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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#116506#4885. Triangular Cactus Pathshos_lyricTL 6ms98768kbC++1412.1kb2023-06-29 13:40:032023-06-29 13:40:04

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-06-29 13:40:04]
  • 评测
  • 测评结果:TL
  • 用时:6ms
  • 内存:98768kb
  • [2023-06-29 13:40:03]
  • 提交

answer

#include <cassert>
#include <cmath>
#include <cstdint>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <algorithm>
#include <bitset>
#include <complex>
#include <deque>
#include <functional>
#include <iostream>
#include <limits>
#include <map>
#include <numeric>
#include <queue>
#include <set>
#include <sstream>
#include <string>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>

using namespace std;

using Int = long long;

template <class T1, class T2> ostream &operator<<(ostream &os, const pair<T1, T2> &a) { return os << "(" << a.first << ", " << a.second << ")"; };
template <class T> ostream &operator<<(ostream &os, const vector<T> &as) { const int sz = as.size(); os << "["; for (int i = 0; i < sz; ++i) { if (i >= 256) { os << ", ..."; break; } if (i > 0) { os << ", "; } os << as[i]; } return os << "]"; }
template <class T> void pv(T a, T b) { for (T i = a; i != b; ++i) cerr << *i << " "; cerr << endl; }
template <class T> bool chmin(T &t, const T &f) { if (t > f) { t = f; return true; } return false; }
template <class T> bool chmax(T &t, const T &f) { if (t < f) { t = f; return true; } return false; }

////////////////////////////////////////////////////////////////////////////////
template <unsigned M_> struct ModInt {
  static constexpr unsigned M = M_;
  unsigned x;
  constexpr ModInt() : x(0U) {}
  constexpr ModInt(unsigned x_) : x(x_ % M) {}
  constexpr ModInt(unsigned long long x_) : x(x_ % M) {}
  constexpr ModInt(int x_) : x(((x_ %= static_cast<int>(M)) < 0) ? (x_ + static_cast<int>(M)) : x_) {}
  constexpr ModInt(long long x_) : x(((x_ %= static_cast<long long>(M)) < 0) ? (x_ + static_cast<long long>(M)) : x_) {}
  ModInt &operator+=(const ModInt &a) { x = ((x += a.x) >= M) ? (x - M) : x; return *this; }
  ModInt &operator-=(const ModInt &a) { x = ((x -= a.x) >= M) ? (x + M) : x; return *this; }
  ModInt &operator*=(const ModInt &a) { x = (static_cast<unsigned long long>(x) * a.x) % M; return *this; }
  ModInt &operator/=(const ModInt &a) { return (*this *= a.inv()); }
  ModInt pow(long long e) const {
    if (e < 0) return inv().pow(-e);
    ModInt a = *this, b = 1U; for (; e; e >>= 1) { if (e & 1) b *= a; a *= a; } return b;
  }
  ModInt inv() const {
    unsigned a = M, b = x; int y = 0, z = 1;
    for (; b; ) { const unsigned q = a / b; const unsigned c = a - q * b; a = b; b = c; const int w = y - static_cast<int>(q) * z; y = z; z = w; }
    assert(a == 1U); return ModInt(y);
  }
  ModInt operator+() const { return *this; }
  ModInt operator-() const { ModInt a; a.x = x ? (M - x) : 0U; return a; }
  ModInt operator+(const ModInt &a) const { return (ModInt(*this) += a); }
  ModInt operator-(const ModInt &a) const { return (ModInt(*this) -= a); }
  ModInt operator*(const ModInt &a) const { return (ModInt(*this) *= a); }
  ModInt operator/(const ModInt &a) const { return (ModInt(*this) /= a); }
  template <class T> friend ModInt operator+(T a, const ModInt &b) { return (ModInt(a) += b); }
  template <class T> friend ModInt operator-(T a, const ModInt &b) { return (ModInt(a) -= b); }
  template <class T> friend ModInt operator*(T a, const ModInt &b) { return (ModInt(a) *= b); }
  template <class T> friend ModInt operator/(T a, const ModInt &b) { return (ModInt(a) /= b); }
  explicit operator bool() const { return x; }
  bool operator==(const ModInt &a) const { return (x == a.x); }
  bool operator!=(const ModInt &a) const { return (x != a.x); }
  friend std::ostream &operator<<(std::ostream &os, const ModInt &a) { return os << a.x; }
};
////////////////////////////////////////////////////////////////////////////////

constexpr unsigned MO = 998244353;
using Mint = ModInt<MO>;

constexpr int LIM_INV = 400'010;
Mint inv[LIM_INV], fac[LIM_INV], invFac[LIM_INV];

void prepare() {
  inv[1] = 1;
  for (int i = 2; i < LIM_INV; ++i) {
    inv[i] = -((Mint::M / i) * inv[Mint::M % i]);
  }
  fac[0] = invFac[0] = 1;
  for (int i = 1; i < LIM_INV; ++i) {
    fac[i] = fac[i - 1] * i;
    invFac[i] = invFac[i - 1] * inv[i];
  }
}
Mint binom(Int n, Int k) {
  if (n < 0) {
    if (k >= 0) {
      return ((k & 1) ? -1 : +1) * binom(-n + k - 1, k);
    } else if (n - k >= 0) {
      return (((n - k) & 1) ? -1 : +1) * binom(-k - 1, n - k);
    } else {
      return 0;
    }
  } else {
    if (0 <= k && k <= n) {
      assert(n < LIM_INV);
      return fac[n] * invFac[k] * invFac[n - k];
    } else {
      return 0;
    }
  }
}


#ifndef LIBRA_GRAPH_GRAPH_H_
#define LIBRA_GRAPH_GRAPH_H_

#include <assert.h>
#include <ostream>
#include <utility>
#include <vector>

using std::ostream;
using std::pair;
using std::vector;

////////////////////////////////////////////////////////////////////////////////
// neighbors of u: [pt[u], pt[u + 1])
struct Graph {
  int n;
  vector<pair<int, int>> edges;
  vector<int> pt;
  vector<int> zu;

  Graph() : n(0), edges() {}
  explicit Graph(int n_) : n(n_), edges() {}
  void ae(int u, int v) {
    assert(0 <= u); assert(u < n);
    assert(0 <= v); assert(v < n);
    edges.emplace_back(u, v);
  }
  void build(bool directed) {
    const int edgesLen = edges.size();
    pt.assign(n + 1, 0);
    if (directed) {
      for (int i = 0; i < edgesLen; ++i) {
        ++pt[edges[i].first];
      }
      for (int u = 0; u < n; ++u) pt[u + 1] += pt[u];
      zu.resize(edgesLen);
      for (int i = edgesLen; --i >= 0; ) {
        zu[--pt[edges[i].first]] = edges[i].second;
      }
    } else {
      for (int i = 0; i < edgesLen; ++i) {
        ++pt[edges[i].first];
        ++pt[edges[i].second];
      }
      for (int u = 0; u < n; ++u) pt[u + 1] += pt[u];
      zu.resize(2 * edgesLen);
      for (int i = edgesLen; --i >= 0; ) {
        const int u = edges[i].first, v = edges[i].second;
        zu[--pt[u]] = v;
        zu[--pt[v]] = u;
      }
    }
  }

  inline int deg(int u) const {
    return pt[u + 1] - pt[u];
  }
  inline int operator[](int j) const {
    return zu[j];
  }
  friend ostream &operator<<(ostream &os, const Graph &g) {
    os << "Graph(n=" << g.n << ";";
    for (int u = 0; u < g.n; ++u) {
      os << " " << u << ":[";
      for (int j = g.pt[u]; j < g.pt[u + 1]; ++j) {
        if (j != g.pt[u]) os << ",";
        os << g[j];
      }
      os << "]";
    }
    os << ")";
    return os;
  }
};
////////////////////////////////////////////////////////////////////////////////

#endif  // LIBRA_GRAPH_GRAPH_H_


// gg: bipartite graph between {vertex} and {biconnected component}
//   (gg.n - n) biconnected components
//   isolated point: not regarded as biconnected component (==> isolated in gg)
// f: DFS forest
struct Biconnected {
  int n;
  Graph g, f, gg;

