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QOJ
| ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
|---|---|---|---|---|---|---|---|---|---|
| #136493 | #5. 在线 O(1) 逆元 | zhouhuanyi | 60 | 4521ms | 42956kb | C++14 | 387b | 2023-08-08 21:04:54 | 2024-11-05 21:51:30 |
Judging History
answer
#include<iostream>
#include<cstdio>
#define mod 998244353
#define N 10000000
using namespace std;
int MD2(int x)
{
return x<0?x+mod:x;
}
int T,invs[N+1];
void init(int p)
{
invs[1]=1;
for (int i=2;i<=N;++i) invs[i]=MD2(-1ll*(mod/i)*invs[mod%i]%mod);
return;
}
int inv(int x)
{
int a,b;
if (x<=N) return invs[x];
else return MD2(-1ll*(mod/x)*inv(mod%x)%mod);
}
詳細信息
Pretests
Final Tests
Test #1:
score: 10
Accepted
time: 152ms
memory: 42896kb
Test #2:
score: 20
Accepted
time: 1048ms
memory: 42760kb
Test #3:
score: 30
Accepted
time: 4521ms
memory: 42956kb
Test #4:
score: 0
Time Limit Exceeded
Test #5:
score: 0
Time Limit Exceeded