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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#129388#6137. Sub-cycle GraphEnergy_is_not_over#AC ✓1492ms5816kbC++173.9kb2023-07-22 17:59:032023-07-22 17:59:05

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-07-22 17:59:05]
  • 评测
  • 测评结果:AC
  • 用时:1492ms
  • 内存:5816kb
  • [2023-07-22 17:59:03]
  • 提交

answer

//
// Created by Barichek on 22.07.2023 11:45:22
//

#include <bits/stdc++.h>

#define F first
#define S second
#define MP make_pair
#define PB push_back

#define all(a) a.begin(), a.end()
#define len(a) (int) (a.size())
#define mp make_pair
#define pb push_back
#define fir first
#define sec second

using namespace std;

typedef pair<int, int> pii;
typedef long long ll;
typedef long double ld;

#ifdef Energy_is_not_over
#define DEBUG for (bool ____DEBUG = true; ____DEBUG; ____DEBUG = false)
#define LOG(...) print(#__VA_ARGS__" ::", __VA_ARGS__) << endl

template<class ...Ts>
auto &print(Ts ...ts) { return ((cerr << ts << " "), ...); }

#else
#define DEBUG while (false)
#define LOG(...)
#endif

const int max_n = -1, inf = 1000111222;

/*
 * long long version

long long mul(long long a, long long b) {
    long long x = (long double) a * b / mod;
    long long y = (a * b - x * mod) % mod;
    return y < 0 ? y + mod : y;
}

long long power(long long a, long long b) {
    if (b == 0) {
        return 1 % mod;
    }
    if (b % 2 == 0) {
        return power(mul(a, a), b / 2);
    }
    return mul(a, power(a, b - 1));
}*/

const int mod = 1000000007;
//const int mod = 998244353;

inline void inc(int &x, int y) {
    x += y;
    if (x >= mod) {
        x -= mod;
    }
}

inline void dec(int &x, int y) {
    x -= y;
    if (x < 0) {
        x += mod;
    }
}

inline int neg(int x) {
    return x ? (mod - x) : 0;
}

inline int mul(int x) {
    return x;
}

template<typename... Args>
inline int mul(int x, Args... args) {
    return (1LL * x * mul(args...)) % mod;
}

int power(int a, long long b) {
    int res = 1 % mod;
    while (b) {
        if (b % 2) {
            res = mul(res, a);
        }
        b /= 2;
        a = mul(a, a);
    }
    return res;
}

int inv(int x) {
    return power(x, mod - 2);
}

const int max_f = 3e5+10;
const int max_rf = max_f;
static_assert(max_f >= 1 && max_rf >= 1);

int f[max_f], rf[max_rf];

bool frf_calculated = []() {
    f[0] = 1;
    for (int i = 1; i < max_f; ++i) {
        f[i] = mul(i, f[i - 1]);
    }
    int x = f[min(max_f, max_rf) - 1];
    for (int i = max_f; i < max_rf; ++i) {
        x = mul(x, i);
    }
    rf[max_rf - 1] = inv(x);
    for (int i = max_rf - 2; i >= 0; --i) {
        rf[i] = mul(i + 1, rf[i + 1]);
    }
    return true;
}();

int get_c(int n, int k) {
    if (n < k || k < 0) {
        return 0;
    }
    assert(n < max_f && k < max_rf && n - k < max_rf);
    return mul(f[n], rf[k], rf[n - k]);
}

string str_fraction(int x, int n = 20) {
    stringstream res;
    pair<int, int> best(x, 1);
    for (int j = 1; j < n; ++j) {
        best = min(best, {mul(x, j), j});
        best = min(best, {mod - mul(x, j), -j});
    }
    if (best.second < 0) {
        best.first *= -1;
        best.second *= -1;
    }
    res << best.first << "/" << best.second;
    return res.str();
}

void solve()
{
    int n;
    ll m;
    cin>>n>>m;
    if (m>n){
        cout<<0<<"\n";
        return;
    }
    if (m==n){
        cout<<mul(f[n-1],inv(2))<<"\n";
        return;
    }
    if (m==0){
        cout<<1<<"\n";
        return;
    }
    const int c=n-m;
    int ans=0;
    for (int ones=0;ones<c;ones++){
        int cur_n=n-ones;
        int cur_c=c-ones;
        LOG(ones,cur_n,cur_c);
        if (cur_n>=2*cur_c){
            int cur=mul(f[cur_n],get_c((cur_n-2*cur_c)+cur_c-1,cur_c-1),inv(power(2,cur_c)),rf[cur_c]);
            LOG(get_c(n,ones),cur);
            inc(ans,mul(get_c(n,ones),cur));
        }
    }
    cout<<ans<<"\n";
}

int main() {
//    freopen("input.txt", "r", stdin);
//    freopen("output.txt", "w", stdout);
    ios_base::sync_with_stdio(0);
    cin.tie(0);

    int tests;
    cin>>tests;
    while (tests--){
        solve();
    }
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 5ms
memory: 5816kb

input:

3
4 2
4 3
5 3

output:

15
12
90

result:

ok 3 number(s): "15 12 90"

Test #2:

score: 0
Accepted
time: 1492ms
memory: 5804kb

input:

17446
3 0
3 1
3 2
3 3
4 0
4 1
4 2
4 3
4 4
5 0
5 1
5 2
5 3
5 4
5 5
6 0
6 1
6 2
6 3
6 4
6 5
6 6
7 0
7 1
7 2
7 3
7 4
7 5
7 6
7 7
8 0
8 1
8 2
8 3
8 4
8 5
8 6
8 7
8 8
9 0
9 1
9 2
9 3
9 4
9 5
9 6
9 7
9 8
9 9
10 0
10 1
10 2
10 3
10 4
10 5
10 6
10 7
10 8
10 9
10 10
11 0
11 1
11 2
11 3
11 4
11 5
11 6
11 7
11...

output:

1
3
3
1
1
6
15
12
3
1
10
45
90
60
12
1
15
105
375
630
360
60
1
21
210
1155
3465
5040
2520
360
1
28
378
2940
13545
35280
45360
20160
2520
1
36
630
6552
42525
170100
393120
453600
181440
20160
1
45
990
13230
114345
643545
2286900
4762800
4989600
1814400
181440
1
55
1485
24750
273735
2047815
10239075
3...

result:

ok 17446 numbers