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QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#129338#6300. Best Carry Player 2zltWA 1ms3880kbC++141.1kb2023-07-22 15:40:572023-07-22 15:41:01

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-07-22 15:41:01]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:3880kb
  • [2023-07-22 15:40:57]
  • 提交

answer

#include <bits/stdc++.h>
#define pb emplace_back
#define fst first
#define scd second
#define mems(a, x) memset((a), (x), sizeof(a))

using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef double db;
typedef long double ldb;
typedef pair<ll, ll> pii;

ll n, m, f[20][20][2], a[20], tot;

void solve() {
	scanf("%lld%lld", &n, &m);
	if (m == 0) {
		ll ans = 1;
		while (n % 10 == 9) {
			n /= 10;
			ans *= 10;
		}
		printf("%lld\n", ans);
		return;
	}
	ll pw = 1;
	while (n % 10 == 0) {
		n /= 10;
		pw *= 10;
	}
	tot = 0;
	ll x = n;
	while (x) {
		a[++tot] = x % 10;
		x /= 10;
	}
	mems(f, 0x3f);
	f[0][0][0] = 0;
	ll p = 1;
	for (int i = 1; i <= 18; ++i, p *= 10) {
		for (int j = 0; j < 18; ++j) {
			for (int k = 0; k < 2; ++k) {
				for (int t = 0; t <= 9; ++t) {
					int nj = (t + a[i] + k) / 10 + j, nk = (t + a[i] + k) / 10;
					f[i][nj][nk] = min(f[i][nj][nk], f[i - 1][j][k] + p * t);
				}
			}
		}
	}
	printf("%lld\n", min(f[18][m][0], f[18][m][1]) * pw);
}

int main() {
	int T = 1;
	scanf("%d", &T);
	while (T--) {
		solve();
	}
	return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 1ms
memory: 3648kb

input:

4
12345678 0
12345678 5
12345678 18
990099 5

output:

1
54322
999999999987654322
9910

result:

ok 4 lines

Test #2:

score: -100
Wrong Answer
time: 1ms
memory: 3880kb

input:

21
999990000099999 0
999990000099999 1
999990000099999 2
999990000099999 3
999990000099999 4
999990000099999 5
999990000099999 6
999990000099999 7
999990000099999 8
999990000099999 9
999990000099999 10
999990000099999 11
999990000099999 12
999990000099999 13
999990000099999 14
999990000099999 15
999...

output:

100000
10000
1000
100
10
1
900001
9900001
99900001
999900001
10000000001
9999910000
9999901000
9999900100
9999900010
9999900001
9000009999900001
99000009999900001
999000009999900001
4055430048555597824
1000000000000000000

result:

wrong answer 20th lines differ - expected: '99999999999999999900000000000000000', found: '4055430048555597824'