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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#123206 | #6726. Turn It Off | lhzawa | AC ✓ | 13ms | 3824kb | C++14 | 1001b | 2023-07-11 21:11:08 | 2023-07-11 21:11:09 |
Judging History
answer
// lhzawa(https://www.cnblogs.com/lhzawa/)
// Problem: E. Turn It Off
// Contest: QOJ - The 2019 ICPC China Shaanxi Provincial Programming Contest
// URL: https://qoj.ac/contest/1285/problem/6726
// Memory Limit: 256 MB
// Time Limit: 1000 ms
//
// Powered by CP Editor (https://cpeditor.org)
#include<bits/stdc++.h>
using namespace std;
const int N = 2e5 + 10;
char s[N];
int main() {
function<void ()> solve = []() -> void {
int n, k;
scanf("%d%d%s", &n, &k, s + 1);
int l = 1, r = n, ans = n;
function<int (int)> check = [&n, &k](int l) -> int {
int c = 0;
for (int i = 1; i <= n; ) {
if (s[i] == '1') {
i += l, c++;
}
else {
i++;
}
}
return c <= k;
};
for (; l <= r; ) {
int mid = (l + r) >> 1;
if (check(mid)) {
ans = mid, r = mid - 1;
}
else {
l = mid + 1;
}
}
printf("%d\n", ans);
return ;
};
int _;
scanf("%d", &_);
for (; _; _--) {
solve();
}
return 0;
}
这程序好像有点Bug,我给组数据试试?
详细
Test #1:
score: 100
Accepted
time: 1ms
memory: 3640kb
input:
2 10 4 0101011111 3 1 010
output:
3 1
result:
ok 2 number(s): "3 1"
Test #2:
score: 0
Accepted
time: 13ms
memory: 3824kb
input:
1109 47 36 11101110101001111110101101100001000011101001011 6 5 100010 35 26 00011111000000101010011010100101111 71 45 11101001000111011101101000000000010001100100110000001000011011001011000 32 23 00000100011110010101000110010110 36 30 110110000000000011010001100011111100 21 8 010000011010011101100 9...
output:
1 1 1 1 1 1 2 4 10 2 2 3 3 1 2 1 1 1 1 2 2 2 6 7 1 1 1 1 1 1 1 3 1 1 2 3 1 1 3 1 1 6 1 1 5 1 1 3 10 19 1 1 1 4 1 1 2 1 2 1 1 2 1 1 60 17 3 3 2 2 1 1 4 1 1 1 1 1 2 2 1 3 5 2 1 1 4 2 1 1 3 1 1 1 1 1 5 2 3 1 2 1 1 1 1 2 1 1 2 1 1 81 1 4 1 1 1 2 1 44 1 5 2 3 1 1 1 2 1 8 1 1 3 1 1 2 1 46 1 1 1 1 1 1 1 1 ...
result:
ok 1109 numbers