfu
gsgk
ftchwlm
bzqgar
ovj
nsgiegk
dbolme
nvr
rpsc
fprodu
eqtidwto
j
qty
o
jknssmabwl
qjfv
wrd
aa
ejsf
i
npmmhkef
dzvyon
p
zww
dp
ru
qmwm
sc
wnnjyoepxo
hc
opvfepiko
inuxx...

output:

8
7
2
8
4
8
2
6
0
3
7
0
1
2
5
2
4
6
0
6
2
6
5
2
5
5
2
3
5
6
0
2
0
8
3
2
0
3
0
6
5
0
1
1
1
2
1
8
1
7
5
3
4
4
1
8
5
5
8
8
6
3
0
2
3
2
1
5
0
0
9
3
3
4
8
4
0
4
2
6
6
0
8
7
4
3
9
3
4
2
5
8
8
8
6
1
4
4
2
7
2
8
6
4
4
8
7
8
4
9
3
8
0
7
7
2
6
0
0
5
4
0
7
5
4
2
1
6
7
5
2
4
4
7
3
3
2
5
4
8
5
0
3
5
1
2
3
0
4
7
...

result:

ok 11107 numbers