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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#105947#5422. Perfect PalindromeRabbieWjy#AC ✓10ms3744kbC++14420b2023-05-16 08:13:032023-05-16 08:13:04

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-05-16 08:13:04]
  • 评测
  • 测评结果:AC
  • 用时:10ms
  • 内存:3744kb
  • [2023-05-16 08:13:03]
  • 提交

answer

#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;

int t,n;
char s[1000010];
int cnt[30];

int main()
{
	scanf("%d",&t);
	while (t --)
	{
		scanf("%s",s + 1);
		n = strlen(s + 1);
		for (int i = 0;i < 26;i ++) cnt[i] = 0;
		for (int i = 1;i <= n;i ++) cnt[s[i] - 'a'] ++;
		int ans = 0;
		for (int i = 0;i < 26;i ++) ans = max(ans,cnt[i]);
		printf("%d\n",n - ans);
	}
}

Details

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Test #1:

score: 100
Accepted
time: 2ms
memory: 3744kb

input:

2
abcb
xxx

output:

2
0

result:

ok 2 number(s): "2 0"

Test #2:

score: 0
Accepted
time: 10ms
memory: 3660kb

input:

11107
lfpbavjsm
pdtlkfwn
fmb
hptdswsoul
bhyjhp
pscfliuqn
nej
nxolzbd
z
clzb
zqomviosz
u
ek
vco
oymonrq
rjd
ktsqti
mdcvserv
x
birnpfu
gsgk
ftchwlm
bzqgar
ovj
nsgiegk
dbolme
nvr
rpsc
fprodu
eqtidwto
j
qty
o
jknssmabwl
qjfv
wrd
aa
ejsf
i
npmmhkef
dzvyon
p
zww
dp
ru
qmwm
sc
wnnjyoepxo
hc
opvfepiko
inuxx...

output:

8
7
2
8
4
8
2
6
0
3
7
0
1
2
5
2
4
6
0
6
2
6
5
2
5
5
2
3
5
6
0
2
0
8
3
2
0
3
0
6
5
0
1
1
1
2
1
8
1
7
5
3
4
4
1
8
5
5
8
8
6
3
0
2
3
2
1
5
0
0
9
3
3
4
8
4
0
4
2
6
6
0
8
7
4
3
9
3
4
2
5
8
8
8
6
1
4
4
2
7
2
8
6
4
4
8
7
8
4
9
3
8
0
7
7
2
6
0
0
5
4
0
7
5
4
2
1
6
7
5
2
4
4
7
3
3
2
5
4
8
5
0
3
5
1
2
3
0
4
7
...

result:

ok 11107 numbers