#include <bits/stdc++.h>
using namespace std;
#define SZ(a) (int)a.size()
#define ALL(a) a.begin(), a.end()
#define FOR(i, a, b) for (int i = (a); i<(b); ++i)
#define RFOR(i, b, a) for (int i = (b)-1; i>=(a); --i)
#define MP make_pair
#define PB push_back
#define F first
#define S second
#define FILL(a, b) memset(a, b, sizeof(a))
typedef long long LL;
typedef pair<int, int> PII;
typedef vector<int> VI;
string numb[7];
int a[7][21];
int b[7][21];
vector<vector<string>> v;
char ans[7][21];
VI st = {0, 5, 12, 17};
bool ok(int t, int n)
{
FOR (i, 0, n)
{
int h = t / 60;
int m = t % 60;
VI vec = {h / 10, h % 10, m / 10, m % 10};
FOR (j, 0, 7)
{
FOR (k, 0, 21)
{
if (a[j][k] != 3) continue;
int idx = upper_bound(ALL(st), k) - st.begin() - 1;
if (v[i][j][k] != numb[j][vec[idx] * 4 + k - st[idx]]) return false;
}
}
t++;
if (t >= 1440)
t = 0;
}
return true;
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(0);
numb[0] = ".XX......XX..XX......XX..XX..XX..XX..XX.";
numb[1] = "X..X...X...X...XX..XX...X......XX..X...X";
numb[2] = "X..X...X...X...XX..XX...X......XX..X...X";
numb[3] = ".XX......XX..XX..XX..XX..XX......XX..XX.";
numb[4] = "X..X...XX......X...X...XX..X...XX..X...X";
numb[5] = "X..X...XX......X...X...XX..X...XX..X...X";
numb[6] = ".XX......XX..XX......XX..XX......XX.....";
int n;
cin >> n;
v = vector<vector<string>>(n, vector<string>(7));
FOR (i, 0, n)
{
FOR (j, 0, 7)
{
cin >> v[i][j];
FOR (k, 0, 21)
a[j][k] |= (1 << (v[i][j][k] == 'X'));
}
}
int cnt = 0;
FOR (T, 0, 1440)
{
if (ok(T, n))
{
cnt++;
int t = T;
FOR (i, 0, n)
{
int h = t / 60;
int m = t % 60;
VI vec = {h / 10, h % 10, m / 10, m % 10};
FOR (idx, 0, 4)
{
FOR (j, 0, 7)
{
FOR (k, st[idx], st[idx] + 4)
{
if (numb[j][32 + k - st[idx]] == '.') continue;
b[j][k] |= (1 << (numb[j][vec[idx] * 4 + k - st[idx]] == 'X'));
}
}
}
t++;
if (t >= 1440)
t = 0;
}
}
}
if (cnt == 0)
{
cout << "impossible\n";
return 0;
}
FOR (j, 0, 7)
{
FOR (k, 0, 21)
{
ans[j][k] = '.';
}
}
FOR (idx, 0, 4)
{
FOR (j, 0, 7)
{
FOR (k, st[idx], st[idx] + 4)
{
if (numb[j][32 + k - st[idx]] == '.') continue;
if (a[j][k] == 3) ans[j][k] = 'W';
else
{
if (b[j][k] == 3) ans[j][k] = '?';
else if (v[0][j][k] == '.') ans[j][k] = '0';
else ans[j][k] = '1';
}
}
}
}
if ()
FOR (i, 0, 7)
{
FOR (j, 0, 21) cout << ans[i][j];
cout << '\n';
}
return 0;
}