  Biconnected() : n(0), stackLen(0), zeit(0) {}
  explicit Biconnected(int n_) : n(n_), g(n_), stackLen(0), zeit(0) {}
  void ae(int u, int v) {
    g.ae(u, v);
  }

  int stackLen;
  vector<int> stack;
  vector<int> par, rs;
  int zeit;
  vector<int> dis, fin, low;
  vector<int> cntPar;
  void dfs(int u) {
    stack[stackLen++] = u;
    dis[u] = low[u] = zeit++;
    for (int j = g.pt[u]; j < g.pt[u + 1]; ++j) {
      const int v = g[j];
      if (par[u] == v && !cntPar[u]++) continue;
      if (~dis[v]) {
        if (low[u] > dis[v]) low[u] = dis[v];
      } else {
        f.ae(u, v);
        par[v] = u;
        rs[v] = rs[u];
        dfs(v);
        if (low[u] > low[v]) low[u] = low[v];
        if (dis[u] <= low[v]) {
          const int x = gg.n++;
          for (; ; ) {
            const int w = stack[--stackLen];
            gg.ae(w, x);
            if (w == v) break;
          }
          gg.ae(u, x);
        }
      }
    }
    fin[u] = zeit;
  }
  void build() {
    g.build(false);
    f = Graph(n);
    gg = Graph(n);
    stack.resize(n);
    par.assign(n, -1);
    rs.assign(n, -1);
    zeit = 0;
    dis.assign(n, -1);
    fin.assign(n, -1);
    low.assign(n, -1);
    cntPar.assign(n, 0);
    for (int u = 0; u < n; ++u) if (!~dis[u]) {
      stackLen = 0;
      rs[u] = u;
      dfs(u);
    }
    f.build(true);
    gg.build(false);
  }

  // Returns true iff u is an articulation point
  //   <=> # of connected components increases when u is removed.
  inline bool isArt(int u) const {
    return (gg.deg(u) >= 2);
  }

  // Returns w s.t. w is a child of u and a descendant of v in the DFS forest.
  // Returns -1 instead if v is not a proper descendant of u
  //   O(log(deg(u))) time
  int dive(int u, int v) const {
    if (dis[u] < dis[v] && dis[v] < fin[u]) {
      int j0 = f.pt[u], j1 = f.pt[u + 1];
      for (; j0 + 1 < j1; ) {
        const int j = (j0 + j1) / 2;
        ((dis[f[j]] <= dis[v]) ? j0 : j1) = j;
      }
      return f[j0];
    } else {
      return -1;
    }
  }
  // Returns true iff there exists a v-w path when u is removed.
  //   O(log(deg(u))) time
  bool isStillReachable(int u, int v, int w) const {
    assert(0 <= u); assert(u < n);
    assert(0 <= v); assert(v < n);
    assert(0 <= w); assert(w < n);
    assert(u != v);
    assert(u != w);
    if (rs[v] != rs[w]) return false;
    if (rs[u] != rs[v]) return true;
    const int vv = dive(u, v);
    const int ww = dive(u, w);
    if (~vv) {
      if (~ww) {
        return (vv == ww || (dis[u] > low[vv] && dis[u] > low[ww]));
      } else {
        return (dis[u] > low[vv]);
      }
    } else {
      if (~ww) {
        return (dis[u] > low[ww]);
      } else {
        return true;
      }
    }
  }
};

////////////////////////////////////////////////////////////////////////////////


int N, M;
vector<int> A, B;

Biconnected C;

constexpr int E = 19;
constexpr int MAX_N = 400'010;
int dep[MAX_N];
int ppar[E][MAX_N];
int sum2[E][MAX_N];
int sum3[E][MAX_N];

void dfs(int u, int p) {
  dep[u] = (~p) ? (dep[p] + 1) : 0;
  ppar[0][u] = p;
  for (int j = C.gg.pt[u]; j < C.gg.pt[u + 1]; ++j) {
    const int v = C.gg[j];
    if (p != v) {
      dfs(v, u);
    }
  }
}

int lca(int u, int v) {
  for (int e = E; --e >= 0; ) {
    if (dep[u] - (1 << e) >= dep[v]) {
      u = ppar[e][u];
    }
    if (dep[v] - (1 << e) >= dep[u]) {
      v = ppar[e][v];
    }
  }
  for (int e = E; --e >= 0; ) {
    if (ppar[e][u] != ppar[e][v]) {
      u = ppar[e][u];
      v = ppar[e][v];
    }
  }
  if (u != v) {
    u = ppar[0][u];
    v = ppar[0][v];
  }
  return u;
}

int main() {
  prepare();
  
  for (; ~scanf("%d%d", &N, &M); ) {
    A.resize(M);
    B.resize(M);
    for (int i = 0; i < M; ++i) {
      scanf("%d%d", &A[i], &B[i]);
      --A[i];
      --B[i];
    }
    
