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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#134908#6634. Central SubsetkiwiHM#WA 13ms9716kbC++141.8kb2023-08-05 09:56:002023-08-05 09:56:01

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-08-05 09:56:01]
  • 评测
  • 测评结果:WA
  • 用时:13ms
  • 内存:9716kb
  • [2023-08-05 09:56:00]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;

const int Maxn = 200500;

struct Enode{
    int u, v;
} E[1000500];

vector <int> son[Maxn], ans;
int dep[Maxn], maxd[Maxn], p[Maxn];
int n, m, LMT;

void cmax(int &x, int y){ if (x < y) x = y; }

void dfs(int u, int fa){
    for (auto v : son[u]) if (v != fa){
        dep[v] = dep[u] + 1;
        dfs(v, u);
    }
}

void solve(int u, int fa){
    maxd[u] = dep[u];
    for (auto v : son[u]) if (v != fa){
        solve(v, u);
        if (maxd[v] - dep[u] > LMT){
            ans.push_back(v);
        } else {
            cmax(maxd[u], maxd[v]);
        }
    }
}

void init(int n){
    for (int i = 1; i <= n; i++)
        son[i].clear();
    dep[1] = 0;
    for (int i = 1; i <= n; i++)
        p[i] = i;
    LMT = sqrt(n);
    if (LMT * LMT < n)
        LMT++;
}

int getfa(int u){
    if (u == p[u])
        return u;
    return p[u] = getfa(p[u]);
}

int main(){
    int T; cin >> T;
    while (T--){
        cin >> n >> m, init(n);
        for (int i = 1; i <= m; i++)
            cin >> E[i].u >> E[i].v;
        for (int i = 1; i <= m; i++){
            int u = E[i].u, v = E[i].v;
            int fu = getfa(u), fv = getfa(v);
            if (fu == fv)
                continue;
            p[fu] = fv;
            son[u].push_back(v);
            son[v].push_back(u);
        }
        dfs(1, 0), solve(1, 0);
        if (ans.size() > LMT){
            puts("-1");
        } else {   
            cout << ans.size() << '\n';
            for (int i = 0, si = ans.size(); i < si; i++)
                cout << ans[i] << (i == si - 1 ? '\n' : ' ');
        }
    }
    return 0;
}
/*
2
4 3
1 2 
2 3 
3 4 
6 7 
1 2 
2 3 
3 1 
1 4 
4 5 
5 6 
6 4
*/

詳細信息

Test #1:

score: 100
Accepted
time: 2ms
memory: 9584kb

input:

2
4 3
1 2
2 3
3 4
6 7
1 2
2 3
3 1
1 4
4 5
5 6
6 4

output:

1
2
1
2

result:

ok correct (2 test cases)

Test #2:

score: -100
Wrong Answer
time: 13ms
memory: 9716kb

input:

10000
15 14
13 12
5 4
9 8
11 12
15 14
10 9
14 13
2 3
2 1
6 5
10 11
3 4
7 6
8 7
6 5
2 1
2 4
4 6
2 3
3 5
10 9
8 3
9 4
5 6
5 10
3 2
5 4
2 7
1 2
4 3
2 1
2 1
2 1
2 1
9 8
9 8
5 4
1 2
6 5
3 4
3 2
7 8
7 6
2 1
1 2
14 13
3 10
5 6
2 9
11 4
2 3
2 1
8 7
13 6
5 4
5 12
6 7
4 3
7 14
16 15
2 3
2 1
6 10
6 9
6 4
9 11
...

output:

2
11 6
2
11 6
3
11 6 2
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-...

result:

wrong answer Condition failed: "getMaxBfsDist(n, subset) <= csqrtn" (test case 1)