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QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#124150#5874. Mystery Squaretraining4usaco41 ✓504ms3452kbC++173.2kb2023-07-14 10:25:502023-07-14 10:25:53

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-07-14 10:25:53]
  • 评测
  • 测评结果:41
  • 用时:504ms
  • 内存:3452kb
  • [2023-07-14 10:25:50]
  • 提交

answer

#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
#include <bits/stdc++.h>
using namespace std;

using i128 = __int128;

int n, mid;
string str;
i128 ans, mask0, mask1, tot;

void dfs1(int idx, i128 val, i128 s) {
    if(ans != -1) return;
    
    if(idx == mid) {
        if(!(((s * s) & mask0) || ((tot ^ (s * s)) & mask1))) {
            ans = s * s;
        }
        if(!((((s | (i128)1 << (idx - 1)) * (s | (i128)1 << (idx - 1))) & mask0) || ((tot ^ ((s | (i128)1 << (idx - 1)) * (s | (i128)1 << (idx - 1)))) & mask1))) {
            ans = (s | (i128)1 << (idx - 1)) * (s | (i128)1 << (idx - 1));
        }
        return;
    }
    
    int flag = ((s * s) >> idx) & 1;
    int next = flag;
    if(str[idx] == '?' || str[idx] == ('0' + (next & 1))) {
        dfs1(idx + 1, val | (i128)(next & 1) << idx, s);
    }
    next = flag + 1;
    if(idx == 2) ++next;
    if(str[idx] == '?' || str[idx] == ('0' + (next & 1))) {
        dfs1(idx + 1, val | (i128)(next & 1) << idx, s | i128(1) << (idx - 1));
    }
}

void dfs2(int idx, i128 val) {
    if(ans != -1) return;
    if(idx == mid - 1) {
        i128 x = sqrt((long double) val);
        while(x * x < val) ++x;
        while(((x * x) >> mid) == (val >> mid)) {
            if(!(((x * x) & mask0) || ((tot ^ (x * x)) & mask1))) {
                ans = x * x;
                break;
            }
            ++x;
        }
        return;
    }
    
    if(str[idx] == '?' || str[idx] == '0') dfs2(idx - 1, val);
    if(str[idx] == '?' || str[idx] == '1') dfs2(idx - 1, val | (i128)1 << idx);
}

void solve(int t) {
    cin >> str; reverse(str.begin(), str.end());
    ans = -1;
    int i = 0;
    while(str.size()) {
        if(str[0] == '?' || str[0] == '1') {
            str[0] = '1';
            
            mid = (str.size() + 1) / 2;
            int lcnt = 0, rcnt = 0;
            for(int i = 0; i < mid; ++i) lcnt += str[i] == '?';
            for(int i = mid; i < str.size(); ++i) rcnt += str[i] == '?';
            
            mask0 = mask1 = tot = 0;
            for(int i = 0; i < str.size(); ++i) {
                tot |= ((i128)1 << i);
                if(str[i] == '?') continue;
                if(str[i] == '0') mask0 |= ((i128)1 << i);
                if(str[i] == '1') mask1 |= ((i128)1 << i);
            }
            
            if(lcnt < rcnt) {
                // cout << "a" << endl;
                dfs1(2, 1, 1);
            }
            else {
                // cout << "b" << endl;
                dfs2(str.size() - 1, 0);
            }
            
            if(ans != (i128)-1) {
                cout << "Case #" << t << ": ";
                for(int i = str.size() - 1; i >= 0; --i) cout << (long long)((ans >> i) & 1);
                for(int j = 1; j <= i; ++j) cout << '0';
                cout << "\n"; break;
            }
            // cout << (long long)ans << endl;
        }
        str.erase(str.begin()); str.erase(str.begin());
        i += 2;
    }
}

int main() {
    cin.tie(0)->sync_with_stdio(false);
    int t, tot; cin >> t; tot = t;
    while(t--) solve(tot - t);
    return 0;
}

詳細信息

Subtask #1:

score: 10
Accepted

Test #1:

score: 10
Accepted
time: 1ms
memory: 3452kb

input:

25
1???
1
10??110??00??1000??
1??010?0110?1010?0?010?0111011?11100?100010?0??0??1
1??11????00??1?1?0?1??01??110110?11?00100110?00100?0?00
11?1?1???11111?11?1??11110000?00?????00??0?000?000?1
10??000000?0?00000?00000000??0?0000???00??????0000???
101???11??11000?????1??1?1??10??0?0100011?0001?01011001...

output:

Case #1: 1001
Case #2: 1
Case #3: 1011110110000100001
Case #4: 111010001100101000001010111011011100110001000110001
Case #5: 1101111110000101100101010111011001110010011000010000100
Case #6: 1111111111111111111111111000000000000000000000000001
Case #7: 1000000000000000000000000000000000000000000000000...

result:

ok 25 lines

Subtask #2:

score: 31
Accepted

Test #2:

score: 31
Accepted
time: 504ms
memory: 3360kb

input:

25
1????????????????????111101010000011100110101111000001011111100110000011000101100000010010110100101000????????????????????
10?11100?000111??11?01010110100??1?100111?001000000??0101?110?0111?011?11?1??00010111?010??100?100??10?010?001001110111110?1
1000100111100100110011010111100001111010?????????...

output:

Case #1: 11100101110101010110111110101000001110011010111100000101111110011000001100010110000001001011010010100001101011000010100001
Case #2: 1011110000001110111001010110100001110011100010000001101010110001111011111110000010111101010100010010101010100100111011111001
Case #3: 1000100111100100110011010...

result:

ok 25 lines

Extra Test:

score: 0
Extra Test Passed