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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#103613#6300. Best Carry Player 2MIT01#TL 4ms3660kbC++172.2kb2023-05-07 04:18:182023-05-07 04:18:22

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-05-07 04:18:22]
  • 评测
  • 测评结果:TL
  • 用时:4ms
  • 内存:3660kb
  • [2023-05-07 04:18:18]
  • 提交

answer

// #pragma GCC optimize("-Ofast","-ffast-math","-funroll-all-loops")
#include <bits/stdc++.h>
using namespace std;
#define ll __int128
#define db double
#define mp make_pair
#define pb push_back
#define fi first
#define se second
#define mod 998244353
#define vi vector<int>
const int maxn = 2000005;
const int S = 37;
template<typename T> bool chkmin(T &a, T b) {
    return (b < a) ? (a = b, 1) : 0;
}

template<typename T> bool chkmax(T &a, T b) {
    return (b > a) ? (a = b, 1) : 0;
}
ll dp[S + 2][3][S]; // next undet: i; j many < 
int dig[S];
int main() {
    ios::sync_with_stdio(0);
    cin.tie(0);
    int t;
    cin >> t;
    while (t--) {
        ll x;
        int k;
        long long inp;
        cin >> inp >> k;
        x = inp;
        for (int j = 0; j < S; j++) {
            dig[j] = x % 10;
            x /= 10;
        }
        ll inf = 3e18;
        inf = inf * inf;
        for (int i = 0; i < S + 2; i++)
            for (int j = 0; j < 3; j++)
                for (int k = 0; k < S; k++)
                    dp[i][j][k] = inf;
        dp[0][1][0] = 0;
        ll pw = 1;
        for (int i = 0; i < S; i++) {
            for (int u = 0; u < 3; u++)
                for (int v = 0; v <= 18; v++) {
                    if (dp[i][u][v] > inf) continue;
                    for (int w = 0; w < 10; w++) {
                        // if (i == S - 1 && w >= 4) continue;
                        ll cc = dp[i][u][v] + w * pw;
                        int eu = 0, ev = v;
                        if (w > dig[i]) eu = 2;
                        else if (w == dig[i]) eu = u;
                        else eu = 0;
                        if (!eu) ev += 1;
                        chkmin(dp[i + 1][eu][ev], cc);
                    }
                }
            pw = pw * 10;
        }
        ll ans = dp[S][2][k] - inp;
        vi otp;
        while (ans) {
            otp.pb(ans % 10);
            ans /= 10;
        }
        reverse(otp.begin(), otp.end());
        for (auto v : otp) printf("%d", v);
        printf("\n");
        // cout << ans << '\n';
        // cout << dp[S][2][k] - stx << '\n';
    }
    return 0;
}
/*
4
12345678 0
12345678 5
12345678 18
990099 5
*/

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 3652kb

input:

4
12345678 0
12345678 5
12345678 18
990099 5

output:

1
54322
999999999987654322
9910

result:

ok 4 lines

Test #2:

score: 0
Accepted
time: 4ms
memory: 3660kb

input:

21
999990000099999 0
999990000099999 1
999990000099999 2
999990000099999 3
999990000099999 4
999990000099999 5
999990000099999 6
999990000099999 7
999990000099999 8
999990000099999 9
999990000099999 10
999990000099999 11
999990000099999 12
999990000099999 13
999990000099999 14
999990000099999 15
999...

output:

100000
10000
1000
100
10
1
900001
9900001
99900001
999900001
10000000001
9999910000
9999901000
9999900100
9999900010
9999900001
9000009999900001
99000009999900001
999000009999900001
99999999999999999900000000000000000
1000000000000000000

result:

ok 21 lines

Test #3:

score: -100
Time Limit Exceeded

input:

100000
119111011091190000 10
1911011191011999 16
110099199000119 0
19009911191091011 13
199090909919000900 17
19009010011919110 5
90910190019900091 18
10911100000101111 1
110090011101119990 4
100909999119090000 12
90901119109011100 2
111010119991090101 4
900991019109199009 5
100919919990991119 8
911...

output:

88988908810000
8088988808988001
10
88808908989
9800909090080999100
80890
909089809980099909
9
80010
9090000880910000
8900
9909
991
9008900
8880880090
8080090801
8009900808909899
80880898981
909
8800909
99988889901
89908888089
980908890980099000
100
9889801
81
908890008099900891
880990801
9998099
890...

result: