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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#118026 | #6683. Difficult Constructive Problem | UndertrainedOverpressure# | AC ✓ | 124ms | 5064kb | C++20 | 6.0kb | 2023-07-02 22:03:49 | 2023-07-02 22:03:53 |
Judging History
answer
/*
author: Maksim1744
created: 02.07.2023 16:47:17
*/
#include "bits/stdc++.h"
using namespace std;
using ll = long long;
using ld = long double;
#define mp make_pair
#define pb push_back
#define eb emplace_back
#define sum(a) ( accumulate ((a).begin(), (a).end(), 0ll))
#define mine(a) (*min_element((a).begin(), (a).end()))
#define maxe(a) (*max_element((a).begin(), (a).end()))
#define mini(a) ( min_element((a).begin(), (a).end()) - (a).begin())
#define maxi(a) ( max_element((a).begin(), (a).end()) - (a).begin())
#define lowb(a, x) ( lower_bound((a).begin(), (a).end(), (x)) - (a).begin())
#define uppb(a, x) ( upper_bound((a).begin(), (a).end(), (x)) - (a).begin())
template<typename T> vector<T>& operator-- (vector<T> &v){for (auto& i : v) --i; return v;}
template<typename T> vector<T>& operator++ (vector<T> &v){for (auto& i : v) ++i; return v;}
template<typename T> istream& operator>>(istream& is, vector<T> &v){for (auto& i : v) is >> i; return is;}
template<typename T> ostream& operator<<(ostream& os, vector<T> v){for (auto& i : v) os << i << ' '; return os;}
template<typename T, typename U> pair<T,U>& operator-- (pair<T, U> &p){--p.first; --p.second; return p;}
template<typename T, typename U> pair<T,U>& operator++ (pair<T, U> &p){++p.first; ++p.second; return p;}
template<typename T, typename U> istream& operator>>(istream& is, pair<T, U> &p){is >> p.first >> p.second; return is;}
template<typename T, typename U> ostream& operator<<(ostream& os, pair<T, U> p){os << p.first << ' ' << p.second; return os;}
template<typename T, typename U> pair<T,U> operator-(pair<T,U> a, pair<T,U> b){return mp(a.first-b.first, a.second-b.second);}
template<typename T, typename U> pair<T,U> operator+(pair<T,U> a, pair<T,U> b){return mp(a.first+b.first, a.second+b.second);}
template<typename T, typename U> void umin(T& a, U b){if (a > b) a = b;}
template<typename T, typename U> void umax(T& a, U b){if (a < b) a = b;}
#ifdef HOME
#define SHOW_COLORS
#include "/mnt/c/Libs/tools/print.cpp"
#else
#define show(...) void(0)
#define debugf(fun) fun
#define debugv(var) var
#define mclock void(0)
#define shows void(0)
#define debug if (false)
#define OSTREAM(...) ;
#define OSTREAM0(...) ;
#endif
void test_case(int test) {
int n, kk;
cin >> n >> kk;
string ss;
cin >> ss;
string best;
for (int c0 = 0; c0 < 2; ++c0) {
if (ss[0] != '?' && ss[0] != '0' + c0) continue;
for (int c1 = 0; c1 < 2; ++c1) {
if (ss.back() != '?' && ss.back() != '0' + c1) continue;
if (n == 1 && c0 != c1) continue;
auto s = ss;
int k = kk;
s[0] = c0 + '0';
s.back() = c1 + '0';
for (int i = 0; i < n - 1; ++i) {
if (s.substr(i, 2) == "01" || s.substr(i, 2) == "10")
--k;
}
if (k < 0) continue;
array<multiset<int>, 2> sets = {};
array<int, 2> sums = {};
auto trans = [&](int& len, int par) {
if (par == 0) {
len = (len - 1) / 2 * 2 + 2;
} else {
len = len / 2 * 2 + 1;
}
};
auto add = [&](int len, int par) {
if (len == 0) return;
trans(len, par);
sets[par].insert(len);
sums[par] += len;
};
auto rem = [&](int len, int par) {
if (len == 0) return;
trans(len, par);
sets[par].erase(sets[par].find(len));
sums[par] -= len;
};
vector<int> r(n);
for (int i = n - 1; i >= 0; --i) {
if (s[i] == '?') r[i] = r[i + 1];
else r[i] = i;
}
for (int i = 1; i < n; ++i) {
if (s[i - 1] != '?' && s[i] == '?')
add(r[i] - i, s[r[i]] != s[i - 1]);
}
auto can = [&]() {
if (k < 0) return false;
int ss = sums[0] + sums[1];
if (ss % 2 != k % 2) return false;
return ss >= k && sets[1].size() <= k;
};
shows;
if (!can()) {
continue;
}
show(s);
show(k);
show(sets);
show(sums);
show(r);
for (int i = 0; i < n; ++i) {
show(i);
if (s[i] != '?') {
continue;
}
bool ok = false;
show(sets, sums, k, s);
for (int c = 0; c < 2; ++c) {
rem(r[i] - i, s[r[i]] != s[i - 1]);
s[i] = '0' + c;
add(r[i] - i - 1, s[r[i]] != s[i]);
if (s[i] != s[i - 1]) --k;
if (s[i] != s[i + 1] && s[i + 1] != '?') --k;
if (can()) {
ok = true;
break;
}
if (s[i] != s[i - 1]) ++k;
if (s[i] != s[i + 1] && s[i + 1] != '?') ++k;
rem(r[i] - i - 1, s[r[i]] != s[i]);
s[i] = '?';
add(r[i] - i, s[r[i]] != s[i - 1]);
}
assert(ok);
}
assert(k == 0);
if (best.empty() || s < best)
best = s;
}
}
if (best.empty()) {
cout << "Impossible\n";
} else {
cout << best << '\n';
}
}
int main() {
ios_base::sync_with_stdio(false); cin.tie(NULL);
int T;
cin >> T;
for (int test = 1; test <= T; ++test) {
test_case(test);
}
return 0;
}
这程序好像有点Bug,我给组数据试试?
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 3460kb
input:
5 9 6 1?010??01 9 5 1?010??01 9 6 100101101 9 5 100101101 9 3 ????????1
output:
100100101 Impossible 100101101 Impossible 000000101
result:
ok 5 lines
Test #2:
score: 0
Accepted
time: 124ms
memory: 5064kb
input:
6110 2 0 01 9 5 ????110?? 18 8 ???111???00??010?? 11 8 001??01???0 2 0 00 8 1 ?????111 11 2 110???01??? 13 7 ??100???01??1 6 2 ?????0 18 8 110??11??011??110? 12 5 00??011??00? 20 10 ??01???0011???0010?? 1 0 ? 13 6 ???10??110??0 6 2 00???1 17 10 ??010??001???11?? 5 2 ????0 14 7 010???00???11? 2 1 01 ...
output:
Impossible 001011001 000111000000101010 00101010010 00 00000111 11000001111 0010000101001 000010 110001100011001101 000001101001 00010000011001001010 0 0001000110010 Impossible 00010010010101100 00010 01000100010111 01 0100100001 Impossible 001100010100100101 00111111000 000 01111001 001000000100010...
result:
ok 6110 lines