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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#113697#6636. Longest Strictly Increasing Sequencehos_lyricAC ✓3ms3624kbC++141.8kb2023-06-19 04:36:382023-06-19 04:36:41

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-06-19 04:36:41]
  • 评测
  • 测评结果:AC
  • 用时:3ms
  • 内存:3624kb
  • [2023-06-19 04:36:38]
  • 提交

answer

#include <cassert>
#include <cmath>
#include <cstdint>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <algorithm>
#include <bitset>
#include <complex>
#include <deque>
#include <functional>
#include <iostream>
#include <map>
#include <numeric>
#include <queue>
#include <set>
#include <sstream>
#include <string>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>

using namespace std;

using Int = long long;

template <class T1, class T2> ostream &operator<<(ostream &os, const pair<T1, T2> &a) { return os << "(" << a.first << ", " << a.second << ")"; };
template <class T> ostream &operator<<(ostream &os, const vector<T> &as) { const int sz = as.size(); os << "["; for (int i = 0; i < sz; ++i) { if (i >= 256) { os << ", ..."; break; } if (i > 0) { os << ", "; } os << as[i]; } return os << "]"; }
template <class T> void pv(T a, T b) { for (T i = a; i != b; ++i) cerr << *i << " "; cerr << endl; }
template <class T> bool chmin(T &t, const T &f) { if (t > f) { t = f; return true; } return false; }
template <class T> bool chmax(T &t, const T &f) { if (t < f) { t = f; return true; } return false; }


int N;
vector<int> B;

int main() {
  for (int numCases; ~scanf("%d", &numCases); ) { for (int caseId = 1; caseId <= numCases; ++caseId) {
    scanf("%d", &N);
    B.assign(N + 1, 0);
    for (int i = 1; i <= N; ++i) {
      scanf("%d", &B[i]);
    }
    
    bool ok = true;
    for (int i = 1; i <= N; ++i) {
      ok = ok && (B[i] == B[i - 1] + 1 || B[i] == B[i - 1]);
    }
    if (ok) {
      puts("YES");
      for (int i = 1; i <= N; ++i) {
        if (i > 1) printf(" ");
        printf("%d", B[i]);
      }
      puts("");
    } else {
      puts("NO");
    }
  }
#ifndef LOCAL
  break;
#endif
  }
  return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 1ms
memory: 3624kb

input:

2
6
1 2 3 2 5 7
2
1 2

output:

NO
YES
1 2

result:

ok t=2 (2 test cases)

Test #2:

score: 0
Accepted
time: 3ms
memory: 3560kb

input:

3483
5
2 3 5 1 1
2
8 1
10
1 2 3 4 4 5 6 6 6 7
10
1 1 2 2 2 2 3 4 4 5
2
5 8
3
7 10 8
5
4 1 3 3 8
10
1 2 2 2 2 2 2 3 3 3
10
1 1 2 3 4 5 5 5 5 6
9
1 2 3 4 5 5 6 6 7
7
8 8 8 8 9 1 2
5
8 9 8 3 5
10
1 2 3 3 3 3 4 4 4 5
5
7 1 6 4 3
7
5 6 8 6 1 5 5
10
1 2 2 3 4 4 4 4 5 5
3
10 4 5
3
1 5 3
5
2 8 1 2 1
3
7 8 3...

output:

NO
NO
YES
1 2 3 4 4 5 6 6 6 7
YES
1 1 2 2 2 2 3 4 4 5
NO
NO
NO
YES
1 2 2 2 2 2 2 3 3 3
YES
1 1 2 3 4 5 5 5 5 6
YES
1 2 3 4 5 5 6 6 7
NO
NO
YES
1 2 3 3 3 3 4 4 4 5
NO
NO
YES
1 2 2 3 4 4 4 4 5 5
NO
NO
NO
NO
NO
NO
YES
1 1 1 2 2 3 3 4 4
NO
NO
NO
NO
NO
NO
NO
YES
1 2 3 3 3 4 4 4 5 5
YES
1 1 2 2 2 3 3 3 3 ...

result:

ok t=3483 (3483 test cases)