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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#142471 | #4918. 染色 | heyangyang | 0 | 0ms | 0kb | C++14 | 5.5kb | 2023-08-19 08:05:18 | 2023-08-19 08:05:21 |
answer
#include<bits/stdc++.h>
#define LL long long
#define eb emplace_back
#define IN inline
using namespace std;
const int N = 3e5 + 5;
int n, m;
IN LL read() {
LL t = 0,res = 0; char ch = getchar();
for (; !isdigit(ch); ch = getchar()) t |= (ch == '-');
for (; isdigit(ch); ch = getchar()) res = (res << 3) + (res << 1) + (ch ^ 48);
return t ? -res : res;
}
#define UL unsigned long long
struct nd{int z, c;}mn[N << 2];
UL sum[N << 2], tag[2][N << 2];
set<int> f[N << 2];
void getplus(int l, int r, int k, UL z, int fl) {
if (fl == 0) tag[0][k] += z, sum[k] += (UL)mn[k].c * z;
else tag[1][k] += z, sum[k] += (UL)(r - l + 1) * z;
}
void pushdown(int k, int l, int r) {
// if (tag[0][k] != 0 || tag[1][k] != 0)
// printf("%d %d %llu %llu\n", l, r, tag[0][k], tag[1][k]);
if (tag[0][k] != 0) {
int z = *(f[k].lower_bound(0));
// printf("%d %d %d %d\n",z,mn[k].z,l,r);
if (z == mn[k].z) tag[1][k] += tag[0][k];
else {
int mid = l + r >> 1;
// printf("%d %d %d\n", z, mn[k << 1].z, mn[k << 1 | 1].z);
if (mn[k << 1].z == mn[k].z) getplus(l, mid, k << 1, tag[0][k], 0);
if (mn[k << 1 | 1].z == mn[k].z) getplus(mid + 1, r, k << 1 | 1, tag[0][k], 0);
}
tag[0][k] = 0;
}
if (tag[1][k] != 0) {
int mid = l + r >> 1;
getplus(l, mid, k << 1, tag[1][k], 1);
getplus(mid + 1, r, k << 1 | 1, tag[1][k], 1);
tag[1][k] = 0;
}
}
nd Min(nd x, nd y) {
if (x.z < y.z) return x;
if (x.z == y.z) return nd{x.z, x.c + y.c};
if (x.z > y.z) return y;
}
void pushup(int k, int l, int r, int fl) {
mn[k] = nd{(int)1e9, 0};
if (l ^ r) mn[k] = Min(mn[k], mn[k << 1]), mn[k] = Min(mn[k], mn[k << 1 | 1]);
int z = *(f[k].lower_bound(0));
if (mn[k].z > z) mn[k] = nd{z, r - l + 1};
if (fl) sum[k] = sum[k << 1] + sum[k << 1 | 1];
}
void update(int l, int r, int k, int L, int R, int x, int fl) {
if (L > R) return;
if (L <= l && r <= R) {
if (fl == 1) f[k].insert(x); else f[k].erase(x);
pushup(k, l, r, 0);
return;
}
int mid = l + r >> 1; pushdown(k, l, r);
if (L <= mid) update(l, mid, k << 1, L, R, x, fl);
if (R > mid) update(mid + 1, r, k << 1 | 1, L, R, x, fl);
pushup(k, l, r, 1);
}
void addmn(int l, int r, int k, int L, int R, int z, UL v, int mz) {
if (L <= l && r <= R) {
// printf("%d %d %d %d\n", l, r, min(mz, mn[k].z), z);
if (min(mz, mn[k].z) == z) getplus(l, r, k, v, 0);
return;
}
int mid = l + r >> 1, val = *(f[k].lower_bound(0)); pushdown(k, l, r);
if (L <= mid) addmn(l, mid, k << 1, L, R, z, v, min(mz, val));
if (R > mid) addmn(mid + 1, r, k << 1 | 1, L, R, z, v, min(mz, val));
pushup(k, l, r, 1);
}
int getmn(int l, int r, int k, int L, int R) {
if (L <= l && r <= R) return mn[k].z;
int mid = l + r >> 1, res = *(f[k].lower_bound(0)); pushdown(k, l, r);
if (L <= mid) res = min(res, getmn(l, mid, k << 1, L, R));
if (R > mid) res = min(res, getmn(mid + 1, r, k << 1 | 1, L, R));
return res;
}
UL query(int l, int r, int k, int L, int R) {
if (L <= l && r <= R) return sum[k];
int mid = l + r >> 1; UL res = 0; pushdown(k, l, r);
if (L <= mid) res = query(l, mid, k << 1, L, R);
if (R > mid) res += query(mid + 1, r, k << 1 | 1, L, R);
return res;
}
struct odt{
int l, r, z;
friend bool operator < (odt x, odt y){return x.r < y.r;}
};
set<odt> T[N];
void split(int id, int x, int fl, int z) {
auto it = T[id].lower_bound(odt{0, x, 0});
