QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#104963#4793. QnpDeterminantRE 11ms5888kbC++14867b2023-05-12 17:22:102023-05-12 17:22:14

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-05-12 17:22:14]
  • 评测
  • 测评结果:RE
  • 用时:11ms
  • 内存:5888kb
  • [2023-05-12 17:22:10]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;typedef long long ll;
const int N=70007;const ll p=1145141919810011ll,p2=1e9+7;
int a[10],st;ll ans,m,inv[N],f[N],f_[N];double s[N];
void sol(){
	ans=st=0;for(int i=0;i<10;++i)scanf("%d",&a[i]),st+=a[i];scanf("%lld",&m);
	while(st){
		int fl=0;
		for(int i=0;i<10;++i)if(a[i]){
			double q=s[st-1];
			for(int j=0;j<10;++j)q-=s[a[j]-(i==j)];
			if(q>=14){fl=i;break;}
			ll q2=f[st-1];
			for(int j=0;j<10;++j)q2=(__int128)q2*f_[a[j]-(i==j)]%p;
			if(m<=q2){fl=i;break;}else m-=q2;
		}
		ans=(ans*10+fl)%p2;st--;a[fl]--;
	}
	printf("%lld\n",ans);
}
int main(){
	inv[1]=1;for(int i=2;i<N;++i)inv[i]=(__int128)(p-p/i)*inv[p%i]%p;
	f[0]=f_[0]=1;for(int i=1;i<N;++i){
		f[i]=(__int128)f[i-1]*i%p,f_[i]=(__int128)f[i-1]*inv[i]%p;
		s[i]=s[i-1]+log10(i);
	}
	int t;scanf("%d",&t);t=6;while(t--)sol();
}

详细

Test #1:

score: 100
Accepted
time: 11ms
memory: 5888kb

input:

6
1 1 0 0 0 0 0 0 0 0 1
1 1 0 0 0 0 0 0 0 0 2
1 1 1 0 0 0 0 0 0 0 1
1 1 1 0 0 0 0 0 0 0 2
1 1 1 0 0 0 0 0 0 0 5
1 2 0 0 0 0 0 0 0 0 2

output:

1
10
12
21
201
101

result:

ok 6 numbers

Test #2:

score: -100
Runtime Error

input:

5000
7142 6835 7022 6981 6929 7008 7038 7015 6885 7145 659213485437
7015 7033 6963 7136 7053 7072 6847 6923 6953 7005 82053183749
7013 7003 6969 7000 7011 7137 7030 6823 7021 6993 817812793310
6893 7008 6963 7086 7012 6922 7128 7094 7028 6866 143084249211
7020 7021 6997 6961 7017 7032 7013 7028 6987...

output:


result: