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QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#138917#4426. Divided Mechanismckiseki#AC ✓3ms3544kbC++172.2kb2023-08-12 14:14:302023-08-12 14:14:33

Judging History

你现在查看的是最新测评结果

  • [2023-08-12 14:14:33]
  • 评测
  • 测评结果:AC
  • 用时:3ms
  • 内存:3544kb
  • [2023-08-12 14:14:30]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;

#define all(x) begin(x), end(x)
#ifdef CKISEKI
#define safe cerr << __PRETTY_FUNCTION__ << " line " << __LINE__ << " safe\n"
#define debug(a...) debug_(#a, a)
#define orange(a...) orange_(#a, a)
template <typename ...T>
void debug_(const char *s, T ...a) {
    cerr << "\e[1;32m(" << s << ") = (";
    int cnt = sizeof...(T);
    (..., (cerr << a << (--cnt ? ", " : ")\e[0m\n")));
}
template <typename I>
void orange_(const char *s, I L, I R) {
    cerr << "\e[1;32m[ " << s << " ] = [ ";
    for (int f = 0; L != R; ++L)
        cerr << (f++ ? ", " : "") << *L;
    cerr << " ]\e[0m\n";
}
#else
#define safe ((void)0)
#define debug(...) safe
#define orange(...) safe
#endif

int dx[256], dy[256];

void solve() {
    int n, m, k;
    cin >> n >> m >> k;

    vector<pair<int,int>> A, B;
    for (int i = 0; i < n; i++) {
        string g;
        cin >> g;
        for (int j = 0; j < m; j++) {
            if (g[j] == 'A') {
                A.emplace_back(i, j);
            } else if (g[j] == 'B') {
                B.emplace_back(i, j);
            }
        }
    }

    vector<vector<int>> G(n * 2, vector<int>(m * 2));
    for (int i = 0; i < n * 2; i++) {
        orange(all(G[i]));
    }

    for (auto [x1, y1]: A) {
        for (auto [x2, y2]: B) {
            G[x1 - x2 + n][y1 - y2 + m] = true;
        }
    }

    string s;
    cin >> s;

    int x = n, y = m;
    assert (G[x][y] == false);

    for (int i = 0; i < n * 2; i++) {
        orange(all(G[i]));
    }

    const auto ok = [&](int x, int y) {
        return x >= 0 && x < n * 2 && y >= 0 && y < m * 2;
    };
    for (char c: s) {
        int DX = dx[c], DY = dy[c];
        debug(DX, DY, c);
        while (ok(x, y) && (!ok(x+DX, y+DY) || G[x+DX][y+DY] == false)) {
            x += DX;
            y += DY;
        }
        if (x < 0 || x >= n * 2 || y < 0 || y >= m * 2) {
            cout << "TAK\n";
            return;
        }
    }
    debug(x, y);

    cout << "NIE\n";

}

int main() {
    cin.tie(nullptr)->sync_with_stdio(false);

    dx['S'] = 1;
    dy['S'] = 0;
    dx['N'] = -1;
    dy['N'] = 0;

    dx['E'] = 0;
    dy['E'] = 1;
    dx['W'] = 0;
    dy['W'] = -1;

    int T;
    cin >> T;
    while (T--)
        solve();

    return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 3ms
memory: 3544kb

input:

1000
10 9 4
AA...AAAA
A......AA
A..BBB..A
A...B...A
A...B...A
AA..BBAAA
A..BB...A
A......AA
A...AAAAA
AAAAAAAAA
WSEN
9 10 4
AAAAAAAAAA
A...A....A
A.........
A..B...B..
AA.BBBBB..
AA..B..B.A
AA..A....A
AAA.A...AA
AAAAAAAAAA
ESNE
9 10 7
AAAAAAAAAA
A...A....A
A.........
A..B...B..
AA.BBBBB..
AA..B..B.A...

output:

TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
NIE
NIE
NIE
NIE
NIE
NIE
NIE
NIE
NIE
NIE
NIE
NIE
NIE
NIE
NIE
NIE
NIE
NIE
NIE
NIE
NIE
NIE
NIE
NIE
NIE
NIE
NIE
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
TAK
...

result:

ok 1000 lines

Extra Test:

score: 0
Extra Test Passed