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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#109028#5418. Color the TreeshihoghmeanWA 31ms3632kbC++173.8kb2023-05-27 09:56:572023-05-27 09:56:58

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-05-27 09:56:58]
  • 评测
  • 测评结果:WA
  • 用时:31ms
  • 内存:3632kb
  • [2023-05-27 09:56:57]
  • 提交

answer


#include<bits/stdc++.h>
using namespace std;
//#define int long long
#define ll long long
#define fo(i,a,b) for(int i=a;i<=b;i++)
#define fr(i,a,b) for(int i=a;i>=b;i--)
#define py puts("Yes")
#define pn puts("No")
#define pt puts("")
#define pb push_back
#define wt(x) write(x),puts("")
#define wr(x) write(x) ,putchar(' ')
#define tx printf("fds")
#define mp make_pair
#define fi first
#define se second
inline int read(){
	int x=0,k=1;
	char ch=getchar();
	while(ch<'0'||ch>'9'){
		if(ch=='-') k=-1;
		ch=getchar();
	}
	while(ch>='0'&&ch<='9'){
		x=(x<<1)+(x<<3)+ch-48;
		ch=getchar();
	}
	return x*k;
}
void write(int x){
	if(x<0){
		x=-x;
		putchar('-');
	}
	if(x>9) write(x/10);
	putchar(x%10+'0');
}
int power(int x,int y,int mod){
	int num=1;
	while(y){
		if(y&1) num=(num*x)%mod;
		x=x*x%mod;
		y>>=1;
	}
	return num;
}
int mul(int x,int y,int mod){
	int num=0;
	while(y){
		if(y&1) num=(num+x)%mod;
		x=(x+x)%mod;
		y>>=1;
	}
	return num;
}
const int N=1e6+7,mod=998244353;
int n,m,tot,cnt,ans,k;
int a[N],b[N];
int head[N];
struct edge{
    int to,next;
}e[N];
void add(int u,int v){
    e[++tot]={v,head[u]};
    head[u]=tot;
}
struct tree{
    int ls,rs;
    int num;
}t[N];
int siz[N],dep[N],son[N],mdep[N],top[N];
int rt[N];
int rmq[N][20];
int newnode(int x){
    t[x]={0,0,0};
    return x;
}
void pu(int id){
    int x=0,y=0;
    if(t[id].ls) x=t[t[id].ls].num;
    if(t[id].rs) y=t[t[id].rs].num;
    t[id].num=x+y;
}
void update(int id,int l,int r,int x,int k){
    if(l==r){
        t[id].num=k;
        return ;
    }
    int mid=(l+r)>>1;
    if(x<=mid){
        if(!t[id].ls) t[id].ls=newnode(++cnt);
        update(t[id].ls,l,mid,x,k);
    }
    else{
        if(!t[id].rs) t[id].rs=newnode(++cnt);
        update(t[id].rs,mid+1,r,x,k);
    }
    pu(id);
}
int RMQ(int l,int r){
    int x=log2(r-l+1);
    return min(rmq[l][x],rmq[r-(1<<x)+1][x]);
}
int merge(int ddp,int dp,int x,int y,int l,int r){
    if(!x||!y) return x+y;
    if(l==r){
        t[x].num=min(t[x].num+t[y].num,RMQ(l-dp+1,l-ddp+1));
        return x;
    }
    int mid=(l+r)>>1;
    t[x].ls=merge(ddp,dp,t[x].ls,t[y].ls,l,mid);
    t[x].rs=merge(ddp,dp,t[x].rs,t[y].rs,mid+1,r);
    pu(x);
    return x;
}
void dfs(int u,int fa){
    dep[u]=mdep[u]=dep[fa]+1;
    siz[u]=1;
    for(int i=head[u];i;i=e[i].next){
        int v=e[i].to;
        if(v==fa) continue;
        dfs(v,u);
        siz[u]+=siz[v];
        mdep[u]=max(mdep[u],mdep[v]);
        if(mdep[v]>mdep[son[u]]){
            son[u]=v;
        }
    }
}
void dfs1(int u,int fa,int tp){
    top[u]=tp;
    if(u==tp) rt[u]=newnode(++cnt);
    update(rt[top[u]],1,n,dep[u],b[dep[u]-dep[top[u]]]);
    if(son[u]) dfs1(son[u],u,tp);
    for(int i=head[u];i;i=e[i].next){
        int v=e[i].to;
        if(v==fa||v==son[u]) continue;
        dfs1(v,u,v);
    }
}
void dfs2(int u,int fa){
    for(int i=head[u];i;i=e[i].next){
        int v=e[i].to;
        if(v==fa) continue;
        dfs2(v,u);
        if(son[u]!=v) rt[top[u]]=merge(dep[top[u]],dep[u],rt[top[u]],rt[top[v]],1,n);
    }
}
signed main(){
	int tt=read();
	while(tt--){
		tot=0;
        n=read();
        fo(i,1,n) head[i]=0,rt[i]=0,son[i]=0,siz[i]=0,dep[i]=0,mdep[i]=0,top[i]=0;
        fo(i,0,n-1) a[i]=read(),b[i]=a[i];
        fo(i,1,n-1)b[i]=min(b[i],b[i-1]);
        fo(i,1,n){
            rmq[i][0]=a[i-1];
        }
        fo(i,1,19){
            fo(j,1,n){
                rmq[j][i]=min(rmq[j][i-1],rmq[j+(1<<(i-1))][i-1]);
            }
        }
        fo(i,2,n){
            int x=read(),y=read();
            add(x,y);
            add(y,x);
        }
        cnt=0;
        dfs(1,0);
        dfs1(1,0,1);
        dfs2(1,0);
        wt(t[rt[1]].num);
	}
	return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 0ms
memory: 3404kb

input:

3
4
10 15 40 1
1 2
2 3
2 4
5
10 5 1 100 1000
1 2
2 3
2 4
4 5
4
1000 200 10 8
1 2
2 3
3 4

output:

35
17
1218

result:

ok 3 number(s): "35 17 1218"

Test #2:

score: -100
Wrong Answer
time: 31ms
memory: 3632kb

input:

3000
54
43 44 11 49 17 14 7 30 35 12 34 14 15 8 29 47 30 31 39 17 26 23 26 45 34 50 49 13 35 18 29 15 13 44 47 5 22 20 19 46 30 22 26 13 47 46 43 27 48 48 13 14 30 44
1 2
1 3
2 4
3 5
4 6
2 7
4 8
1 9
3 10
1 11
8 12
2 13
9 14
1 15
1 16
15 17
15 18
7 19
1 20
19 21
13 22
10 23
17 24
9 25
9 26
24 27
8 28...

output:

138
120
189
190
148
227
221
104
100
81
155
73
143
127
143
86
153
230
105
174
138
168
78
188
195
267
187
211
119
118
211
233
88
246
239
173
173
180
166
113
109
114
180
123
226
191
182
91
195
59
56
31
115
150
186
115
103
208
53
119
181
170
169
134
233
72
163
273
80
350
142
133
122
147
240
269
113
210
...

result:

wrong answer 1st numbers differ - expected: '180', found: '138'