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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#125499 | #5668. Cell Nuclei Detection | KKT89 | AC ✓ | 2430ms | 148064kb | C++17 | 4.1kb | 2023-07-16 19:21:06 | 2023-07-16 19:21:08 |
Judging History
answer
#pragma GCC optimize("Ofast")
#include <bits/stdc++.h>
using namespace std;
typedef long long int ll;
typedef unsigned long long int ull;
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
ll myRand(ll B) {
return (ull) rng() % B;
}
template<typename T>
struct dinic{
struct edge{
int to;
T c,f;
};
T eps;
const T inf=numeric_limits<T>::max();
int n,m = 0;
vector<edge> e;
vector<vector<int>> g;
vector<int> level, ptr;
dinic(int n): n(n), g(n), level(n), ptr(n) {
eps = (T)1 / (T)1e9;
}
void add_edge(int s, int t, T c){
e.push_back({t, c, 0});
e.push_back({s, 0, 0});
g[s].push_back(m++);
g[t].push_back(m++);
}
bool bfs(int s, int t){
fill(level.begin(), level.end(), -1);
level[s] = 0;
for(queue<int> q({s});q.size();q.pop()){
int s = q.front();
for(int i:g[s]){
int t = e[i].to;
if(level[t] == -1 and (e[i].c - e[i].f) > eps){
level[t] = level[s] + 1;
q.push(t);
}
}
}
return (level[t] != -1);
}
T dfs(int s, int t, T psh){
if(!(psh > eps) or s == t) return psh;
for(int &i = ptr[s]; i < (int)g[s].size(); ++i){
auto &eg = e[g[s][i]];
if(level[eg.to] != level[s] + 1 or !(eg.c - eg.f > eps)) continue;
T f = dfs(eg.to, t, min(psh, eg.c-eg.f));
if(f > eps){
eg.f += f;
e[g[s][i]^1].f -= f;
return f;
}
}
return 0;
}
T max_flow(int s, int t){
T f = 0;
while(bfs(s,t)){
fill(ptr.begin(), ptr.end(), 0);
while(1){
T c = dfs(s, t, inf);
if(c > eps){
f += c;
}
else{
break;
}
}
}
return f;
}
// ABC239-G
vector<bool> min_cut(int s){
vector<bool> visited(n);
queue<int> q; q.push(s);
while(q.size()){
int p = q.front(); q.pop();
visited[p] = true;
for(auto idx:g[p]){
auto eg = e[idx];
if(eg.c - eg.f > eps and !visited[eg.to]){
visited[eg.to] = true;
q.push(eg.to);
}
}
}
return visited;
}
};
vector<int> d[2001][2001];
int main() {
cin.tie(nullptr);
ios::sync_with_stdio(false);
int q; cin >> q;
while (q--) {
int m,n; cin >> m >> n;
const int N = m+n;
vector<int> x1(N),y1(N),x2(N),y2(N);
for (int i = 0; i < N; ++i) {
cin >> x1[i] >> y1[i] >> x2[i] >> y2[i];
}
for (int i = 0; i < n; ++i) {
int xx = x1[m+i], yy = y1[m+i];
d[xx][yy].emplace_back(m+i);
}
const int S = N, T = N+1;
dinic<int> g(N+2);
// 長方形の共通面積
auto cal = [&](int i,int j)->int{
return max(0, min(x2[i],x2[j]) - max(x1[i],x1[j])) * max(0, min(y2[i],y2[j]) - max(y1[i],y1[j]));
};
for (int i = 0; i < m; ++i) {
int x = x1[i], y = y1[i];
int xx = x2[i], yy = y2[i];
int area = (xx-x)*(yy-y);
for (int j = max(x-3,0); j <= xx; ++j) {
for (int k = max(y-3,0); k <= yy; ++k) {
for (int l:d[j][k]) {
int s = cal(i,l);
if(s*2 >= area) g.add_edge(i,l,1);
}
}
}
}
for (int i = 0; i < m; ++i) {
g.add_edge(S,i,1);
}
for (int i = 0; i < n; ++i) {
g.add_edge(i+m,T,1);
}
cout << g.max_flow(S,T) << "\n";
for (int i = 0; i < n; ++i) {
int xx = x1[m+i], yy = y1[m+i];
d[xx][yy].clear();
}
}
}
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 11ms
memory: 97252kb
input:
3 2 2 1 1 3 3 3 3 5 5 2 2 4 4 4 4 6 6 2 3 1 1 3 3 3 3 5 5 1 3 3 5 2 1 4 5 3 1 5 3 3 3 1 1 2 2 2 2 3 3 3 3 4 4 1 1 3 3 2 2 4 4 3 3 5 5
output:
0 1 3
result:
ok 3 lines
Test #2:
score: 0
Accepted
time: 11ms
memory: 97392kb
input:
3 2 2 1 1 3 3 3 3 5 5 2 2 4 4 4 4 6 6 2 3 1 1 3 3 3 3 5 5 1 3 3 5 2 1 4 5 3 1 5 3 3 3 1 1 2 2 2 2 3 3 3 3 4 4 1 1 3 3 2 2 4 4 3 3 5 5
output:
0 1 3
result:
ok 3 lines
Test #3:
score: 0
Accepted
time: 1280ms
memory: 146076kb
input:
5 50000 50000 0 0 4 4 4 0 8 4 8 0 12 4 12 0 16 4 16 0 20 4 20 0 24 4 24 0 28 4 28 0 32 4 32 0 36 4 36 0 40 4 40 0 44 4 44 0 48 4 48 0 52 4 52 0 56 4 56 0 60 4 60 0 64 4 64 0 68 4 68 0 72 4 72 0 76 4 76 0 80 4 80 0 84 4 84 0 88 4 88 0 92 4 92 0 96 4 96 0 100 4 100 0 104 4 104 0 108 4 108 0 112 4 112 ...
output:
50000 50000 0 50000 3150
result:
ok 5 lines
Test #4:
score: 0
Accepted
time: 211ms
memory: 141552kb
input:
5 50000 50000 0 0 1 1 1 0 2 1 2 0 3 1 3 0 4 1 4 0 5 1 5 0 6 1 6 0 7 1 7 0 8 1 8 0 9 1 9 0 10 1 10 0 11 1 11 0 12 1 12 0 13 1 13 0 14 1 14 0 15 1 15 0 16 1 16 0 17 1 17 0 18 1 18 0 19 1 19 0 20 1 20 0 21 1 21 0 22 1 22 0 23 1 23 0 24 1 24 0 25 1 25 0 26 1 26 0 27 1 27 0 28 1 28 0 29 1 29 0 30 1 30 0 ...
output:
50000 25050 12500 16000 8000
result:
ok 5 lines
Test #5:
score: 0
Accepted
time: 153ms
memory: 112692kb
input:
5 50000 50000 0 0 2 4 4 0 7 1 8 0 10 1 12 0 15 3 16 0 19 1 20 0 22 2 24 0 26 4 28 0 30 4 32 0 36 3 36 0 40 1 40 0 44 1 44 0 47 2 48 0 49 3 52 0 54 1 56 0 59 4 60 0 64 3 64 0 68 3 68 0 70 1 72 0 76 4 76 0 80 3 80 0 84 4 84 0 87 2 88 0 90 1 92 0 94 4 96 0 98 1 100 0 104 1 104 0 107 2 108 0 110 4 112 0...
output:
10594 10779 10618 10381 10779
result:
ok 5 lines
Test #6:
score: 0
Accepted
time: 2430ms
memory: 148064kb
input:
5 50000 50000 0 0 4 4 1 0 5 4 2 0 6 4 3 0 7 4 4 0 8 4 5 0 9 4 6 0 10 4 7 0 11 4 8 0 12 4 9 0 13 4 10 0 14 4 11 0 15 4 12 0 16 4 13 0 17 4 14 0 18 4 15 0 19 4 16 0 20 4 17 0 21 4 18 0 22 4 19 0 23 4 20 0 24 4 21 0 25 4 22 0 26 4 23 0 27 4 24 0 28 4 25 0 29 4 26 0 30 4 27 0 31 4 28 0 32 4 29 0 33 4 30...
output:
50000 50000 50000 50000 49600
result:
ok 5 lines
Test #7:
score: 0
Accepted
time: 11ms
memory: 97304kb
input:
1 4 4 1 1 3 3 2 1 4 3 1 2 3 4 2 2 4 4 2 1 4 3 3 2 5 4 1 2 3 4 2 3 4 5
output:
3
result:
ok single line: '3'