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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#114079#6644. Red Black GridpropaneWA 22ms3560kbC++202.2kb2023-06-20 21:25:592023-06-20 21:26:00

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-06-20 21:26:00]
  • 评测
  • 测评结果:WA
  • 用时:22ms
  • 内存:3560kb
  • [2023-06-20 21:25:59]
  • 提交

answer

#include<iostream>
#include<cstring>
#include<vector>
using namespace std;
using LL = long long;

int main(){

#ifdef LOCAL
    freopen("data.in", "r", stdin);
    freopen("data.out", "w", stdout);
#endif

    cin.tie(0);
    cout.tie(0);
    ios::sync_with_stdio(0);

    int T;
    cin >> T;
    while(T--){
        int n, k;
        cin >> n >> k;
        
        auto solve = [&](int target){
            int sum = n * (n - 1) * 2;
            vector<vector<int> > a(n, vector<int>(n));
            vector<pair<int, int> > v[5];
            for(int i = 0; i < n; i++){
                for(int j = 0; j < n; j++){
                    if ((i + j) % 2 == target){
                        a[i][j] = 1;
                        int t = 4 - (i == 0 || i == n - 1) - (j == 0 || j == n - 1);
                        v[t].push_back({i, j});
                    }
                }
            }
            for(int i = 0; i <= v[2].size(); i++){
                for(int j = 0; j <= v[3].size(); j++){
                    int need = sum - k - 2 * i - 3 * j;
                    if (need % 4 == 0 && need >= 0 && need / 4 <= v[4].size()){
                        for(int t = 0; t < i; t++){
                            auto [x, y] = v[2][t];
                            a[x][y] = 0;
                        }
                        for(int t = 0; t < j; t++){
                            auto [x, y] = v[3][t];
                            a[x][y] = 0;
                        }
                        for(int t = 0; t < need / 4; t++){
                            auto [x, y] = v[4][t];
                            a[x][y] = 0;
                        }
                        cout << "Possible" << '\n';
                        for(int i = 0; i < n; i++){
                            for(int j = 0; j < n; j++){
                                cout << (a[i][j] ? 'R' : 'B');
                            }
                            cout << '\n';
                        }
                        return true;
                    }
                }
            }
            return false;
        };

        if (!solve(0) && !solve(1)){
            cout << "Impossible" << '\n';
        }
    }

}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 3416kb

input:

2
3 6
3 1

output:

Possible
BBR
BBB
RBR
Impossible

result:

ok correct! (2 test cases)

Test #2:

score: -100
Wrong Answer
time: 22ms
memory: 3560kb

input:

4424
1 0
2 4
2 3
2 2
2 1
2 0
3 12
3 11
3 10
3 9
3 8
3 7
3 6
3 5
3 4
3 3
3 2
3 1
3 0
4 24
4 23
4 22
4 21
4 20
4 19
4 18
4 17
4 16
4 15
4 14
4 13
4 12
4 11
4 10
4 9
4 8
4 7
4 6
4 5
4 4
4 3
4 2
4 1
4 0
5 40
5 39
5 38
5 37
5 36
5 35
5 34
5 33
5 32
5 31
5 30
5 29
5 28
5 27
5 26
5 25
5 24
5 23
5 22
5 21
5...

output:

Possible
R
Possible
RB
BR
Impossible
Possible
BB
BR
Impossible
Possible
BB
BB
Possible
RBR
BRB
RBR
Impossible
Possible
BBR
BRB
RBR
Possible
BBB
RBR
BRB
Possible
RBR
BBB
RBR
Impossible
Possible
BBR
BBB
RBR
Impossible
Possible
BBB
BBB
RBR
Possible
BBB
BBB
BRB
Possible
BBB
BBB
BBR
Impossible
Possible
B...

result:

wrong answer Condition failed: "A == B" (test case 12)