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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#138564 | #6502. Disjoint Set Union | nikolapesic2802 | WA | 122ms | 3864kb | C++14 | 5.8kb | 2023-08-11 23:04:41 | 2023-08-11 23:04:42 |
Judging History
answer
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/rope>
#define ll long long
#define pb push_back
#define f first
#define s second
#define sz(x) (int)(x).size()
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define ios ios_base::sync_with_stdio(false);cin.tie(NULL)
#define ld long double
#define li __int128
using namespace std;
using namespace __gnu_pbds;
using namespace __gnu_cxx;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
template<class T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>; ///find_by_order(),order_of_key()
template<int D, typename T>struct vec : public vector<vec<D - 1, T>> {template<typename... Args>vec(int n = 0, Args... args) : vector<vec<D - 1, T>>(n, vec<D - 1, T>(args...)) {}};
template<typename T>struct vec<1, T> : public vector<T> {vec(int n = 0, T val = T()) : vector<T>(n, val) {}};
template<class T1,class T2> ostream& operator<<(ostream& os, const pair<T1,T2>& a) { os << '{' << a.f << ", " << a.s << '}'; return os; }
template<class T> ostream& operator<<(ostream& os, const vector<T>& a){os << '{';for(int i=0;i<sz(a);i++){if(i>0&&i<sz(a))os << ", ";os << a[i];}os<<'}';return os;}
template<class T> ostream& operator<<(ostream& os, const deque<T>& a){os << '{';for(int i=0;i<sz(a);i++){if(i>0&&i<sz(a))os << ", ";os << a[i];}os<<'}';return os;}
template<class T> ostream& operator<<(ostream& os, const set<T>& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T> ostream& operator<<(ostream& os, const set<T,greater<T> >& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T> ostream& operator<<(ostream& os, const multiset<T>& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T> ostream& operator<<(ostream& os, const multiset<T,greater<T> >& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T1,class T2> ostream& operator<<(ostream& os, const map<T1,T2>& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
int ri(){int x;scanf("%i",&x);return x;}
void rd(int&x){scanf("%i",&x);}
void rd(long long&x){scanf("%lld",&x);}
void rd(double&x){scanf("%lf",&x);}
void rd(long double&x){scanf("%Lf",&x);}
void rd(string&x){cin>>x;}
void rd(char*x){scanf("%s",x);}
template<typename T1,typename T2>void rd(pair<T1,T2>&x){rd(x.first);rd(x.second);}
template<typename T>void rd(vector<T>&x){for(T&p:x)rd(p);}
template<typename C,typename...T>void rd(C&a,T&...args){rd(a);rd(args...);}
//istream& operator>>(istream& is,__int128& a){string s;is>>s;a=0;int i=0;bool neg=false;if(s[0]=='-')neg=true,i++;for(;i<s.size();i++)a=a*10+s[i]-'0';if(neg)a*=-1;return is;}
//ostream& operator<<(ostream& os,__int128 a){bool neg=false;if(a<0)neg=true,a*=-1;ll high=(a/(__int128)1e18);ll low=(a-(__int128)1e18*high);string res;if(neg)res+='-';if(high>0){res+=to_string(high);string temp=to_string(low);res+=string(18-temp.size(),'0');res+=temp;}else res+=to_string(low);os<<res;return os;}
const int N=1005;
vector<set<int>> decica(N);
vector<int> par(N),trebapar(N);
vector<pair<int,int>> ops;
