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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#115930#5301. Modulo Ruins the LegendPetroTarnavskyi#WA 27ms5076kbC++172.1kb2023-06-27 18:51:282023-06-27 18:51:29

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-06-27 18:51:29]
  • 评测
  • 测评结果:WA
  • 用时:27ms
  • 内存:5076kb
  • [2023-06-27 18:51:28]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;

#define SZ(a) (int)a.size()
#define ALL(a) a.begin(), a.end()
#define FOR(i, a, b) for (int i = (a); i<(b); ++i)
#define RFOR(i, b, a) for (int i = (b)-1; i>=(a); --i)
#define MP make_pair
#define PB push_back
#define F first
#define S second

typedef long long LL;
typedef pair<int, int> PII;
typedef vector<int> VI;

map<VI, int> m;
map<VI, PII> op;

void brute(int n)
{
	VI v(n);
	iota(ALL(v), 1);
	m[v] = 0;
	queue<VI> q;
	q.push(v);
	while (!q.empty())
	{
		auto b = q.front();
		q.pop();
		int a = m[b];
		FOR (x, 1, n - 2)
		{
			FOR (y, 1, n - x)
			{
				VI vec;
				FOR (i, 0, y) vec.PB(b[n - y + i]);
				FOR (i, x, n - y) vec.PB(b[i]);
				FOR (i, 0, x) vec.PB(b[i]);
				if (!m.count(vec))
				{
					m[vec] = a + 1;
					op[vec] = {y, x};
					q.push(vec);
				}
			}
		}
	}
}

vector<PII> oper;

void solve(int realN, VI a, VI sz)
{
	int n = SZ(a);
	if (SZ(a) <= 7)
	{
		while (m[a] != 0)
		{
			PII p = op[a];
			int x = 0, y = 0;
			FOR (i, 0, p.first) x += sz[i];
			FOR (i, 0, p.second) y += sz[SZ(a) - 1 - i];
			oper.PB({x, y});
			
			VI na, nsz;
			FOR (i, 0, p.second)
			{
				na.PB(a[n - p.second]);
				nsz.PB(sz[n - p.second]);
			}
			FOR (i, p.first, n - p.second)
			{ 
				na.PB(a[i]);
				nsz.PB(sz[n - p.second]);
			}
			FOR (i, 0, p.first)
			{
				na.PB(a[i]);
				nsz.PB(sz[n - p.second]);
			}
			a = na;
			sz = nsz;
		}
		return;
	}
	RFOR (i, n - 2, n - 5)
	{
		if (a[i] == realN) continue;
		FOR (j, 0, i)
		{
			if (a[j] == a[i] + 1)
			{
				// 
			}
		}
	}
	
}

int main()
{
	ios::sync_with_stdio(false);
	cin.tie(0);
	for (int i = 4; i <= 7; i++) brute(i);
	
	int t;
	cin >> t;
	while (t--)
	{
		int n;
		cin >> n;
		VI a(n);
		FOR (i, 0, n) cin >> a[i];
		if (n == 3)
		{
			if (a[2] < a[0])
				cout << "1\n1 1\n";
			else
				cout << "0\n";
			continue;
		}
		VI sz(n, 1);
		solve(n, a, sz);
		cout << SZ(oper) << '\n';
		FOR (i, 0, SZ(oper))
		{
			cout << oper[i].first << ' ' << oper[i].second << '\n';
		}
	}
	
	return 0;
}


详细

Test #1:

score: 0
Wrong Answer
time: 27ms
memory: 5076kb

input:

6 24
1 1 4 5 1 4

output:

0
0
0
0
0
0

result:

wrong answer Result not equal to solution.