QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#117363#6300. Best Carry Player 2memset0WA 0ms3380kbC++201.9kb2023-07-01 02:14:342023-07-01 02:14:35

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-07-01 02:14:35]
  • 评测
  • 测评结果:WA
  • 用时:0ms
  • 内存:3380kb
  • [2023-07-01 02:14:34]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
using ull = unsigned long long;
const int N = 25, n = 18;
int T, k, a[N];
ull x, f[N], dp[N][N];
inline void chkmin(ull &x, ull y) {
  if (y < x) x = y;
}
inline ull pick(int l, int r) {
  ull s = 0;
  for (int i = l; i <= r; i++) {
    s = s * 10 + a[i];
  }
  return s;
}
int main() {
#ifdef memset0
  freopen("1.in", "r", stdin);
#endif
  cin >> T;
  f[0] = 1;
  for (int i = 1; i <= n + 1; i++) f[i] = f[i - 1] * 10;
  while (T--) {
    memset(a, 0, sizeof(a));
    memset(dp, 63, sizeof(dp));
    cin >> x >> k;
    for (int i = 1; i <= n; i++) {
      a[i] = x % 10;
      x /= 10;
    }

    if (k == 0) {
      ull y = 1;
      for (int i = 1; i <= n + 1; i++)
        if (a[i] < 9) {
          cout << y << endl;
          break;
        } else {
          y *= 10;
        }
      continue;
    }

    for (int i = 1; i <= n; i++)
      if (a[i]) {
        int d = 0;
        while (a[i + d + 1] == 9) ++d;
        dp[i + d][1 + d] = f[i - 1] * (10 - a[i]);
      }
    for (int i = 1; i <= n; i++)
      for (int j = 0; j < k; j++)
        if (dp[i][j] != dp[0][0]) {
          for (int v = i + 1; v <= n; v++) {
            int x = v == i + 1 ? a[v] + 1 : a[v];
            if (!x) continue;
            int d = 0;
            while (a[v + d + 1] == 9) ++d;
            chkmin(dp[v + d][j + d + 1], dp[i][j] + f[v - 1] * (10 - x));
            // fprintf(stderr, "dp[%d][%d] -> dp[%d][%d](%d) : %llu + %llu * %d : %llu\n", i, j, v + d, j + d + 1, d, dp[i][j], f[v - 1], 10 - x, dp[v + d][j + d + 1]);
          }
        }

    // for (int i = 1; i <= n; i++)
    //   for (int j = 1; j <= k; j++)
    //     if (dp[i][j] != dp[0][0]) {
    //       printf("dp[%d][%d] = %llu\n", i, j, dp[i][j]);
    //     }

    ull ans = dp[0][0];
    for (int i = 1; i <= n; i++) {
      chkmin(ans, dp[i][k]);
    }
    cout << ans << endl;
  }
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 3376kb

input:

4
12345678 0
12345678 5
12345678 18
990099 5

output:

1
54322
999999999987654322
9910

result:

ok 4 lines

Test #2:

score: -100
Wrong Answer
time: 0ms
memory: 3380kb

input:

21
999990000099999 0
999990000099999 1
999990000099999 2
999990000099999 3
999990000099999 4
999990000099999 5
999990000099999 6
999990000099999 7
999990000099999 8
999990000099999 9
999990000099999 10
999990000099999 11
999990000099999 12
999990000099999 13
999990000099999 14
999990000099999 15
999...

output:

100000
10000
1000
100
10
1
900001
9900001
99900001
999900001
10000000001
9999910000
9999901000
9999900100
9999900010
9999900001
9000009999900001
99000009999900001
999000009999900001
4557430888798830399
1000000000000000000

result:

wrong answer 20th lines differ - expected: '99999999999999999900000000000000000', found: '4557430888798830399'