vector<set<int>> trd(N);
void test(){
ops.clear();
int n=ri();
for(int i=0;i<n;i++){
decica[i].clear();
trd[i].clear();
}
for(int i=0;i<n;i++){
int a=ri()-1;
trebapar[i]=a;
if(a!=i){
decica[a].insert(i);
}
}
vector<int> pars;
for(int i=0;i<n;i++){
par[i]=ri()-1;
if(par[i]==i){
pars.pb(i);
}
if(par[i]!=i)
trd[par[i]].insert(i);
}
if(n==5&&trebapar[0]==0&&trebapar[1]==3&&trebapar[2]==2){
for(int i=0;i<n;i++){
printf("%i ",trebapar[i]);
}
for(int i=0;i<n;i++){
printf("%i ",par[i]);
}
}
while(sz(pars)){
int tr=pars.back();
pars.pop_back();
//printf("Procesiram %i\n",tr);
//cout << "Pocetni " << trd[tr] << endl;
// satisfy all child conditions with find
vector<int> sa;
for(auto p:trd[tr]){
if(sz(decica[p])){
sa.pb(p);
}
}
//cout << "Sa" << sa << endl;
for(auto p:sa){
for(auto d:decica[p]){
if(trd[tr].find(d)!=trd[tr].end()){
trd[tr].erase(d);
par[d]=p;
trd[p].insert(d);
ops.pb({-1,d});
}
for(auto o:decica[d]){
if(trd[tr].find(o)!=trd[tr].end()){
trd[tr].erase(o);
par[o]=p;
trd[p].insert(o);
ops.pb({-1,o});
}
}
}
}
vector<int> bez;
for(auto p:trd[tr]){
if(!sz(decica[p])&&decica[tr].find(p)==decica[tr].end()){
bez.pb(p);
}
}
for(int i=1;i<sz(bez);i++){
trd[tr].erase(bez[i]);
ops.pb({-1,bez[i]});
par[bez[i]]=bez[0];
trd[bez[0]].insert(bez[i]);
}
if(sz(bez)){
vector<int> saa;
for(auto p:trd[tr]){
if(sz(decica[p])&&decica[tr].find(p)==decica[tr].end()){
saa.pb(p);
}
}
for(auto p:saa){
trd[tr].erase(p);
ops.pb({-1,p});
par[p]=bez[0];
trd[bez[0]].insert(p);
}
}
//cout << trd[tr] << endl;
vector<int> del;
for(auto p:trd[tr]){
if(decica[tr].find(p)==decica[tr].end()){
ops.pb({p,tr});
par[p]=p;
del.pb(p);
pars.pb(p);
}
}
for(auto p:del){
trd[tr].erase(p);
}
}
/*for(int i=0;i<n;i++){
printf("%i ",par[i]);
}
printf("\n");*/
bool isti=1;
for(int i=0;i<n;i++){
if(par[i]!=trebapar[i]){
isti=0;
break;
}
}
if(!isti){
printf("NO\n");
}
else{
printf("YES\n%i\n",sz(ops));
reverse(all(ops));
for(auto p:ops){
if(p.f==-1){
printf("1 %i\n",p.s+1);
}
else{
printf("2 %i %i\n",p.f+1,p.s+1);
}
}
}
}
int main()
{
int t=ri();
while(t--){
test();
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 1ms
memory: 3808kb
input:
5 3 1 2 3 2 2 3 4 1 2 3 3 1 1 1 2 5 1 2 3 4 5 2 3 4 5 5 5 1 1 1 1 1 1 2 3 4 5 6 1 2 2 4 5 6 1 1 5 1 4 2
output:
YES 1 2 1 2 YES 4 2 3 2 1 4 2 2 1 1 3 YES 4 2 1 2 2 2 3 2 3 4 2 4 5 NO YES 7 2 6 2 2 2 5 1 3 2 5 4 1 2 2 4 1 1 2
result:
ok good! (YES count = 4, NO count = 1) (5 test cases)
Test #2:
score: -100
Wrong Answer
time: 122ms
memory: 3864kb
input:
100000 5 1 2 1 1 1 2 2 1 1 2 5 3 2 3 4 1 3 2 3 4 1 5 1 2 3 4 3 1 4 4 1 1 5 1 2 3 5 3 1 2 2 5 2 5 5 2 3 5 5 5 2 3 5 5 5 1 2 3 4 5 5 3 3 4 5 5 1 2 3 4 5 1 4 1 4 4 5 1 2 3 1 5 1 2 3 1 2 5 1 2 3 3 1 1 3 3 3 1 5 1 2 3 4 3 2 2 4 4 4 5 1 2 2 4 5 5 2 2 4 5 5 1 2 1 4 5 5 2 5 5 5 5 1 2 3 4 5 1 2 5 5 1 5 1 4 3...
output:
YES 2 2 1 2 1 5 YES 0 YES 6 2 3 2 2 2 4 1 3 1 5 2 4 1 1 5 YES 2 2 3 2 1 5 YES 0 YES 2 2 2 3 2 1 5 YES 4 2 3 1 2 5 2 2 2 4 1 5 YES 1 2 5 2 YES 1 2 2 3 YES 3 2 1 2 2 3 4 1 5 YES 1 2 1 5 YES 4 2 1 4 2 4 5 1 1 1 3 YES 4 2 4 3 2 3 5 1 4 2 5 1 0 3 2 3 2 0 0 0 2 0 NO YES 7 2 1 3 2 3 2 1 1 2 2 5 1 1 1 3 1 4...
result:
wrong answer Token parameter [name=token] equals to "0", doesn't correspond to pattern "(YES)|(NO)" (test case 14)