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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#113838#5545. Contingency PlanPetroTarnavskyi#WA 1ms5716kbC++172.0kb2023-06-19 17:24:342023-06-19 17:24:37

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-06-19 17:24:37]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:5716kb
  • [2023-06-19 17:24:34]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;

#define SZ(a) (int)a.size()
#define ALL(a) a.begin(), a.end()
#define FOR(i, a, b) for (int i = (a); i<(b); ++i)
#define RFOR(i, b, a) for (int i = (b)-1; i>=(a); --i)
#define MP make_pair
#define PB push_back
#define F first
#define S second

typedef long long LL;
typedef pair<int, int> PII;
typedef vector<int> VI;

const int N = 474;
const int inf = 4747474;
string v[3];
double dp[N][N][8][8];

void setmax(double& a, double b)
{
	a = max(a, b);
}
void setmin(double& a, double b)
{
	a = min(a, b);
}

double f(int mask1, int mask2, int dis)
{
	double ans = inf;
	FOR (i, 0, 3)
	{
		if (((mask1 >> i) & 1) == 0)
			continue;
		FOR (j, 0, 3)
		{
			if (((mask2 >> j) & 1) == 0)
				continue;
			int d1 = abs(i - j);
			setmin(ans, sqrt(d1 * d1 + dis * dis));
		}
	}
	
	if ((mask1 & 3) == 3 || (mask1 & 6) == 6 || (mask2 & 3) == 3 || (mask2 & 6) == 6)
		setmin(ans, 1);
	if ((mask1 & 5) == 5 || (mask2 & 5) == 5)
		setmin(ans, 2);
	return ans;
}

bool ok(int m, int i)
{
	FOR (j, 0, 3)
	{
		if (((m >> j) & 1) && v[j][i] == '#')
			return false;
	}
	return true;
}

int main()
{
	ios::sync_with_stdio(false);
	cin.tie(0);
	
	int n, k;
	cin >> n >> k;
	FOR (i, 0, 3)
	{
		string s;
		cin >> s;
		v[i] = "#" + s;
	}
	FOR (i, 0, n + 1)
	{
		FOR(cnt, 0, k + 1)
		{
			FOR (m1, 0, 8)
			{
				FOR (m2, 0, 8)
					dp[i][cnt][m1][m2] = inf;
			}
		}
	}
	dp[0][0][0][0] = 0;
	FOR (now, 1, n + 1)
	{
		FOR (cnt, 0, k + 1)
		{
			FOR (col, 0, now)
			{
				FOR (m, 0, 8)
				{
					if (!ok(m, now))
						continue;
					FOR (mask, 0, 8)
					{
						FOR (pmask, 0, 8)
						{
							setmax(dp[now][cnt + __builtin_popcount(m)][m][col + 1 == now ? mask : 0], max({dp[col][cnt][mask][pmask], f(mask, m, now - col), f(pmask, m, now - col + 1)}));
						}
					}
				}
			}
		}
	}
	
	double ans = 0;
	FOR (i, 0, 8)
	{
		FOR (j, 0, 8)
		{
			ans = min(ans, dp[n][k][i][j]);
		}
	}
	cout << ans << '\n';
	
	return 0;
}


详细

Test #1:

score: 0
Wrong Answer
time: 1ms
memory: 5716kb

input:

7
1 2
3 7
2 4
2 5
1 3
3 6

output:

0

result:

wrong output format Unexpected end of file - int32 expected