QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#114217#6626. Real Mountainsruizhangj0 2ms6120kbC++141.9kb2023-06-21 15:46:242023-06-21 15:46:28

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-06-21 15:46:28]
  • 评测
  • 测评结果:0
  • 用时:2ms
  • 内存:6120kb
  • [2023-06-21 15:46:24]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N=1e6+5;
int a[N],n,p=-1;
map<int,pair<vector<int>,vector<int>>> b;
int tr[4*N];
void build(int x,int l,int r){
    if (l==r){
        tr[x]=a[l];
        return;
    }
    int mid=(l+r)>>1;
    build(x<<1,l,mid);
    build(x<<1|1,mid+1,r);
    tr[x]=min(tr[x<<1],tr[x<<1|1]);
}
int query(int x,int l,int r,int L,int R){
    if (L<=l && r<=R) return tr[x];
    int mid=(l+r)>>1;
    if (R<=mid) return query(x<<1,l,mid,L,R);
    if (L>mid) return query(x<<1|1,mid+1,r,L,R);
    return min(query(x<<1,l,mid,L,R),query(x<<1|1,mid+1,r,L,R));
}
void modify(int x,int l,int r,int p,int v){
    if (l==r){
        tr[x]=v;
        return;
    }
    int mid=(l+r)>>1;
    if (p<=mid) modify(x<<1,l,mid,p,v);
    else modify(x<<1|1,mid+1,r,p,v);
    tr[x]=min(tr[x<<1],tr[x<<1|1]);
}
set<int> s;
int main(){
    // freopen("a.in","r",stdin);
    scanf("%d",&n);
    for (int i=1;i<=n;++i){
        scanf("%d",&a[i]);
        if (p==-1 || a[i]>a[p]) p=i;
        b[a[i]].first.emplace_back(i);
    }
    for (int i=1,mx=0;i<=p;++i){
        mx=max(mx,a[i]);
        b[mx].second.emplace_back(i);
    }
    for (int i=n,mx=0;i>p;--i){
        mx=max(mx,a[i]);
        b[mx].second.emplace_back(i);
    }
    build(1,1,n);
    ll ans=0;
    for (auto it=b.begin();it!=b.end();++it){
        auto obj=*it;
        ll h=obj.first;
        for (auto x:obj.second.first) s.emplace(x);
        for (auto x:obj.second.second) s.erase(x),modify(1,1,n,x,1e9);
        if (next(it)==b.end()) break;
        ll v=next(it)->first;
        if (!s.size()) continue;
        ll x=query(1,1,n,1,*s.begin()-1),y=query(1,1,n,*prev(s.end())+1,n);
        if (s.size()==1) ans+=(v-h)*(x+y)+(h+v-1)*(v-h)/2;
        else ans+=(v-h)*(max(x,y)+2*min(x,y)+1+2*(s.size()-2))+(3+3*(s.size()-2))*(h+v-1)*(v-h)/2;
    }
    printf("%lld\n",ans);
    return 0;
}

详细

Subtask #1:

score: 0
Wrong Answer

Test #1:

score: 3
Accepted
time: 2ms
memory: 5672kb

input:

3
29 9 9

output:

0

result:

ok 1 number(s): "0"

Test #2:

score: 0
Accepted
time: 1ms
memory: 5788kb

input:

3
62 20 71

output:

7287

result:

ok 1 number(s): "7287"

Test #3:

score: 0
Accepted
time: 1ms
memory: 5740kb

input:

10
72 33 22 22 13 49 53 57 72 85

output:

40403

result:

ok 1 number(s): "40403"

Test #4:

score: -3
Wrong Answer
time: 1ms
memory: 6120kb

input:

5000
100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 99 99 99 99 99 99 99 99 99 99 99 99 99 99 99 99 99 99 99 99 99 99 99 99 99 99 98 98 98 98 98 98 98 98 98 98 98 98 98 98 98 98 98 98 98 98 98 98 98 98 97 97 97 97 9...

output:

49481200

result:

wrong answer 1st numbers differ - expected: '481053', found: '49481200'

Subtask #2:

score: 0
Skipped

Dependency #1:

0%

Subtask #3:

score: 0
Skipped

Dependency #2:

0%

Subtask #4:

score: 0
Skipped

Dependency #3:

0%

Subtask #5:

score: 0
Skipped

Dependency #2:

0%

Subtask #6:

score: 0
Skipped

Dependency #3:

0%

Subtask #7:

score: 0
Skipped

Dependency #1:

0%