QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#125590 | #6744. Square | awellwell | AC ✓ | 180ms | 3356kb | C++14 | 1.2kb | 2023-07-16 23:02:59 | 2023-07-16 23:03:03 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
#define forn(i,p,q) for(long long i = p;i <=q;i++)
#define pii pair<int,int>
#define x first
#define y second
int dx[] = {1,-1,0,0};
int dy[] = {0,0,1,-1};
long long sum(long long x)
{
return x * (x + 1LL) / 2LL;
}
long long binary1(long long l, long long r, long long x)
{
while(l<r)
{
long long mid=(r+l)>>1;
if(sum(mid) >= x) r=mid;//类似于线段树,check()则取r = 左的最后一个
else l=mid+1;//否则就是l = 右的第一个
}
return l;//可以做类似于上面的改变,!check(),返回l+极小元
}
long long lv(long long x)
{
return binary1(1,2000000000,x);
}
int main()
{
long long T;
cin >> T;
while(T--)
{
long long p, q;
cin >> p >> q;
if(p >= q) cout << p - q << endl;
else
{
long long plv = lv(p), qlv = lv(q);
long long ans = (sum(qlv) - q) - (sum(plv) - p);
if(ans < 0)
{
ans = (sum(qlv) - q) + (p - sum(plv-1)) + 1;
}
cout << qlv - plv + ans << endl;
}
}
return 0;
}
//1000000000000000000
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 0ms
memory: 3356kb
input:
2 5 1 1 5
output:
4 3
result:
ok 2 number(s): "4 3"
Test #2:
score: 0
Accepted
time: 180ms
memory: 3308kb
input:
100000 1 1 1 2 1 3 1 4 1 5 1 6 1 7 1 8 1 9 1 10 1 11 1 12 1 13 1 14 1 15 1 16 1 17 1 18 1 19 1 20 1 21 1 22 1 23 1 24 1 25 1 26 1 27 1 28 1 29 1 30 1 31 1 32 1 33 1 34 1 35 1 36 1 37 1 38 1 39 1 40 1 41 1 42 1 43 1 44 1 45 1 46 1 47 1 48 1 49 1 50 1 51 1 52 1 53 1 54 1 55 1 56 1 57 1 58 1 59 1 60 1 ...
output:
0 2 1 4 3 2 6 5 4 3 8 7 6 5 4 10 9 8 7 6 5 12 11 10 9 8 7 6 14 13 12 11 10 9 8 7 16 15 14 13 12 11 10 9 8 18 17 16 15 14 13 12 11 10 9 20 19 18 17 16 15 14 13 12 11 10 22 21 20 19 18 17 16 15 14 13 12 11 24 23 22 21 20 19 18 17 16 15 14 13 12 26 25 24 23 22 21 20 19 18 1 0 2 2 1 3 4 3 2 4 6 5 4 3 5 ...
result:
ok 100000 numbers