    C = Biconnected(N);
    for (int i = 0; i < M; ++i) {
      C.ae(A[i], B[i]);
    }
    C.build();
cerr<<"gg = "<<C.gg<<endl;
    
    fill(dep, dep + C.gg.n, -1);
    for (int u = 0; u < C.gg.n; ++u) if (!~dep[u]) {
      dfs(u, -1);
    }
    fill(sum2[0], sum2[0] + C.gg.n, 0);
    for (int u = N; u < C.gg.n; ++u) {
      ((C.gg.deg(u) == 2) ? sum2 : sum3)[0][u] = 1;
    }
    for (int e = 0; e < E - 1; ++e) {
      for (int u = 0; u < C.gg.n; ++u) {
        const int p = ppar[e][u];
        if (~p) {
          ppar[e + 1][u] = ppar[e][p];
          sum2[e + 1][u] = sum2[e][u] + sum2[e][p];
          sum3[e + 1][u] = sum3[e][u] + sum3[e][p];
        } else {
          ppar[e + 1][u] = -1;
          sum2[e + 1][u] = sum2[e][u];
          sum3[e + 1][u] = sum3[e][u];
        }
      }
    }
    
    int Q;
    scanf("%d", &Q);
    for (; Q--; ) {
      int S, T, K;
      scanf("%d%d%d", &S, &T, &K);
      --S;
      --T;
      
      int s2 = 0, s3 = 0;
      auto add = [&](int u, int d) -> void {
        for (int e = E; --e >= 0; ) if (d >> e & 1) {
          s2 += sum2[e][u];
          s3 += sum3[e][u];
          u = ppar[e][u];
        }
      };
      const int l = lca(S, T);
      add(S, dep[S] - dep[l]);
      add(T, dep[T] - dep[l]);
      if (l >= N) {
        ++((C.gg.deg(l) == 2) ? s2 : s3);
      }
cerr<<"s2 = "<<s2<<", s3 = "<<s3<<endl;
      Mint ans = 0;
      if (s2 + s3 <= K && K <= s2 + 2 * s3) {
        ans = binom(s3, K - (s2 + s3));
      }
      printf("%u\n", ans.x);
    }
  }
  return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 6ms
memory: 97472kb

input:

8 10
1 2
2 3
3 1
3 4
4 5
5 6
6 4
4 7
7 8
8 4
6
1 1 0
1 1 1
1 4 3
6 2 4
5 7 4
3 4 2

output:

1
0
1
2
1
0

result:

ok 6 numbers

Test #2:

score: 0
Accepted
time: 1ms
memory: 98768kb

input:

2 1
1 2
8
1 1 0
1 1 1
1 2 0
1 2 1
2 1 0
2 1 1
2 2 0
2 2 1

output:

1
0
0
1
0
1
1
0

result:

ok 8 numbers

Test #3:

score: -100
Time Limit Exceeded

input:

50 70
41 24
9 15
29 19
21 11
1 14
5 27
34 48
10 32
34 49
46 3
22 33
34 39
16 30
22 45
7 16
25 30
43 17
22 44
5 25
41 49
29 32
39 25
10 4
45 27
13 38
29 7
3 35
14 30
50 2
8 11
13 35
18 26
34 40
38 36
7 19
12 3
25 26
30 42
21 8
12 46
44 33
14 31
47 2
25 46
20 19
49 24
15 43
18 25
13 36
27 22
4 32
30 3...

output:

0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
1
0
0
0
0
0
0
0
0
0
0
3
0
0
0
0
0
4
0
0
15
5
0
1
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
10
2
0
0
0
0
0
6
0
0
0
0
0
0
0
0
7
0
0
0
0
3
0
6
0
0
0
0
7
0
6
0
0
0
0
0
0
1
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
15
0
0
0
0
0
0
0
1
0
0
0
0
0
0
0
0
0
0
0
0...

result: