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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#136613 | #237. Triangle Partition | whsyhyyh# | 100 ✓ | 6ms | 3636kb | C++14 | 920b | 2023-08-09 09:22:11 | 2023-08-09 09:22:11 |
Judging History
answer
#pragma GCC optimize("Ofast","unroll-loops","omit-frame-pointer","inline")
#pragma GCC option("arch=native","tune=native","no-zero-upper")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,avx2")
#pragma GCC optimize(3)
#include<bits/stdc++.h>
#define N 3010
#define rep(i,l,r) for(int i=l;i<=r;i++)
#define drep(i,r,l) for(int i=r;i>=l;i--)
using namespace std;
int rd() {
int res=0,f=1;char ch=getchar();
while(ch<'0'||ch>'9') {if(ch=='-') f*=-1;ch=getchar();}
while(ch>='0'&&ch<='9') res=(res<<1)+(res<<3)+(ch^48),ch=getchar();
return res*f;
}
int T,n;
struct node {
int x,y,id;
}q[N];
bool cmp(node x,node y) {
if(x.x!=y.x) return x.x<y.x;
return x.y<y.y;
}
int main() {
T=rd();
while(T--) {
n=rd();
rep(i,1,n*3) q[i].x=rd(),q[i].y=rd(),q[i].id=i;
sort(q+1,q+n*3+1,cmp);
rep(i,1,n) printf("%d %d %d\n",q[i*3-2].id,q[i*3-1].id,q[i*3].id);
}
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 6ms
memory: 3636kb
input:
190 10 -7215 2904 -5179 1663 -542 1091 -5687 7868 7838 -1048 -2944 4346 -2780 3959 -9402 1099 -8548 -7238 -3821 -2917 2713 295 -856 -8661 7651 3945 -8216 -543 5798 5024 8583 -3384 -1208 5955 3068 -385 340 2968 6559 -272 4537 5075 5126 4343 639 8281 1700 2572 819 9317 -9854 -1316 -3421 -1137 9368 718...
output:
26 8 9 14 29 1 4 2 10 27 6 7 17 12 3 19 23 25 24 11 18 21 22 15 20 30 13 5 16 28 30 3 18 29 5 17 12 11 27 15 19 10 28 25 9 24 7 13 6 8 23 14 22 2 20 4 16 26 21 1 6 11 16 8 27 10 13 15 14 29 22 19 9 2 18 24 12 20 1 26 4 5 30 7 3 25 23 17 21 28 16 8 18 19 23 13 7 26 24 3 1 5 29 25 27 9 6 15 12 22 14 1...
result:
ok AC