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QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#137129#6347. XOR Determinantberarchegas#RE 2ms5544kbC++173.0kb2023-08-09 22:22:422023-08-09 22:22:46

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-08-09 22:22:46]
  • 评测
  • 测评结果:RE
  • 用时:2ms
  • 内存:5544kb
  • [2023-08-09 22:22:42]
  • 提交

answer

#include <algorithm>
#include <deque>
#include <iomanip>
#include <iostream>
#include <iterator>
#include <limits>
#include <map>
#include <numeric>
#include <queue>
#include <set>
#include <stack>
#include <string>
#include <utility>
#include <random>
#include <bits/stdc++.h>

using namespace std;
#define F first
#define S second
#define rep(i, a, b) for(int i = a; i < (b); ++i)
#define per(i, a, b) for(int i = b-1; i>=a ; i--)
#define trav(a, x) for(auto& a : x)
#define allin(a , x) for(auto a : x)
#define all(x) begin(x), end(x)
#define sz(x) (int)(x).size()
typedef long long ll;
typedef pair<int, int> pii;
typedef vector<ll> vl;
typedef vector<pii> vpi;
typedef pair<ll,ll> pll;
typedef vector<string> vs;
typedef vector<pll> vpl;
typedef vector<int> vi;

ll cdiv(ll a, ll b) { return a/b+((a^b)>0&&a%b); } // divide a by b rounded up
ll fdiv(ll a, ll b) { return a/b-((a^b)<0&&a%b); } // divide a by b rounded down

#define Unique(v) sort(all(v));v.erase(unique(all(v)),v.end());

const int maxn = 2*100000 + 10;

// const int inf = 1000000000;
// const ll inf = 1000000000000000000LL;

const ll mod = 998244353;
// const ll mod = 1000000007; // 10^9 + 7

int n;

ll b[maxn], c[maxn];

ll inv(ll v) { return v == 1 ? 1 : ( (mod - mod/v)*inv(mod%v) )%mod; }

ll det(vector< vector<ll> >& a)
{
    // int n = sz(a); double res = 1;
	// rep(i,0,n) {
	// 	int b = i;
	// 	rep(j,i+1,n) if (fabs(a[j][i]) > fabs(a[b][i])) b = j;
	// 	if (i != b) swap(a[i], a[b]), res *= -1;
	// 	res *= a[i][i];
	// 	if (res == 0) return 0;
	// 	rep(j,i+1,n) {
	// 		double v = a[j][i] / a[i][i];
	// 		if (v != 0) rep(k,i+1,n) a[j][k] -= v * a[i][k];
	// 	}
	// }
	// return res;

    ll res = 1;

    for(int i = 0 ; i < n ; i++)
    {
        int b = i;

        for(int j = i + 1 ; j < n ; j++)
            if( a[j][i] > a[b][i] ) b = j;

        if( i != b )
            swap( a[i] , a[b] ), res = mod - res;

        res *= a[i][i]; res %= mod;
        ll curInv = inv( a[i][i] );

        if( res == 0 )
            return 0;

        for(int j = i + 1 ; j < n ; j++)
        {
            ll v = a[j][i]*curInv; v %= mod;
            
            for(int k = i + 1 ; k < n && v != 0 ; k++)
            {
                a[j][k] -= v*a[i][k];

                a[j][k] %= mod;
                a[j][k] = (mod + a[j][k])%mod;
            }
        }
    }

    return res;
}

void solve(int testcase)
{
    cin >> n;

    for(int i = 1 ; i <= n ; i++)
        cin >> b[i];

    for(int i = 1 ; i <= n ; i++)
        cin >> c[i];

    if( n >= 70 )
    {
        cout << 0 << endl;
        return;
    }

    vector< vector<ll> > a(n, vector<ll>(n, 0));

    for(int i = 0 ; i < n ; i++)
        for(int j = 0 ; j < n ; j++)
            a[i][j] = (b[i + 1]^c[j + 1])%mod;

    cout << det(a) << endl;
}

int main()
{
    ios_base::sync_with_stdio(false);  
    cin.tie(NULL);

    int t = 1;
    cin >> t;

    for(int testcase = 1 ; testcase <= t ; testcase++)
        solve( testcase );
}

Details

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Test #1:

score: 100
Accepted
time: 2ms
memory: 5544kb

input:

3
2
2 5
4 1
1
1000000000000000001
987467354324283836
4
1 2 3 4
1 2 3 4

output:

21
214139910
998244129

result:

ok 3 number(s): "21 214139910 998244129"

Test #2:

score: -100
Runtime Error

input:

1
5
1 2 3 4 5
1 2 3 4 5

output:


result: