QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#111246#6561. Fail FastKhNURE_KIVIWA 3ms6032kbC++202.5kb2023-06-06 14:40:172023-06-06 14:40:20

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-06-06 14:40:20]
  • 评测
  • 测评结果:WA
  • 用时:3ms
  • 内存:6032kb
  • [2023-06-06 14:40:17]
  • 提交

answer

//#pragma GCC optimize("Ofast", "unroll-loops")
//#pragma GCC target("sse", "sse2", "sse3", "ssse3", "sse4")

#ifdef __APPLE__
#include <iostream>
#include <cmath>
#include <algorithm>
#include <stdio.h>
#include <cstdint>
#include <cstring>
#include <string>
#include <cstdlib>
#include <vector>
#include <bitset>
#include <map>
#include <queue>
#include <ctime>
#include <stack>
#include <set>
#include <list>
#include <random>
#include <deque>
#include <functional>
#include <iomanip>
#include <sstream>
#include <fstream>
#include <complex>
#include <numeric>
#include <cassert>
#include <array>
#include <tuple>
#include <unordered_map>
#include <unordered_set>
#include <thread>
#else
#include <bits/stdc++.h>
#endif

#define all(a) a.begin(),a.end()
#define len(a) (int)(a.size())
#define mp make_pair
#define pb push_back
#define fir first
#define sec second
#define fi first
#define se second

using namespace std;

typedef pair<int, int> pii;
typedef long long ll;
typedef long double ld;

template<typename T>
bool umin(T &a, T b) {
    if (b < a) {
        a = b;
        return true;
    }
    return false;
}
template<typename T>
bool umax(T &a, T b) {
    if (a < b) {
        a = b;
        return true;
    }
    return false;
}

#if __APPLE__
#define D for (bool _FLAG = true; _FLAG; _FLAG = false)
#define LOG(...) print(#__VA_ARGS__" ::", __VA_ARGS__) << endl
template <class ...Ts> auto &print(Ts ...ts) { return ((cerr << ts << " "), ...); }
#else
#define D while (false)
#define LOG(...)
#endif

const int max_n = 1e5+10, inf = 1000111222;

struct e
{
    __float128 p;
    int c;
    int id;
};

const bool operator<(const e& lhs,const e& rhs)
{
    return (lhs.c + lhs.p * rhs.c < rhs.c + rhs.p * lhs.c);
}

vector<e> reb[max_n];

int main() {
//    freopen("input.txt", "r", stdin);
//    freopen("output.txt", "w", stdout);

    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);

    int n;
    cin>>n;
    set<e> setik;
    for (int i=1;i<=n;i++){
        int c;
        ld p;
        int d;

        cin>>c>>p>>d;
        if (d==0){
            setik.insert(e{p,c,i});
        }
        else{
            reb[d].pb(e{p,c,i});
        }
    }
    while (!setik.empty()){
        e now=*setik.begin();
        setik.erase(setik.begin());
        cout<<now.id<<"\n";
        for (auto wh:reb[now.id]){
            setik.insert(e{wh.p * now.p, wh.c + now.c, wh.id});
        }
    }
}

詳細信息

Test #1:

score: 100
Accepted
time: 1ms
memory: 5952kb

input:

4
100 0.5 0
200 0.1 1
10 0.5 2
10 0.9 0

output:

4
1
2
3

result:

ok correct

Test #2:

score: -100
Wrong Answer
time: 3ms
memory: 6032kb

input:

4
84 0.716 0
91 0.115 0
19 0.640 1
103 0.455 0

output:

2
4
1
3

result:

wrong answer your plan is not optimal