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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#141503 | #6534. Peg Solitaire | cy1999 | TL | 0ms | 3744kb | C++20 | 1.3kb | 2023-08-17 15:30:06 | 2023-08-17 15:30:10 |
Judging History
answer
#include<cstdio>
#include<iostream>
#include<algorithm>
#include<cstring>
#include<vector>
using namespace std;
int t, n, m, k, ans = 7777;
int state[7][7];
void dfs(int a[][7]) {
//中嘞,哥
int tmp = 0;
for(int i=1; i<=n; i++) {
for(int j=1; j<=m; j++) {
//对于这个点(i, j),能不能跳ww
if(i<=n-2&&a[i][j]&&a[i+1][j]&&!a[i+2][j]) {
a[i][j] = a[i+1][j] = 0;
a[i+2][j] = 1;
dfs(a);
a[i][j] = a[i+1][j] = 1;
a[i+2][j] = 0;
}
if(i>=3&&a[i][j]&&a[i-1][j]&&!a[i-2][j]) {
a[i][j] = a[i-1][j] = 0;
a[i-2][j] = 1;
dfs(a);
a[i][j] = a[i-1][j] = 1;
a[i-2][j] = 0;
}
if(j>=3&&a[i][j]&&a[i][j-1]&&!a[i][j-2]) {
a[i][j] = a[i][j-1] = 0;
a[i][j-2] = 1;
dfs(a);
a[i][j] = a[i][j-1] = 1;
a[i][j-2] = 0;
}
if(j<=m-2&&a[i][j]&&a[i][j+1]&&!a[i][j+2]) {
a[i][j] = a[i][j+1] = 0;
a[i][j+2] = 1;
dfs(a);
a[i][j] = a[i][j+1] = 1;
a[i][j-2] = 0;
}
if(a[i][j]) tmp++;
}
}
ans = min(ans, tmp);
}
int main() {
//(顿住)
scanf("%d", &t);
while(t--) {
ans = 7777;
memset(state, 0, sizeof(state));
scanf("%d%d%d", &n, &m, &k);
for(int i=1; i<=k; i++) {
int x, y; scanf("%d%d", &x, &y);
state[x][y] = 1;
}
dfs(state);
cout<<ans<<endl;
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 3744kb
input:
3 3 4 5 2 2 1 2 1 4 3 4 1 1 1 3 3 1 1 1 2 1 3 2 1 1 2 1
output:
2 3 1
result:
ok 3 number(s): "2 3 1"
Test #2:
score: -100
Time Limit Exceeded
input:
20 2 1 2 1 1 2 1 5 1 3 3 1 2 1 4 1 3 3 6 1 2 2 2 1 1 2 3 3 1 3 2 4 4 4 2 3 3 1 3 2 1 2 1 1 1 1 1 5 2 6 3 2 4 1 2 1 5 2 2 2 5 1 1 3 1 1 2 1 5 1 1 5 4 6 5 4 6 4 4 2 3 4 3 1 6 6 6 3 2 4 1 3 2 1 2 2 2 2 1 1 1 5 3 4 2 2 5 1 4 3 3 2 6 5 6 5 5 6 5 2 4 2 1 3 4 1 4 2 6 5 1 6 2 1 1 4 2 3 1 3 3 5 6 2 1 3 3 1 5...
output:
2 2 3 1 1 2 1 1 3 3 2 1 3 3 2 1 3 1