QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#134828 | #6636. Longest Strictly Increasing Sequence | SolitaryDream# | AC ✓ | 3ms | 3744kb | C++20 | 739b | 2023-08-05 09:10:34 | 2023-08-05 09:10:35 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
const int N=1e5+1e3+7;
int T,n,a[N],f[N];
int main()
{
scanf("%d",&T);
while(T--)
{
scanf("%d",&n);
for(int i=1;i<=n;i++)
scanf("%d",&a[i]);
for(int i=1;i<=n;i++)
{
f[i]=0;
for(int j=0;j<i;j++)
if(a[i]>a[j])
f[i]=max(f[i],f[j]+1);
}
bool ok=1;
for(int i=1;i<=n;i++)
if(f[i]!=a[i]||a[i]<a[i-1])
ok=0;
if(!ok)
puts("NO");
else
{
puts("YES");
for(int i=1;i<=n;i++)
printf("%d%c",a[i]," \n"[i==n]);
}
}
}
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 0ms
memory: 3644kb
input:
2 6 1 2 3 2 5 7 2 1 2
output:
NO YES 1 2
result:
ok t=2 (2 test cases)
Test #2:
score: 0
Accepted
time: 3ms
memory: 3744kb
input:
3483 5 2 3 5 1 1 2 8 1 10 1 2 3 4 4 5 6 6 6 7 10 1 1 2 2 2 2 3 4 4 5 2 5 8 3 7 10 8 5 4 1 3 3 8 10 1 2 2 2 2 2 2 3 3 3 10 1 1 2 3 4 5 5 5 5 6 9 1 2 3 4 5 5 6 6 7 7 8 8 8 8 9 1 2 5 8 9 8 3 5 10 1 2 3 3 3 3 4 4 4 5 5 7 1 6 4 3 7 5 6 8 6 1 5 5 10 1 2 2 3 4 4 4 4 5 5 3 10 4 5 3 1 5 3 5 2 8 1 2 1 3 7 8 3...
output:
NO NO YES 1 2 3 4 4 5 6 6 6 7 YES 1 1 2 2 2 2 3 4 4 5 NO NO NO YES 1 2 2 2 2 2 2 3 3 3 YES 1 1 2 3 4 5 5 5 5 6 YES 1 2 3 4 5 5 6 6 7 NO NO YES 1 2 3 3 3 3 4 4 4 5 NO NO YES 1 2 2 3 4 4 4 4 5 5 NO NO NO NO NO NO YES 1 1 1 2 2 3 3 4 4 NO NO NO NO NO NO NO YES 1 2 3 3 3 4 4 4 5 5 YES 1 1 2 2 2 3 3 3 3 ...
result:
ok t=3483 (3483 test cases)