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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#123572#6639. Disk TreeinstallbWA 2ms19160kbC++144.2kb2023-07-12 21:48:582023-07-12 21:48:59

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-07-12 21:48:59]
  • 评测
  • 测评结果:WA
  • 用时:2ms
  • 内存:19160kb
  • [2023-07-12 21:48:58]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N = 400005;

struct interval{
    int l,r,pos,id;
    bool operator < (const interval &o)const{
        if(l == o.l) return pos < o.pos;
        return l < o.l;
    }
}s[N];

set <pair <int,int> > st;
vector <tuple <int,int,int,int> > ans;
int n,x[N],y[N],r[N];

struct node{
    int x,y,id;
    bool operator < (const node &nd)const{
        if(x == nd.x) return y < nd.y;
        return x < nd.x;
    }
};
// node lis[N << 2]; int lsc = 0;
vector <node> nx[N];

void solve(){
    cin >> n;
    int minl = 0x3f3f3f3f;
    for(int i = 1;i <= n;i ++){
        cin >> x[i] >> y[i] >> r[i];
        s[i] = {x[i] - r[i],x[i] + r[i],y[i],i};
        minl = min(minl,x[i] - r[i]);
    }
    if(minl < 0) minl = 0;
    sort(s + 1,s + 1 + n);
    // connect all possible circles with x = minl first
    int pos = 0;
    for(int i = 1;i <= n;i ++){
        if(x[s[i].id] - r[s[i].id] <= minl) pos = i;
        else break;
    }
    vector <pair <int,int> > G;
    for(int i = 1;i <= pos;i ++){
        G.push_back({y[s[i].id],s[i].id});
        st.insert({y[s[i].id],s[i].id});
    }
    sort(G.begin(),G.end());
    for(int i = 1;i < G.size();i ++){
        int u = G[i - 1].second,v = G[i].second;
        ans.push_back({0,y[u],0,y[v]});
    }
    
    G.clear();
    pair <int,int> mxr = {-1,-1};
    for(int i = 1;i <= pos;i ++) mxr = max(mxr,{x[s[i].id] + r[s[i].id],s[i].id});
    for(int i = pos + 1;i <= n;i ++){
        int u = s[i].id,id = -1;
        
        if(i > 1 && x[s[i].id] - r[s[i].id] != x[s[i - 1].id] - r[s[i - 1].id]){
            for(auto pi : G) st.insert(pi);
            G.clear();
        }

        while(st.size()){
            auto it = st.lower_bound({y[u],-1});
            if(it == st.end()) break;
            int v = it->second;
            if(x[v] + r[v] < x[u] - r[u]) st.erase(it);
            else{
                id = v;
                break;
            }
        }
        if(id == -1){
            while(st.size()){
                auto it = -- st.lower_bound({y[u],-1});
                int v = it->second;
                if(x[v] + r[v] < x[u] - r[u]) st.erase(it);
                else{
                    id = v;
                    break;
                }
            }
        }
        if(id == -1 && i > 1){
            ans.push_back({mxr.first,y[mxr.second],x[u] - r[u],y[u]});
        }
        else{
            nx[id].push_back({x[u] - r[u],y[u],u});
            // lis[++ lsc] = {x[u] - r[u],min(y[id],y[u]),max(y[id],y[u])};
            // ans.push_back({x[u] - r[u],y[id],x[u] - r[u],y[u]});
        }
        G.push_back({y[u],u});
        mxr = max(mxr,{x[u] + r[u],u});
    }
    for(int i = 1;i <= n;i ++){
        if(nx[i].size() == 0) continue;
        sort(nx[i].begin(),nx[i].end());
        int las = 0;
        for(int j = 0;j < nx[i].size();j ++){
            if(j + 1 == nx[i].size() || (nx[i][j].x != nx[i][j + 1].x)){
                G.clear();
                for(int k = las;k <= j;k ++){
                    G.push_back({nx[i][k].y,nx[i][k].id});
                }
                G.push_back({y[s[i].id],s[i].id});
                sort(G.begin(),G.end());
                for(int k = 1;k < G.size();k ++){
                    ans.push_back({nx[i][j].x,G[k - 1].first,nx[i][j].x,G[k].first});
                }
                las = j + 1;
            }
        }
    }
    // sort(lis + 1,lis + 1 + lsc);
    // vector <int> H;
    // for(int my = -1,i = 1;i <= lsc;i ++){
    //     H.push_back(lis[i].yl); H.push_back(lis[i].yr);
    //     my = max(my,lis[i].yr);
    //     if(i == lsc || lis[i + 1].x != lis[i].x || lis[i + 1].yl > my){
    //         sort(H.begin(),H.end());
    //         H.erase(unique(H.begin(),H.end()),H.end());
    //         for(int j = 1;j < H.size();j ++) ans.push_back({lis[i].x,H[j - 1],lis[i].x,H[j]});
    //         my = 0; H.clear();
    //     }
    // }

    if(ans.size() != n - 1) cout << ans.size() << endl;
    cout << "YES\n";
    for(auto [a,b,c,d] : ans) cout << a << ' ' << b << ' ' << c << ' ' << d << '\n';
}

int main(){
    ios::sync_with_stdio(false);
    solve();
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 2ms
memory: 19160kb

input:

3
1 0 3
10 10 6
0 5 1

output:

YES
0 0 0 5
4 0 4 10

result:

ok answer = 1

Test #2:

score: 0
Accepted
time: 1ms
memory: 17776kb

input:

2
1 1 1
3 3 1

output:

YES
2 1 2 3

result:

ok answer = 1

Test #3:

score: 0
Accepted
time: 0ms
memory: 18716kb

input:

5
10 10 10
2 0 1
20 20 1
3 20 1
20 0 1

output:

YES
1 0 1 10
2 10 2 20
19 0 19 10
19 10 19 20

result:

ok answer = 1

Test #4:

score: -100
Wrong Answer
time: 1ms
memory: 17804kb

input:

10
29 29 2
28 55 10
99 81 4
17 82 10
45 88 10
48 68 10
0 8 10
98 95 10
34 0 10
17 24 10

output:

YES
58 68 88 95
27 24 27 29
35 24 35 88
18 55 18 55
38 0 38 68
7 24 7 82
7 82 7 88
95 68 95 81
24 0 24 81

result:

wrong answer Segment is degenerate