QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#127698 | #6636. Longest Strictly Increasing Sequence | xiaoxing666 | AC ✓ | 3ms | 3628kb | C++17 | 826b | 2023-07-19 22:22:20 | 2023-07-19 22:22:21 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
int main()
{
int t;
scanf("%d" ,&t);
while(t--)
{
int n;
scanf("%d", &n);
int f = 1;
vector<int> b(n + 1), a(n + 1);
for(int i = 1; i <= n; i++)
{
scanf("%d", &b[i]);
if(b[i] > i){
f = 0;
}
if(b[i] < b[i - 1])
{
f = 0;
}
if(b[i] - b[i - 1] >= 2)
{
f = 0;
}
}
if(f == 0)
{
puts("NO");
continue;
}
else{
puts("YES");
// a[1] = 1;
// printf("%d ", a[1]);
// for(int i = 2; i <= n; i++)
// {
// if(b[i] == b[i - 1])
// {
// a[i] = a[i - 1];
// }
// else{
// a[i] = a[i - 1] + 1;
// }
// printf("%d ", a[i]);
// }
for(int i = 1; i <= n; i++)
cout << b[i] << " ";
puts("");
}
}
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 1ms
memory: 3528kb
input:
2 6 1 2 3 2 5 7 2 1 2
output:
NO YES 1 2
result:
ok t=2 (2 test cases)
Test #2:
score: 0
Accepted
time: 3ms
memory: 3628kb
input:
3483 5 2 3 5 1 1 2 8 1 10 1 2 3 4 4 5 6 6 6 7 10 1 1 2 2 2 2 3 4 4 5 2 5 8 3 7 10 8 5 4 1 3 3 8 10 1 2 2 2 2 2 2 3 3 3 10 1 1 2 3 4 5 5 5 5 6 9 1 2 3 4 5 5 6 6 7 7 8 8 8 8 9 1 2 5 8 9 8 3 5 10 1 2 3 3 3 3 4 4 4 5 5 7 1 6 4 3 7 5 6 8 6 1 5 5 10 1 2 2 3 4 4 4 4 5 5 3 10 4 5 3 1 5 3 5 2 8 1 2 1 3 7 8 3...
output:
NO NO YES 1 2 3 4 4 5 6 6 6 7 YES 1 1 2 2 2 2 3 4 4 5 NO NO NO YES 1 2 2 2 2 2 2 3 3 3 YES 1 1 2 3 4 5 5 5 5 6 YES 1 2 3 4 5 5 6 6 7 NO NO YES 1 2 3 3 3 3 4 4 4 5 NO NO YES 1 2 2 3 4 4 4 4 5 5 NO NO NO NO NO NO YES 1 1 1 2 2 3 3 4 4 NO NO NO NO NO NO NO YES 1 2 3 3 3 4 4 4 5 5 YES 1 1 2 2 2...
result:
ok t=3483 (3483 test cases)