int cor = it->z, l = it->l, r = it->r;
// printf("ff %d %d %d %d\n", x, l, r, cor);
if (cor == 0) {
update(1, n, 1, l, r, id, -1);
if (fl == 1) update(1, n, 1, x + 1, r, id, 1);
else update(1, n, 1, l, x - 1, id, 1);
}
T[id].erase(it);
if (fl == 1) {
if (x < r) T[id].insert(odt{x + 1, r, cor});
T[id].insert(odt{l, x, cor});
}
else {
if (l < x) T[id].insert(odt{l, x - 1, cor});
T[id].insert(odt{x, r, cor});
}
}
void prf(int l, int r, int k) {
// printf("%d %d\n",l,r);
// for (auto i = f[k].begin(); i != f[k].end(); i++)
// printf("%d ", *i);
// puts("");
if (l == r) return;
int mid = l + r >> 1;
prf(l, mid, k << 1), prf(mid + 1, r, k << 1 | 1);
}
void change(int id, int l, int r, int z) {
split(id, r, 1, z), split(id, l, 0, z);
// puts("ff");
auto itl = T[id].lower_bound(odt{0, l, 0}), itr = T[id].lower_bound(odt{0, r, 0});
// printf("%d %d %d %d %d %d\n",itl->l,itl->r,itl->z,itr->l,itr->r,itr->z);
for (auto i = itl; i != itr; i++) {
if (i == itl || i == itr) continue;
if (i->z == 0) update(1, n, 1, i->l, i->r, id, -1);
}
if (z == 0) update(1, n, 1, l, r, id, 1);
puts("");
prf(1, n, 1);
// printf("%d %d %d\n",l,r,z);
itr++, T[id].erase(itl, itr);
T[id].insert(odt{l, r, z});
// puts("2set");
// for (auto i = T[2].begin(); i != T[2].end(); i++)
// printf("%d %d %d\n",i->l,i->r,i->z);
}
void build(int l, int r, int k) {
mn[k] = nd{(int)1e9, r - l + 1}, f[k].insert((int)1e9);
if (l == r) return; int mid = l + r >> 1;
build(l, mid, k << 1), build(mid + 1, r, k << 1 | 1);
}
int main() {
freopen("paint.in", "r", stdin);
// freopen("paint.out", "w", stdout);
n = read(), m = read(), build(1, n, 1), mn[1] = nd{1, n};
for (int i = 1; i <= m; i++) f[1].insert(i), T[i].insert(odt{1, n, 0});
for (int i = 1; i <= m; i++) {
int opt = read(), l = read(), r = read(); LL x;
if (opt == 1) x = read(), change(x, l, r, 1);
if (opt == 2) x = read(), change(x, l, r, 0);
if (opt == 3) {
x = read();
int z = getmn(1, n, 1, l, r);
// printf("ff %d\n", z);
addmn(1, n, 1, l, r, z, x, (int)1e9);
}
if (opt == 4) {
UL ans = query(1, n, 1, l, r);
printf("%llu\n", ans);
}
}
}
详细
Subtask #1:
score: 0
Time Limit Exceeded
Test #1:
score: 0
Time Limit Exceeded
input:
1000 1000 3 722 914 2141556875752121755 3 323 347 6433743606947304931 2 142 206 439 2 117 840 195 2 127 502 56 3 168 707 15142638115094015116 4 190 257 2 88 976 475 1 319 867 351 1 682 889 409 2 406 446 196 3 28 35 4899387534800369959 2 291 546 150 1 528 617 128 1 58 122 251 2 381 400 276 4 510 958 ...
output:
result:
Subtask #2:
score: 0
Time Limit Exceeded
Test #11:
score: 0
Time Limit Exceeded
input:
300000 300000 1 237576 237663 1 3 16150 16208 9270412155482010138 2 175648 175692 1 4 190836 190849 4 199010 199097 1 73976 298801 1 3 89902 89939 6418828085116455990 3 55415 55461 12238963685511262676 3 119825 119875 8146944792877919309 3 135103 135158 218634681842812119 3 127261 127352 13291431184...
output:
result:
Subtask #3:
score: 0
Skipped
Dependency #2:
0%
Subtask #4:
score: 0
Time Limit Exceeded
Test #31:
score: 0
Time Limit Exceeded
input:
300000 300000 1 85444 86076 59 1 41150 41411 71 1 278698 279414 45 1 238445 239202 56 1 29965 29984 49 1 282953 283272 37 1 34668 35653 86 2 198587 198744 28 1 270855 271611 58 1 2130 2965 773 1 161601 162298 937 1 50299 50435 36 1 100759 101198 64 1 120208 120543 84 1 295293 295732 34 1 112185 1129...
output:
result:
Subtask #5:
score: 0
Skipped
Dependency #1:
0%
Subtask #6:
score: 0
Skipped
Dependency #1:
0%