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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#130821#4940. Token Distancekaruna#RE 1ms5532kbC++173.6kb2023-07-25 11:30:342023-07-25 11:30:37

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-07-25 11:30:37]
  • 评测
  • 测评结果:RE
  • 用时:1ms
  • 内存:5532kb
  • [2023-07-25 11:30:34]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;

const int MAXN = 101010;
const int INF = 1e9 + 10;
int n, q, a[MAXN];

struct seg {
    array<int, 3> tree[MAXN];
    bool g = false;

    void update(int a, int v, int l, int r, int x) {
        if (l == r) {
            tree[x] = {v, v, v};
            return;
        }
        int m = (l + r) / 2;
        if (a <= m) update(a, v, l, m, 2 * x);
        else update(a, v, m + 1, r, 2 * x + 1);
        auto [m1, M1, g1] = tree[2 * x];
        auto [m2, M2, g2] = tree[2 * x + 1];
        if (g) {
            tree[x] = {min(m1, m2), max(M1, M2), __gcd(g1, g2)};
        }
        else {
            tree[x] = {min(m1, m2), max(M1, M2), 0};
        }
    }
    int query(int a, int b, int t, int l, int r, int x) {
        if (b < l || a > r) {
            return vector<int>{INF, -INF, 0}[t];
        }
        if (a <= l && r <= b) return tree[x][t];
        int m = (l + r) / 2;
        int r1 = query(a, b, t, l, m, 2 * x);
        int r2 = query(a, b, t, m + 1, r, 2 * x + 1);
        if (t == 0) return min(r1, r2);
        else if (t == 1) return max(r1, r2);
        else return __gcd(r1, r2);
    }
} t1, t2, t3;

set<pair<int, int>> st;
int main() {
    cin.tie(0); ios_base::sync_with_stdio(0);
    cin >> n >> q;
    t2.g = true;
    for (int i = 1; i <= n; i++) {
        cin >> a[i];
        t1.update(i, a[i], 1, n, 1);
        if (i != 1) {
            t2.update(i, a[i] - a[i - 1], 2, n, 1);
        }
        st.insert({a[i], i});
    }
    for (auto it = st.begin(); it != st.end(); it = next(it)) {
        if (it != st.begin() && prev(it)->first == it->first)
            t3.update(it->second, prev(it)->second, 1, n, 1);
    }
    while (q--) {
        int t; cin >> t;
        if (t == 1) {
            int x, v; cin >> x >> v;
            auto it = st.find({a[x], x});
            if (it != st.begin() && prev(it)->first == it->first) {
                t3.update(it->second, 0, 1, n, 1);
            }
            if (it != st.end() && it->first == next(it)->first) {
                t3.update(next(it)->second, 0, 1, n, 1);
            }
            st.erase({a[x], x});
            a[x] = v;

            t1.update(x, v, 1, n, 1);
            if (x != 1) t2.update(x, a[x] - a[x - 1], 2, n, 1);
            if (x != n) t2.update(x + 1, a[x + 1] - a[x], 2, n, 1);
            it = st.insert({v, x}).first;
            if (it != st.begin() && prev(it)->first == it->first) {
                t3.update(it->second, prev(it)->second, 1, n, 1);
            }
            if (it != st.end() && it->first == next(it)->first) {
                t3.update(next(it)->second, it->second, 1, n, 1);
            }
        }
        else {
            int l, r; cin >> l >> r;
            int m = t1.query(l, r, 0, 1, n, 1);
            int M = t1.query(l, r, 1, 1, n, 1);
            if (m == M) {
                cout << "YES\n";
            }
            else {
                if ((M - m) % (r - l) != 0) {
                    cout << "NO\n";
                }
                else {
                    int D = (M - m) / (r - l);
                    int g = t2.query(l + 1, r, 2, 2, n, 1);
                    if (g % D != 0) {
                        cout << "NO\n";
                    }
                    else {
                        int x = t3.query(l, r, 1, 1, n, 1);
                        if (x >= l) 
                            cout << "NO\n";
                        else 
                            cout << "YES\n";
                    }
                }
            }
        }
    }
}

詳細信息

Test #1:

score: 100
Accepted
time: 1ms
memory: 5488kb

input:

5 7
1 1 1 10 1
2 1 3
2 1 5
1 5 4
1 3 7
2 2 4
2 2 5
2 4 5

output:

YES
NO
NO
YES
YES

result:

ok 5 lines

Test #2:

score: 0
Accepted
time: 1ms
memory: 5532kb

input:

2 1
0 1000000000
2 1 2

output:

YES

result:

ok single line: 'YES'

Test #3:

score: -100
Runtime Error

input:

81473 13549
972586683 972586964 972587245 972587526 972587807 972588088 972588369 972588650 972588931 972589212 972589493 972589774 972590055 972590336 972590617 972590898 972591179 972591460 972591741 972592022 972592303 972592584 972592865 972593146 972593427 972593708 972593989 972594270 97259455...

output:


result: