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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#126647 | #4193. Joined Sessions | cyb1010 | WA | 2ms | 7872kb | C++14 | 2.3kb | 2023-07-18 20:30:41 | 2023-07-18 20:30:42 |
Judging History
answer
/**
* @author : cyb1010
* @date : 2023-07-18 10:11:09
* @file : trolcon.cpp
*/
#include <bits/stdc++.h>
using namespace std;
#define fo(s) freopen(s ".in", "r", stdin), freopen(s ".out", "w", stdout)
#define fi first
#define se second
typedef double db;
typedef long double ldb;
typedef long long ll;
typedef unsigned long long ull;
int n, f[100010][5], lst[100010], cont[100010], ans[5];
struct seg {
int l, r;
seg() {}
seg(int _l, int _r) : l(_l), r(_r) {}
} a[100010];
set<pair<int, int>> s;
bool cmp(seg x, seg y) { return x.r < y.r; }
struct point {
int l, r, t;
} t[3000010];
int rt, tot, inf = 1000000000;
int mx(int x, int y) { return a[x].l > a[y].l ? y : x; }
void add(int &p, int l, int r, int k) {
if (!p)
p = ++tot, t[p].t = k;
t[p].t = mx(t[p].t, k);
if (l < r) {
int mid = l + r >> 1;
a[k].r <= mid ? add(t[p].l, l, mid, k) : add(t[p].r, mid + 1, r, k);
}
}
int qry(int p, int l, int r, int ll) {
if (r < ll || !p)
return 0;
if (l >= ll)
return t[p].t;
int mid = l + r >> 1;
return mx(qry(t[p].l, l, mid, ll), qry(t[p].r, mid + 1, r, ll));
}
int main() {
// fo("trolcon");
scanf("%d", &n), a[0].l = inf;
for (int i = 1; i <= n; i++) scanf("%d%d", &a[i].l, &a[i].r);
sort(a + 1, a + 1 + n, cmp);
for (int i = 1; i <= n; i++) {
auto x = s.lower_bound({a[i].l, 0});
if (x != s.begin())
lst[i] = (--x)->second;
cont[i] = qry(rt, 1, inf, a[i].l), add(rt, 1, inf, i);
s.emplace(a[i].r, i);
}
for (int s = 0; s <= 3; s++) {
for (int i = 1; i <= n; i++) {
f[i][s] = f[lst[i]][s] + 1;
int p = cont[i];
for (int j = 0; j <= s; j++)
f[i][s] = min(f[i][s], p ? f[lst[p]][s - j] + 1 : 1), p = cont[p];
// printf("%d ", f[i][s]);
}
// putchar('\n');
ans[s] = f[n][s];
// for (int i = lst[n] + 1; i < n; i++) ans[s] = min(ans[s], f[i][s]);
// printf("%d\n", ans[s]);
}
if (ans[1] < ans[0])
printf("1\n");
else if (ans[2] < ans[0])
printf("2\n");
else if (ans[3] < ans[0])
printf("3\n");
else
printf("-1\n");
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 2ms
memory: 7644kb
input:
4 1 3 2 5 4 7 6 9
output:
1
result:
ok single line: '1'
Test #2:
score: 0
Accepted
time: 2ms
memory: 7872kb
input:
5 1 3 4 7 8 10 2 5 6 9
output:
2
result:
ok single line: '2'
Test #3:
score: -100
Wrong Answer
time: 0ms
memory: 7796kb
input:
3 1 2 2 3 3 4
output:
-1
result:
wrong answer 1st lines differ - expected: 'impossible', found: '-1'