QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#141289#6525. New Housescy1999TL 1ms5736kbC++142.3kb2023-08-17 10:20:422023-08-17 10:20:45

Judging History

你现在查看的是最新测评结果

  • [2023-08-17 10:20:45]
  • 评测
  • 测评结果:TL
  • 用时:1ms
  • 内存:5736kb
  • [2023-08-17 10:20:42]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
inline ll read() {
	   ll x = 0,f = 1;
	   char ch = getchar();
	   while(ch < '0' ||ch > '9') {
			if(ch == '-') f = -1;
			ch = getchar();
	   }
	   while(ch >= '0' && ch <= '9') {
			x = (x << 1) + (x << 3) + (ch ^ '0');
			ch = getchar();
	   }
	   return x * f;
}
const int N = 5e5 + 10;
int t, n, m;
struct person{
	ll x, y; bool flag;
}a[N], b[N];
bool cmp(person c, person d) {
	return c.y - c.x > d.y - d.x;
}
//!!!!!!!!!!注意,前面已经统计了答案了 
int main() {
	t = read();
	while (t--) { 
		n = read(), m = read(); ll ans = 0, arr = 0;
		for (int i = 1; i <= n; i++) {
			a[i].x = read(), a[i].y = read();
			if (a[i].x >= a[i].y) {
				ans += a[i].x, arr++, a[i].flag = 0;
			}
			else a[i].flag = 1;
		} 
		if (arr >= 2) {
			int tot = 0;
			for (int i = 1; i <= n; i++) {
				if (a[i].flag) b[++tot] = a[i];
			}
			sort(b + 1, b + tot + 1, cmp);
			//int las = m - arr; int k = n - arr;
			int sum = m - n;//las - k
			for (int i = 1; i <= tot ; i++) {
				if (sum > 0) {
					sum--; ans += b[i].y;
				} else {
					ans += b[i].x;
				}
			}
			printf("%lld\n",ans);
		} else if (arr == 0) {//!!!!!!!!!!!!!!!!!!!!!!!test
			int tot = 0; ans = 0;
			for (int i = 1; i <= n; i++) {
				b[++tot] = a[i];
			}
			sort(b + 1, b + tot + 1, cmp);
			//int las = m - arr; int k = n - arr;
			int sum = m - n;//las - k
			if (sum == n - 1) sum++;
			for (int i = 1; i <= tot ; i++) {
				if (sum > 0) {
					sum--; ans += b[i].y;
				} else {
					ans += b[i].x;
				}
			}
			printf("%lld\n",ans);
		} else {
			ans = 0;
			int tot = 0;
			for (int i = 1; i <= n; i++) {
				b[++tot] = a[i];
			}
			sort(b + 1, b + tot + 1, cmp);
			//int las = m - arr; int k = n - arr;
			int sum = m - n;//las - k
			if (sum == n - 1) sum++;
			for (int i = 1; i <= tot ; i++) {
				if (sum > 0) {
					sum--; ans += b[i].y;
				} else {
					ans += b[i].x;
				}
			} ll anss = ans;
			if(!((b[tot].x >= b[tot].y) && (b[tot-1].x < b[tot-1].y))) while(1);
			ans = b[tot].x + b[tot-1].x; tot -= 2;
			sum = m - n;
			for (int i = 1; i <= tot ; i++) {
				if (sum > 0) {
					sum--; ans += b[i].y;
				} else {
					ans += b[i].x;
				}
			} anss = max(anss, ans);
			printf("%lld\n",anss);
		}
		
	}
	return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 1ms
memory: 5736kb

input:

3
4 5
1 100
100 1
100 1
100 1
2 2
1 10
1 10
2 3
100 50
1 1000

output:

400
2
1050

result:

ok 3 number(s): "400 2 1050"

Test #2:

score: -100
Time Limit Exceeded

input:

100000
6 11
191141536 365120521
799679686 648574232
102602909 467685128
405440859 796808887
384858152 191995380
433392826 195648471
5 13
831367906 510447872
795639287 575551283
811207605 176441088
240156289 946977042
133416463 721098873
5 5
806744021 699586200
630510306 637827160
49223781 641709297
...

output:


result: