#pragma GCC optimize("Ofast")
#include<bits/stdc++.h>
#define ll long long
#define mk(x,y) make_pair(x,y)
#define pb(x) push_back(x)
#define cs const
using namespace std;
cs int g=3;
const int N=6e5+10;
const int mod=998244353;
const int lim=1e7;
typedef vector<int> poly;
int rev[N],inv[N],w[N],prime[N],p[N];
unordered_map<int,int>mp;
char s[N];
int n,m,len,d,x,k;
int a[N];
int mul(int x,int y){return (ll)x*y%mod;}
int add(int x,int y){return x+y>=mod?x+y-mod:x+y;}
int dec(int x,int y){return x-y>=0?x-y:x-y+mod;}
int ksm(int x,int y){
	ll ans=1;
	for (;y;y>>=1,x=mul(x,x)) if (y&1) ans=mul(ans,x);
	return ans;
}
int read(){
	int f=1,x=0; char c=getchar();
	while (c<'0'||c>'9'){if (c=='-')f=-1;c=getchar();}
	while (c>='0'&&c<='9'){x=add(mul(x,10),c-'0');c=getchar();}
	return x; 
}
void init(int x){
	len=1,d=0;
	while (len<x) {len<<=1;d++;}
	for (int i=0;i<len;i++) rev[i]=(rev[i>>1]>>1)|((i&1)<<(d-1));
}
inline poly NTT(poly a,int t) {
	for (int i=0;i<a.size();i++) if (i<rev[i]) swap(a[i],a[rev[i]]);
	for (int i=1;i<a.size();i<<=1) {
		int s=(i<<1);
		int wn=ksm(g,(mod-1)/s);
		if (t==-1) wn=ksm(wn,mod-2);
		for (int j=0;j<a.size();j+=s) {
			int w=1;
			for (int k=j;k<j+i;k++) {
				int x=a[k],y=mul(a[k+i],w);
				a[k]=add(x,y); a[k+i]=dec(x,y);
				w=mul(w,wn);
			}
		}
	}
	if (t==-1){
		ll w=ksm(a.size(),mod-2);
		for (int i=0;i<a.size();i++) a[i]=mul(a[i],w);
	}
	return a;
}
inline poly operator *(poly a,poly b){
	int n=a.size(),m=b.size(); 
	init(n+m-1);
	a.resize(len);
	b.resize(len);
	a=NTT(a,1); b=NTT(b,1);
	for (int i=0;i<a.size();i++) a[i]=mul(a[i],b[i]);
	a=NTT(a,-1);
	a.resize(n+m-1);
	return a;
}
int main(){
	scanf("%d",&n);
	for (int i=1;i<=n;i++) scanf("%d",&a[i]);
	scanf("%s",s+1);
	poly b,c;
	for (int i=1;i<n;i++) if (s[i]=='-') b.pb(1); else b.pb(0);
	int x=1;
	for (int i=0;i<mod;i++){
		if (x<=n) w[x]=i;
		x=3ll*x%mod;
	}
	c.pb(dec(mod/2,w[1]));
	for (int i=2;i<=n;i++) c.pb(dec(w[i-2],w[i])); 
	b=b*c;
	int ans=a[1];
	bool p=0;
	for (int i=2;i<=n;i++) if (s[i-2]!='-') {
		ans=add(ans,mul(a[i],ksm(g,b[i-2])));
	}
	for (int i=1;i<n;i++) ans=mul(ans,i);
	printf("%d\n",ans);
}