QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#142912#4564. Digital CircuitAPROHACK0 2ms27596kbC++202.8kb2023-08-20 02:34:142023-08-20 02:34:15

Judging History

你现在查看的是最新测评结果

  • [2023-08-20 02:34:15]
  • 评测
  • 测评结果:0
  • 用时:2ms
  • 内存:27596kb
  • [2023-08-20 02:34:14]
  • 提交

answer

#include "circuit.h"
#include <cstring>
#include <vector>
#include <cassert>
#define ll long long
#define ff first
#define ss second
#define pb push_back
using namespace std;
int n, m;
vector<int>child[200001];
bool state[200001];
ll encen[200001][2]; // encendido y apagado
const int MOD = 1000002022;
int past[2002][2002];
void generate(int node);
int parent[200002];
bool casito = true;
void init(int N, int M, std::vector<int> P, std::vector<int> A) {
	n = N;
	m = M;
	if( m != n+1 )casito = false;
	for(int i = 0 ; i < n+m ; i ++){
		if(P[i] != -1){
			child[P[i]].pb(i);
			if(P[i] != (i-1)/2)casito = false;
		}
		parent[i] = P[i];
	}
	int temp = m;
	while(temp != 1){
		if(temp % 2 == 1)casito = false;
		temp /= 2;
	}
	//assert(casito);
	for(int i = N ; i <= N+M ; i ++)state[i] = A[i-N];
	memset(past, -1, sizeof past);
	generate(0);
}

ll mem[2002][2002];
int currentIt = -1;

void newDp(){
	currentIt++;
}
ll dp(int parent, int i, int k){
	if(k < 0)return 0;
	if(i == child[parent].size() and k > 0)return 0;
	else if(i == child[parent].size()) return 1;
	if(past[i][k] == currentIt)return mem[i][k];
	past[i][k] = currentIt;
	return mem[i][k] = (dp(parent, i+1, k-1) * encen[child[parent][i]][0] + dp(parent, i+1, k) * encen[child[parent][i]][1])%MOD;
}

void generate(int node){
	if(node >= n){
		if(state[node]){
			encen[node][0] = 1;
			encen[node][1] = 0;
		}else{
			encen[node][0] = 0;
			encen[node][1] = 1;
		}
		return ;
	}
	for(int i = 0 ; i < child[node].size() ; i ++){
		generate(child[node][i]);
	}
	newDp();
	ll enc = 0;
	for(int i = 1 ; i <= child[node].size() ; i ++){
		enc += dp(node, 0, i) * i;
		enc %= MOD;
	}
	ll allWays = 1;
	for(int i = 0 ; i < child[node].size() ; i ++){
		allWays *= (encen[child[node][i]][0] + encen[child[node][i]][1]);
		allWays %= MOD;
	}
	allWays *= child[node].size();
	allWays %= MOD;
	encen[node][0] = enc;
	encen[node][1] = ((allWays - enc) + MOD) % MOD;
	//cout << "for node " << node << " there are " << encen[node][0] << ", " << encen[node][1] << "\n";
}
void recargar(int node){
	if(node >= n){
		if(state[node]){
			encen[node][0] = 1;
			encen[node][1] = 0;
		}else{
			encen[node][0] = 0;
			encen[node][1] = 1;
		}
		return ;
	}
	newDp();
	ll enc = 0;
	for(int i = 1 ; i <= child[node].size() ; i ++){
		enc += dp(node, 0, i) * i;
		enc %= MOD;
	}
	ll allWays = 1;
	for(int i = 0 ; i < child[node].size() ; i ++){
		allWays *= (encen[child[node][i]][0] + encen[child[node][i]][1]);
		allWays %= MOD;
	}
	allWays *= child[node].size();
	allWays %= MOD;
	encen[node][0] = enc;
	encen[node][1] = ((allWays - enc) + MOD) % MOD;
	if(parent[node] != -1)recargar(parent[node]);
}

int count_ways(int L, int R) {
	for(int i = L ; i <= R ; i ++){
		state[i] = !state[i];
	}
	if(L == R and casito and n <= 1000 and m <= 1000)recargar(L);
	else generate(0);
	return encen[0][0];
}

詳細信息

Subtask #1:

score: 0
Wrong Answer

Test #1:

score: 0
Wrong Answer
time: 2ms
memory: 26856kb

input:

1 2
-1 0 0
0 0
1 1
2 2
1 2
2 2
1 2
-1 -1
-2 -2

output:

0
0
0
0
1

result:

wrong answer 3rd lines differ - expected: '1', found: '0'

Subtask #2:

score: 0
Wrong Answer

Test #9:

score: 0
Wrong Answer
time: 1ms
memory: 27596kb

input:

1 2
-1 0 0
0 0
1 1
2 2
1 2
2 2
1 2
-1 -1
-2 -2

output:

0
0
0
0
1

result:

wrong answer 3rd lines differ - expected: '1', found: '0'

Subtask #3:

score: 0
Skipped

Dependency #1:

0%

Subtask #4:

score: 0
Time Limit Exceeded

Test #43:

score: 0
Time Limit Exceeded

input:

32767 32768
-1 0 0 1 1 2 2 3 3 4 4 5 5 6 6 7 7 8 8 9 9 10 10 11 11 12 12 13 13 14 14 15 15 16 16 17 17 18 18 19 19 20 20 21 21 22 22 23 23 24 24 25 25 26 26 27 27 28 28 29 29 30 30 31 31 32 32 33 33 34 34 35 35 36 36 37 37 38 38 39 39 40 40 41 41 42 42 43 43 44 44 45 45 46 46 47 47 48 48 49 49 50 50...

output:

431985922
394586018
431985922
469385826
506785730
469385826
431985922
469385826
431985922
469385826
506785730
469385826
431985922
394586018
357186114
319786210
357186114
394586018
431985922
394586018
357186114
394586018
431985922
469385826
506785730
469385826
431985922
394586018
357186114
319786210
...

result:


Subtask #5:

score: 0
Skipped

Dependency #4:

0%

Subtask #6:

score: 0
Skipped

Dependency #2:

0%

Subtask #7:

score: 0
Skipped

Dependency #3:

0%

Subtask #8:

score: 0
Skipped

Dependency #1:

0%